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Theorem iftrueb01 7572
Description: Using an if expression to represent a truth value by or 1o. Unlike some theorems using if, 𝜑 does not need to be decidable. (Contributed by Jim Kingdon, 9-Jan-2026.)
Assertion
Ref Expression
iftrueb01 (if(𝜑, 1o, ∅) = 1o𝜑)

Proof of Theorem iftrueb01
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 0lt1o 6703 . . . 4 ∅ ∈ 1o
2 elex2 2838 . . . 4 (∅ ∈ 1o → ∃𝑥 𝑥 ∈ 1o)
31, 2ax-mp 5 . . 3 𝑥 𝑥 ∈ 1o
4 eleq2 2302 . . . . . 6 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ if(𝜑, 1o, ∅) ↔ 𝑥 ∈ 1o))
5 elif 3649 . . . . . . 7 (𝑥 ∈ if(𝜑, 1o, ∅) ↔ ((𝜑𝑥 ∈ 1o) ∨ (¬ 𝜑𝑥 ∈ ∅)))
6 noel 3525 . . . . . . . . 9 ¬ 𝑥 ∈ ∅
76intnan 941 . . . . . . . 8 ¬ (¬ 𝜑𝑥 ∈ ∅)
87biorfi 758 . . . . . . 7 ((𝜑𝑥 ∈ 1o) ↔ ((𝜑𝑥 ∈ 1o) ∨ (¬ 𝜑𝑥 ∈ ∅)))
95, 8bitr4i 187 . . . . . 6 (𝑥 ∈ if(𝜑, 1o, ∅) ↔ (𝜑𝑥 ∈ 1o))
104, 9bitr3di 195 . . . . 5 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ 1o ↔ (𝜑𝑥 ∈ 1o)))
11 pm4.71r 394 . . . . 5 ((𝑥 ∈ 1o𝜑) ↔ (𝑥 ∈ 1o ↔ (𝜑𝑥 ∈ 1o)))
1210, 11sylibr 134 . . . 4 (if(𝜑, 1o, ∅) = 1o → (𝑥 ∈ 1o𝜑))
1312exlimdv 1872 . . 3 (if(𝜑, 1o, ∅) = 1o → (∃𝑥 𝑥 ∈ 1o𝜑))
143, 13mpi 15 . 2 (if(𝜑, 1o, ∅) = 1o𝜑)
15 iftrue 3642 . 2 (𝜑 → if(𝜑, 1o, ∅) = 1o)
1614, 15impbii 126 1 (if(𝜑, 1o, ∅) = 1o𝜑)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4  wa 104  wb 105  wo 720   = wceq 1402  wex 1545  wcel 2209  c0 3520  ifcif 3635  1oc1o 6670
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220  ax-nul 4254
This theorem depends on definitions:  df-bi 117  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-v 2823  df-dif 3222  df-un 3224  df-nul 3521  df-if 3636  df-sn 3711  df-suc 4511  df-1o 6677
This theorem is referenced by:  pw1map  16939
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