Theorem ineqan12d 4229

Description: Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007.)

Hypotheses

Ref	Expression
ineq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)
ineqan12d.2	⊢ (𝜓 → 𝐶 = 𝐷)

Assertion

Ref	Expression
ineqan12d	⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))

Proof of Theorem ineqan12d

Step	Hyp	Ref	Expression
1		ineq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		ineqan12d.2	. 2 ⊢ (𝜓 → 𝐶 = 𝐷)
3		ineq12 4222	. 2 ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))
4	1, 2, 3	syl2an 596	1 ⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))

Syntax hints:   → wi 4   ∧ wa 395   = wceq 1536   ∩ cin 3961

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1791  ax-4 1805  ax-5 1907  ax-6 1964  ax-7 2004  ax-8 2107  ax-9 2115  ax-ext 2705

This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1539  df-ex 1776  df-sb 2062  df-clab 2712  df-cleq 2726  df-clel 2813  df-rab 3433  df-in 3969

This theorem is referenced by:  funprg  6621  funtpg  6622  funcnvpr  6629  funcnvqp  6631  fvun1  6999  fndmin  7064  ofrfvalg  7704  offval  7705  offval3  8005  fpar  8139  offsplitfpar  8142  wfrlem4OLD  8350  fisn  9464  ixxin  13400  vdwmc  17011  fvcosymgeq  19461  cssincl  21723  inmbl  25590  iundisj2  25597  itg1addlem3  25746  fh1  31646  iundisj2f  32609  of0r  32694  iundisj2fi  32804  satffunlem1lem1  35386  satffunlem2lem1  35388  disjeccnvep  38265  disjecxrn  38370  br1cosscnvxrn  38455