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Theorem disjecxrn 39123
Description: Two ways of saying that (𝑅𝑆)-cosets are disjoint. (Contributed by Peter Mazsa, 19-Jun-2020.) (Revised by Peter Mazsa, 21-Aug-2023.)
Assertion
Ref Expression
disjecxrn ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) = ∅ ↔ (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ∨ ([𝐴]𝑆 ∩ [𝐵]𝑆) = ∅)))

Proof of Theorem disjecxrn
Dummy variables 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 ecxrn 39117 . . . . . . . . . 10 (𝐴𝑉 → [𝐴](𝑅𝑆) = {⟨𝑦, 𝑧⟩ ∣ (𝐴𝑅𝑦𝐴𝑆𝑧)})
2 ecxrn 39117 . . . . . . . . . 10 (𝐵𝑊 → [𝐵](𝑅𝑆) = {⟨𝑦, 𝑧⟩ ∣ (𝐵𝑅𝑦𝐵𝑆𝑧)})
31, 2ineqan12d 4175 . . . . . . . . 9 ((𝐴𝑉𝐵𝑊) → ([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) = ({⟨𝑦, 𝑧⟩ ∣ (𝐴𝑅𝑦𝐴𝑆𝑧)} ∩ {⟨𝑦, 𝑧⟩ ∣ (𝐵𝑅𝑦𝐵𝑆𝑧)}))
4 inopab 5818 . . . . . . . . 9 ({⟨𝑦, 𝑧⟩ ∣ (𝐴𝑅𝑦𝐴𝑆𝑧)} ∩ {⟨𝑦, 𝑧⟩ ∣ (𝐵𝑅𝑦𝐵𝑆𝑧)}) = {⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐴𝑆𝑧) ∧ (𝐵𝑅𝑦𝐵𝑆𝑧))}
53, 4eqtrdi 2816 . . . . . . . 8 ((𝐴𝑉𝐵𝑊) → ([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) = {⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐴𝑆𝑧) ∧ (𝐵𝑅𝑦𝐵𝑆𝑧))})
6 an4 669 . . . . . . . . 9 (((𝐴𝑅𝑦𝐴𝑆𝑧) ∧ (𝐵𝑅𝑦𝐵𝑆𝑧)) ↔ ((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧)))
76opabbii 5180 . . . . . . . 8 {⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐴𝑆𝑧) ∧ (𝐵𝑅𝑦𝐵𝑆𝑧))} = {⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧))}
85, 7eqtrdi 2816 . . . . . . 7 ((𝐴𝑉𝐵𝑊) → ([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) = {⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧))})
98neeq1d 3019 . . . . . 6 ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) ≠ ∅ ↔ {⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧))} ≠ ∅))
10 opabn0 5540 . . . . . 6 ({⟨𝑦, 𝑧⟩ ∣ ((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧))} ≠ ∅ ↔ ∃𝑦𝑧((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧)))
119, 10bitrdi 290 . . . . 5 ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) ≠ ∅ ↔ ∃𝑦𝑧((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧))))
12 exdistrv 1988 . . . . 5 (∃𝑦𝑧((𝐴𝑅𝑦𝐵𝑅𝑦) ∧ (𝐴𝑆𝑧𝐵𝑆𝑧)) ↔ (∃𝑦(𝐴𝑅𝑦𝐵𝑅𝑦) ∧ ∃𝑧(𝐴𝑆𝑧𝐵𝑆𝑧)))
1311, 12bitrdi 290 . . . 4 ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) ≠ ∅ ↔ (∃𝑦(𝐴𝑅𝑦𝐵𝑅𝑦) ∧ ∃𝑧(𝐴𝑆𝑧𝐵𝑆𝑧))))
14 ecinn0 39064 . . . . 5 ((𝐴𝑉𝐵𝑊) → (([𝐴]𝑅 ∩ [𝐵]𝑅) ≠ ∅ ↔ ∃𝑦(𝐴𝑅𝑦𝐵𝑅𝑦)))
15 ecinn0 39064 . . . . 5 ((𝐴𝑉𝐵𝑊) → (([𝐴]𝑆 ∩ [𝐵]𝑆) ≠ ∅ ↔ ∃𝑧(𝐴𝑆𝑧𝐵𝑆𝑧)))
1614, 15anbi12d 644 . . . 4 ((𝐴𝑉𝐵𝑊) → ((([𝐴]𝑅 ∩ [𝐵]𝑅) ≠ ∅ ∧ ([𝐴]𝑆 ∩ [𝐵]𝑆) ≠ ∅) ↔ (∃𝑦(𝐴𝑅𝑦𝐵𝑅𝑦) ∧ ∃𝑧(𝐴𝑆𝑧𝐵𝑆𝑧))))
1713, 16bitr4d 285 . . 3 ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) ≠ ∅ ↔ (([𝐴]𝑅 ∩ [𝐵]𝑅) ≠ ∅ ∧ ([𝐴]𝑆 ∩ [𝐵]𝑆) ≠ ∅)))
18 neanior 3053 . . 3 ((([𝐴]𝑅 ∩ [𝐵]𝑅) ≠ ∅ ∧ ([𝐴]𝑆 ∩ [𝐵]𝑆) ≠ ∅) ↔ ¬ (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ∨ ([𝐴]𝑆 ∩ [𝐵]𝑆) = ∅))
1917, 18bitrdi 290 . 2 ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) ≠ ∅ ↔ ¬ (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ∨ ([𝐴]𝑆 ∩ [𝐵]𝑆) = ∅)))
2019necon4abid 3000 1 ((𝐴𝑉𝐵𝑊) → (([𝐴](𝑅𝑆) ∩ [𝐵](𝑅𝑆)) = ∅ ↔ (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ∨ ([𝐴]𝑆 ∩ [𝐵]𝑆) = ∅)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3  wi 4  wb 209  wa 401  wo 861   = wceq 1570  wex 1812  wcel 2146  wne 2960  cin 3905  c0 4286   class class class wbr 5111  {copab 5175  [cec 8698  cxrn 38885
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2195  ax-12 2216  ax-ext 2737  ax-sep 5259  ax-nul 5271  ax-pr 5406  ax-un 7742
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2569  df-eu 2599  df-clab 2744  df-cleq 2757  df-clel 2840  df-nfc 2914  df-ne 2961  df-ral 3082  df-rex 3092  df-rab 3419  df-v 3459  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-nul 4287  df-if 4490  df-sn 4592  df-pr 4594  df-op 4598  df-uni 4875  df-br 5112  df-opab 5176  df-mpt 5195  df-id 5558  df-xp 5669  df-rel 5670  df-cnv 5671  df-co 5672  df-dm 5673  df-rn 5674  df-res 5675  df-ima 5676  df-iota 6496  df-fun 6542  df-fn 6543  df-f 6544  df-fo 6546  df-fv 6548  df-1st 7992  df-2nd 7993  df-ec 8702  df-xrn 39091
This theorem is used by:  disjecxrncnvep  39124
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