| Intuitionistic Logic Explorer |
< Previous
Next >
Nearby theorems |
||
| Mirrors > Home > ILE Home > Th. List > ordelsuc | GIF version | ||
| Description: A set belongs to an ordinal iff its successor is a subset of the ordinal. Exercise 8 of [TakeutiZaring] p. 42 and its converse. (Contributed by NM, 29-Nov-2003.) |
| Ref | Expression |
|---|---|
| ordelsuc | ⊢ ((𝐴 ∈ 𝐶 ∧ Ord 𝐵) → (𝐴 ∈ 𝐵 ↔ suc 𝐴 ⊆ 𝐵)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ordsucss 4651 | . . 3 ⊢ (Ord 𝐵 → (𝐴 ∈ 𝐵 → suc 𝐴 ⊆ 𝐵)) | |
| 2 | 1 | adantl 277 | . 2 ⊢ ((𝐴 ∈ 𝐶 ∧ Ord 𝐵) → (𝐴 ∈ 𝐵 → suc 𝐴 ⊆ 𝐵)) |
| 3 | sucssel 4569 | . . 3 ⊢ (𝐴 ∈ 𝐶 → (suc 𝐴 ⊆ 𝐵 → 𝐴 ∈ 𝐵)) | |
| 4 | 3 | adantr 276 | . 2 ⊢ ((𝐴 ∈ 𝐶 ∧ Ord 𝐵) → (suc 𝐴 ⊆ 𝐵 → 𝐴 ∈ 𝐵)) |
| 5 | 2, 4 | impbid 129 | 1 ⊢ ((𝐴 ∈ 𝐶 ∧ Ord 𝐵) → (𝐴 ∈ 𝐵 ↔ suc 𝐴 ⊆ 𝐵)) |
| Colors of variables: wff set class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 104 ↔ wb 105 ∈ wcel 2209 ⊆ wss 3220 Ord word 4507 suc csuc 4510 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 721 ax-5 1500 ax-7 1501 ax-gen 1502 ax-ie1 1546 ax-ie2 1547 ax-8 1557 ax-10 1558 ax-11 1559 ax-i12 1560 ax-bndl 1562 ax-4 1563 ax-17 1579 ax-i9 1583 ax-ial 1587 ax-i5r 1588 ax-ext 2220 |
| This proof depends on definitions: df-bi 117 df-tru 1405 df-nf 1514 df-sb 1816 df-clab 2225 df-cleq 2231 df-clel 2234 df-nfc 2381 df-ral 2533 df-v 2823 df-un 3224 df-in 3226 df-ss 3233 df-sn 3715 df-uni 3936 df-tr 4230 df-iord 4511 df-suc 4516 |
| This theorem is used by: onsucssi 4653 onsucmin 4654 onsucelsucr 4655 onsucsssucr 4656 onsucsssucexmid 4674 frecsuclem 6677 ordgt0ge1 6708 nnsucsssuc 6765 ennnfonelemk 13291 nninfsellemeq 17057 |
| Copyright terms: Public domain | W3C validator |