Theorem sseq1i 3250

Description: An equality inference for the subclass relationship. (Contributed by NM, 18-Aug-1993.)

Hypothesis

Ref	Expression
sseq1i.1	⊢ 𝐴 = 𝐵

Assertion

Ref	Expression
sseq1i	⊢ (𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶)

Proof of Theorem sseq1i

Step	Hyp	Ref	Expression
1		sseq1i.1	. 2 ⊢ 𝐴 = 𝐵
2		sseq1 3247	. 2 ⊢ (𝐴 = 𝐵 → (𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶))
3	1, 2	ax-mp 5	1 ⊢ (𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶)

Syntax hints:   ↔ wb 105   = wceq 1395   ⊆ wss 3197

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-11 1552  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-ext 2211

This theorem depends on definitions:  df-bi 117  df-nf 1507  df-sb 1809  df-clab 2216  df-cleq 2222  df-clel 2225  df-in 3203  df-ss 3210

This theorem is referenced by:  eqsstri  3256  eqsstrid  3270  ssab  3294  rabss  3301  uniiunlem  3313  prss  3824  prssg  3825  tpss  3836  iunss  4006  pwtr  4306  ordsucss  4597  elomssom  4698  cores2  5244  dffun2  5331  funimaexglem  5407  idref  5889  ordgt0ge1  6594  3nsssucpw1  7437  prarloclemn  7702  ausgrusgrben  15987  bdeqsuc  16353  bj-omssind  16407