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Theorem clatglbcl2 18538
Description: Any subset of the base set has a GLB in a complete lattice. (Contributed by NM, 13-Sep-2018.)
Hypotheses
Ref Expression
clatglbcl.b 𝐵 = (Base‘𝐾)
clatglbcl.g 𝐺 = (glb‘𝐾)
Assertion
Ref Expression
clatglbcl2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝐺)

Proof of Theorem clatglbcl2
StepHypRef Expression
1 clatglbcl.b . . . . 5 𝐵 = (Base‘𝐾)
21fvexi 6881 . . . 4 𝐵 ∈ V
32elpw2 5290 . . 3 (𝑆 ∈ 𝒫 𝐵𝑆𝐵)
43bilanri 510 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ 𝒫 𝐵)
5 eqid 2762 . . . . 5 (lub‘𝐾) = (lub‘𝐾)
6 clatglbcl.g . . . . 5 𝐺 = (glb‘𝐾)
71, 5, 6isclat 18532 . . . 4 (𝐾 ∈ CLat ↔ (𝐾 ∈ Poset ∧ (dom (lub‘𝐾) = 𝒫 𝐵 ∧ dom 𝐺 = 𝒫 𝐵)))
8 simprr 782 . . . 4 ((𝐾 ∈ Poset ∧ (dom (lub‘𝐾) = 𝒫 𝐵 ∧ dom 𝐺 = 𝒫 𝐵)) → dom 𝐺 = 𝒫 𝐵)
97, 8sylbi 219 . . 3 (𝐾 ∈ CLat → dom 𝐺 = 𝒫 𝐵)
109adantr 484 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → dom 𝐺 = 𝒫 𝐵)
114, 10eleqtrrd 2865 1 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝐺)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 399   = wceq 1560  wcel 2142  wss 3904  𝒫 cpw 4555  dom cdm 5647  cfv 6521  Basecbs 17245  Posetcpo 18339  lubclub 18341  glbcglb 18342  CLatccla 18530
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1815  ax-4 1829  ax-5 1930  ax-6 1987  ax-7 2028  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5246  ax-nul 5256
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1100  df-tru 1563  df-fal 1573  df-ex 1800  df-sb 2091  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-rab 3415  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4481  df-pw 4557  df-sn 4583  df-pr 4585  df-op 4589  df-uni 4866  df-br 5101  df-dm 5657  df-iota 6477  df-fv 6529  df-clat 18531
This theorem is referenced by:  isglbd  18541  clatglb  18548  clatglble  18549  glbconN  40001
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