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Theorem iftrueb01 7484
Description: Using an if expression to represent a truth value by or 1o. Unlike some theorems using if, 𝜑 does not need to be decidable. (Contributed by Jim Kingdon, 9-Jan-2026.)
Assertion
Ref Expression
iftrueb01 (if(𝜑, 1o, ∅) = 1o𝜑)

Proof of Theorem iftrueb01
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 0lt1o 6651 . . . 4 ∅ ∈ 1o
2 elex2 2820 . . . 4 (∅ ∈ 1o → ∃𝑥 𝑥 ∈ 1o)
31, 2ax-mp 5 . . 3 𝑥 𝑥 ∈ 1o
4 eleq2 2295 . . . . . 6 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ if(𝜑, 1o, ∅) ↔ 𝑥 ∈ 1o))
5 elif 3621 . . . . . . 7 (𝑥 ∈ if(𝜑, 1o, ∅) ↔ ((𝜑𝑥 ∈ 1o) ∨ (¬ 𝜑𝑥 ∈ ∅)))
6 noel 3500 . . . . . . . . 9 ¬ 𝑥 ∈ ∅
76intnan 937 . . . . . . . 8 ¬ (¬ 𝜑𝑥 ∈ ∅)
87biorfi 754 . . . . . . 7 ((𝜑𝑥 ∈ 1o) ↔ ((𝜑𝑥 ∈ 1o) ∨ (¬ 𝜑𝑥 ∈ ∅)))
95, 8bitr4i 187 . . . . . 6 (𝑥 ∈ if(𝜑, 1o, ∅) ↔ (𝜑𝑥 ∈ 1o))
104, 9bitr3di 195 . . . . 5 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ 1o ↔ (𝜑𝑥 ∈ 1o)))
11 pm4.71r 390 . . . . 5 ((𝑥 ∈ 1o𝜑) ↔ (𝑥 ∈ 1o ↔ (𝜑𝑥 ∈ 1o)))
1210, 11sylibr 134 . . . 4 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ 1o𝜑))
1312exlimdv 1867 . . 3 (if(𝜑, 1o, ∅) = 1o → (∃𝑥 𝑥 ∈ 1o𝜑))
143, 13mpi 15 . 2 (if(𝜑, 1o, ∅) = 1o𝜑)
15 iftrue 3614 . 2 (𝜑 → if(𝜑, 1o, ∅) = 1o)
1614, 15impbii 126 1 (if(𝜑, 1o, ∅) = 1o𝜑)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4  wa 104  wb 105  wo 716   = wceq 1398  wex 1541  wcel 2202  c0 3496  ifcif 3607  1oc1o 6618
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2213  ax-nul 4220
This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2364  df-v 2805  df-dif 3203  df-un 3205  df-nul 3497  df-if 3608  df-sn 3679  df-suc 4474  df-1o 6625
This theorem is referenced by:  pw1map  16700
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