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Theorem fldextsubrg 33685
Description: Field extension implies a subring relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
Hypothesis
Ref Expression
fldextsubrg.1 𝑈 = (Base‘𝐹)
Assertion
Ref Expression
fldextsubrg (𝐸/FldExt𝐹𝑈 ∈ (SubRing‘𝐸))

Proof of Theorem fldextsubrg
StepHypRef Expression
1 fldextsubrg.1 . 2 𝑈 = (Base‘𝐹)
2 fldextfld1 33683 . . . . 5 (𝐸/FldExt𝐹𝐸 ∈ Field)
3 fldextfld2 33684 . . . . 5 (𝐸/FldExt𝐹𝐹 ∈ Field)
4 brfldext 33681 . . . . 5 ((𝐸 ∈ Field ∧ 𝐹 ∈ Field) → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸))))
52, 3, 4syl2anc 584 . . . 4 (𝐸/FldExt𝐹 → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸))))
65ibi 267 . . 3 (𝐸/FldExt𝐹 → (𝐹 = (𝐸s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸)))
76simprd 495 . 2 (𝐸/FldExt𝐹 → (Base‘𝐹) ∈ (SubRing‘𝐸))
81, 7eqeltrid 2837 1 (𝐸/FldExt𝐹𝑈 ∈ (SubRing‘𝐸))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395   = wceq 1541  wcel 2113   class class class wbr 5095  cfv 6488  (class class class)co 7354  Basecbs 17124  s cress 17145  SubRingcsubrg 20488  Fieldcfield 20649  /FldExtcfldext 33674
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2705  ax-sep 5238  ax-nul 5248  ax-pr 5374
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2712  df-cleq 2725  df-clel 2808  df-ral 3049  df-rex 3058  df-rab 3397  df-v 3439  df-dif 3901  df-un 3903  df-ss 3915  df-nul 4283  df-if 4477  df-sn 4578  df-pr 4580  df-op 4584  df-uni 4861  df-br 5096  df-opab 5158  df-xp 5627  df-iota 6444  df-fv 6496  df-ov 7357  df-fldext 33677
This theorem is referenced by:  fldextsdrg  33690  fldextsralvec  33691  extdgcl  33692  extdggt0  33693  extdgmul  33699  extdg1id  33702  fldextchr  33705
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