Theorem ineqan12d 4183

Description: Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007.)

Hypotheses

Ref	Expression
ineq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)
ineqan12d.2	⊢ (𝜓 → 𝐶 = 𝐷)

Assertion

Ref	Expression
ineqan12d	⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))

Proof of Theorem ineqan12d

Step	Hyp	Ref	Expression
1		ineq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		ineqan12d.2	. 2 ⊢ (𝜓 → 𝐶 = 𝐷)
3		ineq12 4176	. 2 ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))
4	1, 2, 3	syl2an 607	1 ⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷))

Syntax hints:   → wi 4   ∧ wa 400   = wceq 1567   ∩ cin 3912

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1822  ax-4 1836  ax-5 1937  ax-6 1994  ax-7 2035  ax-8 2151  ax-9 2159  ax-ext 2741

This theorem depends on definitions:  df-bi 210  df-an 401  df-tru 1570  df-ex 1807  df-sb 2098  df-clab 2748  df-cleq 2761  df-clel 2844  df-rab 3424  df-in 3920

This theorem is referenced by:  funprg  6591  funtpg  6592  funcnvpr  6599  funcnvqp  6601  fvun1  6973  fndmin  7041  ofrfvalg  7683  offval  7684  offval3  7979  fpar  8111  offsplitfpar  8114  fisn  9387  ixxin  13389  vdwmc  17038  fvcosymgeq  19499  cssincl  21807  inmbl  25670  iundisj2  25677  itg1addlem3  25826  fh1  31911  iundisj2f  32876  of0r  32965  iundisj2fi  33083  satffunlem1lem1  35827  satffunlem2lem1  35829  disjeccnvep  38863  disjecxrn  38985  br1cosscnvxrn  39137