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Theorem cnvepnep 9609
Description: The membership (epsilon) relation and its converse are disjoint, i.e., E is an asymmetric relation. Variable-free version of en2lp 9607. (Proposed by BJ, 18-Jun-2022.) (Contributed by AV, 19-Jun-2022.)
Assertion
Ref Expression
cnvepnep (◡ E ∩ E ) = ∅

Proof of Theorem cnvepnep
Dummy variables 𝑥 𝑦 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-eprel 5551 . . . . . 6 E = {⟨𝑦, 𝑥⟩ ∣ 𝑦 ∈ 𝑥}
21cnveqi 5852 . . . . 5 ◡ E = ◡{⟨𝑦, 𝑥⟩ ∣ 𝑦 ∈ 𝑥}
3 cnvopab 6131 . . . . 5 ◡{⟨𝑦, 𝑥⟩ ∣ 𝑦 ∈ 𝑥} = {⟨𝑥, 𝑦⟩ ∣ 𝑦 ∈ 𝑥}
42, 3eqtri 2784 . . . 4 ◡ E = {⟨𝑥, 𝑦⟩ ∣ 𝑦 ∈ 𝑥}
5 df-eprel 5551 . . . 4 E = {⟨𝑥, 𝑦⟩ ∣ 𝑥 ∈ 𝑦}
64, 5ineq12i 4164 . . 3 (◡ E ∩ E ) = ({⟨𝑥, 𝑦⟩ ∣ 𝑦 ∈ 𝑥} ∩ {⟨𝑥, 𝑦⟩ ∣ 𝑥 ∈ 𝑦})
7 inopab 5807 . . 3 ({⟨𝑥, 𝑦⟩ ∣ 𝑦 ∈ 𝑥} ∩ {⟨𝑥, 𝑦⟩ ∣ 𝑥 ∈ 𝑦}) = {⟨𝑥, 𝑦⟩ ∣ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦)}
86, 7eqtri 2784 . 2 (◡ E ∩ E ) = {⟨𝑥, 𝑦⟩ ∣ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦)}
9 en2lp 9607 . . . 4 ¬ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦)
109gen2 1829 . . 3 ∀𝑥∀𝑦 ¬ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦)
11 opab0 5529 . . 3 ({⟨𝑥, 𝑦⟩ ∣ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦)} = ∅ ↔ ∀𝑥∀𝑦 ¬ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦))
1210, 11mpbir 234 . 2 {⟨𝑥, 𝑦⟩ ∣ (𝑦 ∈ 𝑥 ∧ 𝑥 ∈ 𝑦)} = ∅
138, 12eqtri 2784 1 (◡ E ∩ E ) = ∅
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   ∧ wa 401  ∀wal 1568   = wceq 1570   ∩ cin 3898  ∅c0 4279  {copab 5167   E cep 5550  ◡ccnv 5650
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-ext 2733  ax-sep 5249  ax-pr 5391  ax-reg 9586
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-ne 2957  df-ral 3078  df-rex 3088  df-rab 3414  df-v 3453  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-pw 4559  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-eprel 5551  df-fr 5604  df-xp 5657  df-rel 5658  df-cnv 5659
This theorem is used by:  epnsym  9610
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