Theorem rneq 4989

Description: Equality theorem for range. (Contributed by NM, 29-Dec-1996.)

Assertion

Ref	Expression
rneq	⊢ (𝐴 = 𝐵 → ran 𝐴 = ran 𝐵)

Proof of Theorem rneq

Step	Hyp	Ref	Expression
1		cnveq 4934	. . 3 ⊢ (𝐴 = 𝐵 → ◡𝐴 = ◡𝐵)
2	1	dmeqd 4963	. 2 ⊢ (𝐴 = 𝐵 → dom ◡𝐴 = dom ◡𝐵)
3		df-rn 4765	. 2 ⊢ ran 𝐴 = dom ◡𝐴
4		df-rn 4765	. 2 ⊢ ran 𝐵 = dom ◡𝐵
5	2, 3, 4	3eqtr4g 2292	1 ⊢ (𝐴 = 𝐵 → ran 𝐴 = ran 𝐵)

Syntax hints:   → wi 4   = wceq 1398  ^◡ccnv 4753  dom cdm 4754  ran crn 4755

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2216

This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2221  df-cleq 2227  df-clel 2230  df-nfc 2375  df-v 2817  df-un 3218  df-in 3220  df-ss 3227  df-sn 3700  df-pr 3701  df-op 3703  df-br 4115  df-opab 4177  df-cnv 4762  df-dm 4764  df-rn 4765

This theorem is referenced by:  rneqi  4990  rneqd  4991  xpima1  5214  feq1  5496  foeq1  5591  ixpsnf1o  6984  imasex  13602  ausgrusgrien  16278  0uhgrsubgr  16372