Theorem rneq 4889

Description: Equality theorem for range. (Contributed by NM, 29-Dec-1996.)

Assertion

Ref	Expression
rneq	⊢ (𝐴 = 𝐵 → ran 𝐴 = ran 𝐵)

Proof of Theorem rneq

Step	Hyp	Ref	Expression
1		cnveq 4836	. . 3 ⊢ (𝐴 = 𝐵 → ◡𝐴 = ◡𝐵)
2	1	dmeqd 4864	. 2 ⊢ (𝐴 = 𝐵 → dom ◡𝐴 = dom ◡𝐵)
3		df-rn 4670	. 2 ⊢ ran 𝐴 = dom ◡𝐴
4		df-rn 4670	. 2 ⊢ ran 𝐵 = dom ◡𝐵
5	2, 3, 4	3eqtr4g 2251	1 ⊢ (𝐴 = 𝐵 → ran 𝐴 = ran 𝐵)

Syntax hints:   → wi 4   = wceq 1364  ^◡ccnv 4658  dom cdm 4659  ran crn 4660

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 710  ax-5 1458  ax-7 1459  ax-gen 1460  ax-ie1 1504  ax-ie2 1505  ax-8 1515  ax-10 1516  ax-11 1517  ax-i12 1518  ax-bndl 1520  ax-4 1521  ax-17 1537  ax-i9 1541  ax-ial 1545  ax-i5r 1546  ax-ext 2175

This theorem depends on definitions:  df-bi 117  df-3an 982  df-tru 1367  df-nf 1472  df-sb 1774  df-clab 2180  df-cleq 2186  df-clel 2189  df-nfc 2325  df-v 2762  df-un 3157  df-in 3159  df-ss 3166  df-sn 3624  df-pr 3625  df-op 3627  df-br 4030  df-opab 4091  df-cnv 4667  df-dm 4669  df-rn 4670

This theorem is referenced by:  rneqi  4890  rneqd  4891  xpima1  5112  feq1  5386  foeq1  5472  ixpsnf1o  6790  imasex  12888