Theorem inteqd 3693

Description: Equality deduction for class intersection. (Contributed by NM, 2-Sep-2003.)

Hypothesis

Ref	Expression
inteqd.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
inteqd	⊢ (𝜑 → ∩ 𝐴 = ∩ 𝐵)

Proof of Theorem inteqd

Step	Hyp	Ref	Expression
1		inteqd.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		inteq 3691	. 2 ⊢ (𝐴 = 𝐵 → ∩ 𝐴 = ∩ 𝐵)
3	1, 2	syl 14	1 ⊢ (𝜑 → ∩ 𝐴 = ∩ 𝐵)

Syntax hints:   → wi 4   = wceq 1289  ∩ cint 3688

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 665  ax-5 1381  ax-7 1382  ax-gen 1383  ax-ie1 1427  ax-ie2 1428  ax-8 1440  ax-10 1441  ax-11 1442  ax-i12 1443  ax-bndl 1444  ax-4 1445  ax-17 1464  ax-i9 1468  ax-ial 1472  ax-i5r 1473  ax-ext 2070

This theorem depends on definitions:  df-bi 115  df-tru 1292  df-nf 1395  df-sb 1693  df-clab 2075  df-cleq 2081  df-clel 2084  df-nfc 2217  df-ral 2364  df-int 3689

This theorem is referenced by:  intprg  3721  op1stbg  4301  onsucmin  4324  elreldm  4661  elxp5  4919  fniinfv  5362  1stval2  5926  2ndval2  5927  fundmen  6521  xpsnen  6535  fiintim  6637  cardcl  6807  isnumi  6808  cardval3ex  6811  carden2bex  6815