Theorem fneq12d 6631

Description: Equality deduction for function predicate with domain. (Contributed by NM, 26-Jun-2011.)

Hypotheses

Ref	Expression
fneq12d.1	⊢ (𝜑 → 𝐹 = 𝐺)
fneq12d.2	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
fneq12d	⊢ (𝜑 → (𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐵))

Proof of Theorem fneq12d

Step	Hyp	Ref	Expression
1		fneq12d.1	. . 3 ⊢ (𝜑 → 𝐹 = 𝐺)
2	1	fneq1d 6629	. 2 ⊢ (𝜑 → (𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐴))
3		fneq12d.2	. . 3 ⊢ (𝜑 → 𝐴 = 𝐵)
4	3	fneq2d 6630	. 2 ⊢ (𝜑 → (𝐺 Fn 𝐴 ↔ 𝐺 Fn 𝐵))
5	2, 4	bitrd 282	1 ⊢ (𝜑 → (𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐵))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   = wceq 1570   Fn wfn 6532

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-rab 3415  df-v 3455  df-dif 3905  df-un 3907  df-ss 3919  df-nul 4283  df-if 4486  df-sn 4588  df-pr 4590  df-op 4594  df-br 5108  df-opab 5172  df-rel 5666  df-cnv 5667  df-co 5668  df-dm 5669  df-fun 6539  df-fn 6540

This theorem is used by:  fneq12  6632  seqfn  14081  sscres  17918  reschomf  17926  funcres  17991  psrvscafval  22169  ressprdsds  24603  rrxmfval  25640  ex-fpar  30950  sseqfn  34909  tfsconcatfn  44187  funcoressn  47938