Proof of Theorem add4
| Step | Hyp | Ref
 | Expression | 
| 1 |   | add12 8184 | 
. . . . 5
⊢ ((𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ) → (𝐵 + (𝐶 + 𝐷)) = (𝐶 + (𝐵 + 𝐷))) | 
| 2 | 1 | 3expb 1206 | 
. . . 4
⊢ ((𝐵 ∈ ℂ ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → (𝐵 + (𝐶 + 𝐷)) = (𝐶 + (𝐵 + 𝐷))) | 
| 3 | 2 | oveq2d 5938 | 
. . 3
⊢ ((𝐵 ∈ ℂ ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → (𝐴 + (𝐵 + (𝐶 + 𝐷))) = (𝐴 + (𝐶 + (𝐵 + 𝐷)))) | 
| 4 | 3 | adantll 476 | 
. 2
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → (𝐴 + (𝐵 + (𝐶 + 𝐷))) = (𝐴 + (𝐶 + (𝐵 + 𝐷)))) | 
| 5 |   | addcl 8004 | 
. . 3
⊢ ((𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ) → (𝐶 + 𝐷) ∈ ℂ) | 
| 6 |   | addass 8009 | 
. . . 4
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ (𝐶 + 𝐷) ∈ ℂ) → ((𝐴 + 𝐵) + (𝐶 + 𝐷)) = (𝐴 + (𝐵 + (𝐶 + 𝐷)))) | 
| 7 | 6 | 3expa 1205 | 
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 + 𝐷) ∈ ℂ) → ((𝐴 + 𝐵) + (𝐶 + 𝐷)) = (𝐴 + (𝐵 + (𝐶 + 𝐷)))) | 
| 8 | 5, 7 | sylan2 286 | 
. 2
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐵) + (𝐶 + 𝐷)) = (𝐴 + (𝐵 + (𝐶 + 𝐷)))) | 
| 9 |   | addcl 8004 | 
. . . 4
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ) → (𝐵 + 𝐷) ∈ ℂ) | 
| 10 |   | addass 8009 | 
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ (𝐵 + 𝐷) ∈ ℂ) → ((𝐴 + 𝐶) + (𝐵 + 𝐷)) = (𝐴 + (𝐶 + (𝐵 + 𝐷)))) | 
| 11 | 10 | 3expa 1205 | 
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ) ∧ (𝐵 + 𝐷) ∈ ℂ) → ((𝐴 + 𝐶) + (𝐵 + 𝐷)) = (𝐴 + (𝐶 + (𝐵 + 𝐷)))) | 
| 12 | 9, 11 | sylan2 286 | 
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐶) + (𝐵 + 𝐷)) = (𝐴 + (𝐶 + (𝐵 + 𝐷)))) | 
| 13 | 12 | an4s 588 | 
. 2
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐶) + (𝐵 + 𝐷)) = (𝐴 + (𝐶 + (𝐵 + 𝐷)))) | 
| 14 | 4, 8, 13 | 3eqtr4d 2239 | 
1
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐵) + (𝐶 + 𝐷)) = ((𝐴 + 𝐶) + (𝐵 + 𝐷))) |