Theorem ineqan12d 4181

Description: Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007.)

Hypotheses

Ref	Expression
ineq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)
ineqan12d.2	⊢ (𝜓 → 𝐶 = 𝐷)

Assertion

Ref	Expression
ineqan12d	⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))

Proof of Theorem ineqan12d

Step	Hyp	Ref	Expression
1		ineq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		ineqan12d.2	. 2 ⊢ (𝜓 → 𝐶 = 𝐷)
3		ineq12 4174	. 2 ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))
4	1, 2, 3	syl2an 596	1 ⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))

Syntax hints:   → wi 4   ∧ wa 395   = wceq 1540   ∩ cin 3910

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2701

This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1543  df-ex 1780  df-sb 2066  df-clab 2708  df-cleq 2721  df-clel 2803  df-rab 3403  df-in 3918

This theorem is referenced by:  funprg  6554  funtpg  6555  funcnvpr  6562  funcnvqp  6564  fvun1  6934  fndmin  6999  ofrfvalg  7641  offval  7642  offval3  7940  fpar  8072  offsplitfpar  8075  fisn  9354  ixxin  13299  vdwmc  16925  fvcosymgeq  19343  cssincl  21630  inmbl  25476  iundisj2  25483  itg1addlem3  25632  fh1  31597  iundisj2f  32569  of0r  32652  iundisj2fi  32770  satffunlem1lem1  35382  satffunlem2lem1  35384  disjeccnvep  38265  disjecxrn  38368  br1cosscnvxrn  38458