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Theorem fldextsubrg 33660
Description: Field extension implies a subring relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
Hypothesis
Ref Expression
fldextsubrg.1 𝑈 = (Base‘𝐹)
Assertion
Ref Expression
fldextsubrg (𝐸/FldExt𝐹𝑈 ∈ (SubRing‘𝐸))

Proof of Theorem fldextsubrg
StepHypRef Expression
1 fldextsubrg.1 . 2 𝑈 = (Base‘𝐹)
2 fldextfld1 33658 . . . . 5 (𝐸/FldExt𝐹𝐸 ∈ Field)
3 fldextfld2 33659 . . . . 5 (𝐸/FldExt𝐹𝐹 ∈ Field)
4 brfldext 33656 . . . . 5 ((𝐸 ∈ Field ∧ 𝐹 ∈ Field) → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸))))
52, 3, 4syl2anc 584 . . . 4 (𝐸/FldExt𝐹 → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸))))
65ibi 267 . . 3 (𝐸/FldExt𝐹 → (𝐹 = (𝐸s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸)))
76simprd 495 . 2 (𝐸/FldExt𝐹 → (Base‘𝐹) ∈ (SubRing‘𝐸))
81, 7eqeltrid 2835 1 (𝐸/FldExt𝐹𝑈 ∈ (SubRing‘𝐸))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395   = wceq 1541  wcel 2111   class class class wbr 5091  cfv 6481  (class class class)co 7346  Basecbs 17120  s cress 17141  SubRingcsubrg 20485  Fieldcfield 20646  /FldExtcfldext 33649
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2113  ax-9 2121  ax-ext 2703  ax-sep 5234  ax-nul 5244  ax-pr 5370
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2710  df-cleq 2723  df-clel 2806  df-ral 3048  df-rex 3057  df-rab 3396  df-v 3438  df-dif 3905  df-un 3907  df-ss 3919  df-nul 4284  df-if 4476  df-sn 4577  df-pr 4579  df-op 4583  df-uni 4860  df-br 5092  df-opab 5154  df-xp 5622  df-iota 6437  df-fv 6489  df-ov 7349  df-fldext 33652
This theorem is referenced by:  fldextsdrg  33665  fldextsralvec  33666  extdgcl  33667  extdggt0  33668  extdgmul  33674  extdg1id  33677  fldextchr  33680
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