Theorem 3sstr4g 3090

Description: Substitution of equality into both sides of a subclass relationship. (Contributed by NM, 16-Aug-1994.) (Proof shortened by Eric Schmidt, 26-Jan-2007.)

Hypotheses

Ref	Expression
3sstr4g.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
3sstr4g.2	⊢ 𝐶 = 𝐴
3sstr4g.3	⊢ 𝐷 = 𝐵

Assertion

Ref	Expression
3sstr4g	⊢ (𝜑 → 𝐶 ⊆ 𝐷)

Proof of Theorem 3sstr4g

Step	Hyp	Ref	Expression
1		3sstr4g.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		3sstr4g.2	. . 3 ⊢ 𝐶 = 𝐴
3		3sstr4g.3	. . 3 ⊢ 𝐷 = 𝐵
4	2, 3	sseq12i 3075	. 2 ⊢ (𝐶 ⊆ 𝐷 ↔ 𝐴 ⊆ 𝐵)
5	1, 4	sylibr 133	1 ⊢ (𝜑 → 𝐶 ⊆ 𝐷)

Syntax hints:   → wi 4   = wceq 1299   ⊆ wss 3021

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1391  ax-7 1392  ax-gen 1393  ax-ie1 1437  ax-ie2 1438  ax-8 1450  ax-11 1452  ax-4 1455  ax-17 1474  ax-i9 1478  ax-ial 1482  ax-i5r 1483  ax-ext 2082

This theorem depends on definitions:  df-bi 116  df-nf 1405  df-sb 1704  df-clab 2087  df-cleq 2093  df-clel 2096  df-in 3027  df-ss 3034

This theorem is referenced by:  rabss2  3127  unss2  3194  sslin  3249  ssopab2  4135  xpss12  4584  coss1  4632  coss2  4633  cnvss  4650  rnss  4707  ssres  4781  ssres2  4782  imass1  4850  imass2  4851  imadif  5139  imain  5141  ssoprab2  5759  suppssfv  5910  suppssov1  5911  tposss  6073  ss2ixp  6535  isumsplit  11099  isumrpcl  11102