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Theorem iftrueb01 7440
Description: Using an if expression to represent a truth value by or 1o. Unlike some theorems using if, 𝜑 does not need to be decidable. (Contributed by Jim Kingdon, 9-Jan-2026.)
Assertion
Ref Expression
iftrueb01 (if(𝜑, 1o, ∅) = 1o𝜑)

Proof of Theorem iftrueb01
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 0lt1o 6607 . . . 4 ∅ ∈ 1o
2 elex2 2819 . . . 4 (∅ ∈ 1o → ∃𝑥 𝑥 ∈ 1o)
31, 2ax-mp 5 . . 3 𝑥 𝑥 ∈ 1o
4 eleq2 2295 . . . . . 6 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ if(𝜑, 1o, ∅) ↔ 𝑥 ∈ 1o))
5 elif 3617 . . . . . . 7 (𝑥 ∈ if(𝜑, 1o, ∅) ↔ ((𝜑𝑥 ∈ 1o) ∨ (¬ 𝜑𝑥 ∈ ∅)))
6 noel 3498 . . . . . . . . 9 ¬ 𝑥 ∈ ∅
76intnan 936 . . . . . . . 8 ¬ (¬ 𝜑𝑥 ∈ ∅)
87biorfi 753 . . . . . . 7 ((𝜑𝑥 ∈ 1o) ↔ ((𝜑𝑥 ∈ 1o) ∨ (¬ 𝜑𝑥 ∈ ∅)))
95, 8bitr4i 187 . . . . . 6 (𝑥 ∈ if(𝜑, 1o, ∅) ↔ (𝜑𝑥 ∈ 1o))
104, 9bitr3di 195 . . . . 5 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ 1o ↔ (𝜑𝑥 ∈ 1o)))
11 pm4.71r 390 . . . . 5 ((𝑥 ∈ 1o𝜑) ↔ (𝑥 ∈ 1o ↔ (𝜑𝑥 ∈ 1o)))
1210, 11sylibr 134 . . . 4 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ 1o𝜑))
1312exlimdv 1867 . . 3 (if(𝜑, 1o, ∅) = 1o → (∃𝑥 𝑥 ∈ 1o𝜑))
143, 13mpi 15 . 2 (if(𝜑, 1o, ∅) = 1o𝜑)
15 iftrue 3610 . 2 (𝜑 → if(𝜑, 1o, ∅) = 1o)
1614, 15impbii 126 1 (if(𝜑, 1o, ∅) = 1o𝜑)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4  wa 104  wb 105  wo 715   = wceq 1397  wex 1540  wcel 2202  c0 3494  ifcif 3605  1oc1o 6574
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 716  ax-5 1495  ax-7 1496  ax-gen 1497  ax-ie1 1541  ax-ie2 1542  ax-8 1552  ax-10 1553  ax-11 1554  ax-i12 1555  ax-bndl 1557  ax-4 1558  ax-17 1574  ax-i9 1578  ax-ial 1582  ax-i5r 1583  ax-ext 2213  ax-nul 4215
This theorem depends on definitions:  df-bi 117  df-tru 1400  df-nf 1509  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2363  df-v 2804  df-dif 3202  df-un 3204  df-nul 3495  df-if 3606  df-sn 3675  df-suc 4468  df-1o 6581
This theorem is referenced by:  pw1map  16596
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