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Theorem List for Metamath Proof Explorer - 9601-9700   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremdjulf1o 9601 The left injection function on all sets is one to one and onto. (Contributed by Jim Kingdon, 22-Jun-2022.)
inl:V–1-1-onto→({∅} × V)
 
Theoremdjurf1o 9602 The right injection function on all sets is one to one and onto. (Contributed by Jim Kingdon, 22-Jun-2022.)
inr:V–1-1-onto→({1o} × V)
 
Theoreminlresf 9603 The left injection restricted to the left class of a disjoint union is a function from the left class into the disjoint union. (Contributed by AV, 27-Jun-2022.)
(inl ↾ 𝐴):𝐴⟶(𝐴𝐵)
 
Theoreminlresf1 9604 The left injection restricted to the left class of a disjoint union is an injective function from the left class into the disjoint union. (Contributed by AV, 28-Jun-2022.)
(inl ↾ 𝐴):𝐴1-1→(𝐴𝐵)
 
Theoreminrresf 9605 The right injection restricted to the right class of a disjoint union is a function from the right class into the disjoint union. (Contributed by AV, 27-Jun-2022.)
(inr ↾ 𝐵):𝐵⟶(𝐴𝐵)
 
Theoreminrresf1 9606 The right injection restricted to the right class of a disjoint union is an injective function from the right class into the disjoint union. (Contributed by AV, 28-Jun-2022.)
(inr ↾ 𝐵):𝐵1-1→(𝐴𝐵)
 
Theoremdjuin 9607 The images of any classes under right and left injection produce disjoint sets. (Contributed by Jim Kingdon, 21-Jun-2022.)
((inl “ 𝐴) ∩ (inr “ 𝐵)) = ∅
 
Theoremdjur 9608* A member of a disjoint union can be mapped from one of the classes which produced it. (Contributed by Jim Kingdon, 23-Jun-2022.)
(𝐶 ∈ (𝐴𝐵) → (∃𝑥𝐴 𝐶 = (inl‘𝑥) ∨ ∃𝑥𝐵 𝐶 = (inr‘𝑥)))
 
Theoremdjuss 9609 A disjoint union is a subclass of a Cartesian product. (Contributed by AV, 25-Jun-2022.)
(𝐴𝐵) ⊆ ({∅, 1o} × (𝐴𝐵))
 
Theoremdjuunxp 9610 The union of a disjoint union and its inversion is the Cartesian product of an unordered pair and the union of the left and right classes of the disjoint unions. (Proposed by GL, 4-Jul-2022.) (Contributed by AV, 4-Jul-2022.)
((𝐴𝐵) ∪ (𝐵𝐴)) = ({∅, 1o} × (𝐴𝐵))
 
TheoremdjuexALT 9611 Alternate proof of djuex 9597, which is shorter, but based indirectly on the definitions of inl and inr. (Proposed by BJ, 28-Jun-2022.) (Contributed by AV, 28-Jun-2022.) (Proof modification is discouraged.) (New usage is discouraged.)
((𝐴𝑉𝐵𝑊) → (𝐴𝐵) ∈ V)
 
Theoremeldju1st 9612 The first component of an element of a disjoint union is either or 1o. (Contributed by AV, 26-Jun-2022.)
(𝑋 ∈ (𝐴𝐵) → ((1st𝑋) = ∅ ∨ (1st𝑋) = 1o))
 
Theoremeldju2ndl 9613 The second component of an element of a disjoint union is an element of the left class of the disjoint union if its first component is the empty set. (Contributed by AV, 26-Jun-2022.)
((𝑋 ∈ (𝐴𝐵) ∧ (1st𝑋) = ∅) → (2nd𝑋) ∈ 𝐴)
 
Theoremeldju2ndr 9614 The second component of an element of a disjoint union is an element of the right class of the disjoint union if its first component is not the empty set. (Contributed by AV, 26-Jun-2022.)
((𝑋 ∈ (𝐴𝐵) ∧ (1st𝑋) ≠ ∅) → (2nd𝑋) ∈ 𝐵)
 
Theoremdjuun 9615 The disjoint union of two classes is the union of the images of those two classes under right and left injection. (Contributed by Jim Kingdon, 22-Jun-2022.)
((inl “ 𝐴) ∪ (inr “ 𝐵)) = (𝐴𝐵)
 
Theorem1stinl 9616 The first component of the value of a left injection is the empty set. (Contributed by AV, 27-Jun-2022.)
(𝑋𝑉 → (1st ‘(inl‘𝑋)) = ∅)
 
Theorem2ndinl 9617 The second component of the value of a left injection is its argument. (Contributed by AV, 27-Jun-2022.)
(𝑋𝑉 → (2nd ‘(inl‘𝑋)) = 𝑋)
 
Theorem1stinr 9618 The first component of the value of a right injection is 1o. (Contributed by AV, 27-Jun-2022.)
(𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)
 
Theorem2ndinr 9619 The second component of the value of a right injection is its argument. (Contributed by AV, 27-Jun-2022.)
(𝑋𝑉 → (2nd ‘(inr‘𝑋)) = 𝑋)
 
Theoremupdjudhf 9620* The mapping of an element of the disjoint union to the value of the corresponding function is a function. (Contributed by AV, 26-Jun-2022.)
(𝜑𝐹:𝐴𝐶)    &   (𝜑𝐺:𝐵𝐶)    &   𝐻 = (𝑥 ∈ (𝐴𝐵) ↦ if((1st𝑥) = ∅, (𝐹‘(2nd𝑥)), (𝐺‘(2nd𝑥))))       (𝜑𝐻:(𝐴𝐵)⟶𝐶)
 
Theoremupdjudhcoinlf 9621* The composition of the mapping of an element of the disjoint union to the value of the corresponding function and the left injection equals the first function. (Contributed by AV, 27-Jun-2022.)
(𝜑𝐹:𝐴𝐶)    &   (𝜑𝐺:𝐵𝐶)    &   𝐻 = (𝑥 ∈ (𝐴𝐵) ↦ if((1st𝑥) = ∅, (𝐹‘(2nd𝑥)), (𝐺‘(2nd𝑥))))       (𝜑 → (𝐻 ∘ (inl ↾ 𝐴)) = 𝐹)
 
Theoremupdjudhcoinrg 9622* The composition of the mapping of an element of the disjoint union to the value of the corresponding function and the right injection equals the second function. (Contributed by AV, 27-Jun-2022.)
(𝜑𝐹:𝐴𝐶)    &   (𝜑𝐺:𝐵𝐶)    &   𝐻 = (𝑥 ∈ (𝐴𝐵) ↦ if((1st𝑥) = ∅, (𝐹‘(2nd𝑥)), (𝐺‘(2nd𝑥))))       (𝜑 → (𝐻 ∘ (inr ↾ 𝐵)) = 𝐺)
 
Theoremupdjud 9623* Universal property of the disjoint union. This theorem shows that the disjoint union, together with the left and right injections df-inl 9591 and df-inr 9592, is the coproduct in the category of sets, see Wikipedia "Coproduct", https://en.wikipedia.org/wiki/Coproduct 9592 (25-Aug-2023). This is a special case of Example 1 of coproducts in Section 10.67 of [Adamek] p. 185. (Proposed by BJ, 25-Jun-2022.) (Contributed by AV, 28-Jun-2022.)
(𝜑𝐹:𝐴𝐶)    &   (𝜑𝐺:𝐵𝐶)    &   (𝜑𝐴𝑉)    &   (𝜑𝐵𝑊)       (𝜑 → ∃!(:(𝐴𝐵)⟶𝐶 ∧ ( ∘ (inl ↾ 𝐴)) = 𝐹 ∧ ( ∘ (inr ↾ 𝐵)) = 𝐺))
 
2.6.11  Cardinal numbers
 
Syntaxccrd 9624 Extend class definition to include the cardinal size function.
class card
 
Syntaxcale 9625 Extend class definition to include the aleph function.
class
 
Syntaxccf 9626 Extend class definition to include the cofinality function.
class cf
 
Syntaxwacn 9627 The axiom of choice for limited-length sequences.
class AC 𝐴
 
Definitiondf-card 9628* Define the cardinal number function. The cardinal number of a set is the least ordinal number equinumerous to it. In other words, it is the "size" of the set. Definition of [Enderton] p. 197. See cardval 10233 for its value and cardval2 9680 for a simpler version of its value. The principal theorem relating cardinality to equinumerosity is carden 10238. Our notation is from Enderton. Other textbooks often use a double bar over the set to express this function. (Contributed by NM, 21-Oct-2003.)
card = (𝑥 ∈ V ↦ {𝑦 ∈ On ∣ 𝑦𝑥})
 
Definitiondf-aleph 9629 Define the aleph function. Our definition expresses Definition 12 of [Suppes] p. 229 in a closed form, from which we derive the recursive definition as Theorems aleph0 9753, alephsuc 9755, and alephlim 9754. The aleph function provides a one-to-one, onto mapping from the ordinal numbers to the infinite cardinal numbers. Roughly, any aleph is the smallest infinite cardinal number whose size is strictly greater than any aleph before it. (Contributed by NM, 21-Oct-2003.)
ℵ = rec(har, ω)
 
Definitiondf-cf 9630* Define the cofinality function. Definition B of Saharon Shelah, Cardinal Arithmetic (1994), p. xxx (Roman numeral 30). See cfval 9934 for its value and a description. (Contributed by NM, 1-Apr-2004.)
cf = (𝑥 ∈ On ↦ {𝑦 ∣ ∃𝑧(𝑦 = (card‘𝑧) ∧ (𝑧𝑥 ∧ ∀𝑣𝑥𝑢𝑧 𝑣𝑢))})
 
Definitiondf-acn 9631* Define a local and length-limited version of the axiom of choice. The definition of the predicate 𝑋AC 𝐴 is that for all families of nonempty subsets of 𝑋 indexed on 𝐴 (i.e. functions 𝐴⟶𝒫 𝑋 ∖ {∅}), there is a function which selects an element from each set in the family. (Contributed by Mario Carneiro, 31-Aug-2015.)
AC 𝐴 = {𝑥 ∣ (𝐴 ∈ V ∧ ∀𝑓 ∈ ((𝒫 𝑥 ∖ {∅}) ↑m 𝐴)∃𝑔𝑦𝐴 (𝑔𝑦) ∈ (𝑓𝑦))}
 
Theoremcardf2 9632* The cardinality function is a function with domain the well-orderable sets. Assuming AC, this is the universe. (Contributed by Mario Carneiro, 6-Jun-2013.) (Revised by Mario Carneiro, 20-Sep-2014.)
card:{𝑥 ∣ ∃𝑦 ∈ On 𝑦𝑥}⟶On
 
Theoremcardon 9633 The cardinal number of a set is an ordinal number. Proposition 10.6(1) of [TakeutiZaring] p. 85. (Contributed by Mario Carneiro, 7-Jan-2013.) (Revised by Mario Carneiro, 13-Sep-2013.)
(card‘𝐴) ∈ On
 
Theoremisnum2 9634* A way to express well-orderability without bound or distinct variables. (Contributed by Stefan O'Rear, 28-Feb-2015.) (Revised by Mario Carneiro, 27-Apr-2015.)
(𝐴 ∈ dom card ↔ ∃𝑥 ∈ On 𝑥𝐴)
 
Theoremisnumi 9635 A set equinumerous to an ordinal is numerable. (Contributed by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ On ∧ 𝐴𝐵) → 𝐵 ∈ dom card)
 
Theoremennum 9636 Equinumerous sets are equi-numerable. (Contributed by Mario Carneiro, 29-Apr-2015.)
(𝐴𝐵 → (𝐴 ∈ dom card ↔ 𝐵 ∈ dom card))
 
Theoremfinnum 9637 Every finite set is numerable. (Contributed by Mario Carneiro, 4-Feb-2013.) (Revised by Mario Carneiro, 29-Apr-2015.)
(𝐴 ∈ Fin → 𝐴 ∈ dom card)
 
Theoremonenon 9638 Every ordinal number is numerable. (Contributed by Mario Carneiro, 29-Apr-2015.)
(𝐴 ∈ On → 𝐴 ∈ dom card)
 
Theoremtskwe 9639* A Tarski set is well-orderable. (Contributed by Mario Carneiro, 19-Apr-2013.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴𝑉 ∧ {𝑥 ∈ 𝒫 𝐴𝑥𝐴} ⊆ 𝐴) → 𝐴 ∈ dom card)
 
Theoremxpnum 9640 The cartesian product of numerable sets is numerable. (Contributed by Mario Carneiro, 3-Mar-2013.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ dom card ∧ 𝐵 ∈ dom card) → (𝐴 × 𝐵) ∈ dom card)
 
Theoremcardval3 9641* An alternate definition of the value of (card‘𝐴) that does not require AC to prove. (Contributed by Mario Carneiro, 7-Jan-2013.) (Revised by Mario Carneiro, 27-Apr-2015.)
(𝐴 ∈ dom card → (card‘𝐴) = {𝑥 ∈ On ∣ 𝑥𝐴})
 
Theoremcardid2 9642 Any numerable set is equinumerous to its cardinal number. Proposition 10.5 of [TakeutiZaring] p. 85. (Contributed by Mario Carneiro, 7-Jan-2013.)
(𝐴 ∈ dom card → (card‘𝐴) ≈ 𝐴)
 
Theoremisnum3 9643 A set is numerable iff it is equinumerous with its cardinal. (Contributed by Mario Carneiro, 29-Apr-2015.)
(𝐴 ∈ dom card ↔ (card‘𝐴) ≈ 𝐴)
 
Theoremoncardval 9644* The value of the cardinal number function with an ordinal number as its argument. Unlike cardval 10233, this theorem does not require the Axiom of Choice. (Contributed by NM, 24-Nov-2003.) (Revised by Mario Carneiro, 13-Sep-2013.)
(𝐴 ∈ On → (card‘𝐴) = {𝑥 ∈ On ∣ 𝑥𝐴})
 
Theoremoncardid 9645 Any ordinal number is equinumerous to its cardinal number. Unlike cardid 10234, this theorem does not require the Axiom of Choice. (Contributed by NM, 26-Jul-2004.)
(𝐴 ∈ On → (card‘𝐴) ≈ 𝐴)
 
Theoremcardonle 9646 The cardinal of an ordinal number is less than or equal to the ordinal number. Proposition 10.6(3) of [TakeutiZaring] p. 85. (Contributed by NM, 22-Oct-2003.)
(𝐴 ∈ On → (card‘𝐴) ⊆ 𝐴)
 
Theoremcard0 9647 The cardinality of the empty set is the empty set. (Contributed by NM, 25-Oct-2003.)
(card‘∅) = ∅
 
Theoremcardidm 9648 The cardinality function is idempotent. Proposition 10.11 of [TakeutiZaring] p. 85. (Contributed by Mario Carneiro, 7-Jan-2013.)
(card‘(card‘𝐴)) = (card‘𝐴)
 
Theoremoncard 9649* A set is a cardinal number iff it equals its own cardinal number. Proposition 10.9 of [TakeutiZaring] p. 85. (Contributed by Mario Carneiro, 7-Jan-2013.)
(∃𝑥 𝐴 = (card‘𝑥) ↔ 𝐴 = (card‘𝐴))
 
Theoremficardom 9650 The cardinal number of a finite set is a finite ordinal. (Contributed by Paul Chapman, 11-Apr-2009.) (Revised by Mario Carneiro, 4-Feb-2013.)
(𝐴 ∈ Fin → (card‘𝐴) ∈ ω)
 
Theoremficardid 9651 A finite set is equinumerous to its cardinal number. (Contributed by Mario Carneiro, 21-Sep-2013.)
(𝐴 ∈ Fin → (card‘𝐴) ≈ 𝐴)
 
Theoremcardnn 9652 The cardinality of a natural number is the number. Corollary 10.23 of [TakeutiZaring] p. 90. (Contributed by Mario Carneiro, 7-Jan-2013.)
(𝐴 ∈ ω → (card‘𝐴) = 𝐴)
 
Theoremcardnueq0 9653 The empty set is the only numerable set with cardinality zero. (Contributed by Mario Carneiro, 7-Jan-2013.)
(𝐴 ∈ dom card → ((card‘𝐴) = ∅ ↔ 𝐴 = ∅))
 
Theoremcardne 9654 No member of a cardinal number of a set is equinumerous to the set. Proposition 10.6(2) of [TakeutiZaring] p. 85. (Contributed by Mario Carneiro, 9-Jan-2013.)
(𝐴 ∈ (card‘𝐵) → ¬ 𝐴𝐵)
 
Theoremcarden2a 9655 If two sets have equal nonzero cardinalities, then they are equinumerous. This assertion and carden2b 9656 are meant to replace carden 10238 in ZF without AC. (Contributed by Mario Carneiro, 9-Jan-2013.)
(((card‘𝐴) = (card‘𝐵) ∧ (card‘𝐴) ≠ ∅) → 𝐴𝐵)
 
Theoremcarden2b 9656 If two sets are equinumerous, then they have equal cardinalities. (This assertion and carden2a 9655 are meant to replace carden 10238 in ZF without AC.) (Contributed by Mario Carneiro, 9-Jan-2013.) (Proof shortened by Mario Carneiro, 27-Apr-2015.)
(𝐴𝐵 → (card‘𝐴) = (card‘𝐵))
 
Theoremcard1 9657* A set has cardinality one iff it is a singleton. (Contributed by Mario Carneiro, 10-Jan-2013.)
((card‘𝐴) = 1o ↔ ∃𝑥 𝐴 = {𝑥})
 
Theoremcardsn 9658 A singleton has cardinality one. (Contributed by Mario Carneiro, 10-Jan-2013.)
(𝐴𝑉 → (card‘{𝐴}) = 1o)
 
Theoremcarddomi2 9659 Two sets have the dominance relationship if their cardinalities have the subset relationship and one is numerable. See also carddom 10241, which uses AC. (Contributed by Mario Carneiro, 11-Jan-2013.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ dom card ∧ 𝐵𝑉) → ((card‘𝐴) ⊆ (card‘𝐵) → 𝐴𝐵))
 
Theoremsdomsdomcardi 9660 A set strictly dominates if its cardinal strictly dominates. (Contributed by Mario Carneiro, 13-Jan-2013.)
(𝐴 ≺ (card‘𝐵) → 𝐴𝐵)
 
Theoremcardlim 9661 An infinite cardinal is a limit ordinal. Equivalent to Exercise 4 of [TakeutiZaring] p. 91. (Contributed by Mario Carneiro, 13-Jan-2013.)
(ω ⊆ (card‘𝐴) ↔ Lim (card‘𝐴))
 
Theoremcardsdomelir 9662 A cardinal strictly dominates its members. Equivalent to Proposition 10.37 of [TakeutiZaring] p. 93. This is half of the assertion cardsdomel 9663 and can be proven without the AC. (Contributed by Mario Carneiro, 15-Jan-2013.)
(𝐴 ∈ (card‘𝐵) → 𝐴𝐵)
 
Theoremcardsdomel 9663 A cardinal strictly dominates its members. Equivalent to Proposition 10.37 of [TakeutiZaring] p. 93. (Contributed by Mario Carneiro, 15-Jan-2013.) (Revised by Mario Carneiro, 4-Jun-2015.)
((𝐴 ∈ On ∧ 𝐵 ∈ dom card) → (𝐴𝐵𝐴 ∈ (card‘𝐵)))
 
Theoremiscard 9664* Two ways to express the property of being a cardinal number. (Contributed by Mario Carneiro, 15-Jan-2013.)
((card‘𝐴) = 𝐴 ↔ (𝐴 ∈ On ∧ ∀𝑥𝐴 𝑥𝐴))
 
Theoremiscard2 9665* Two ways to express the property of being a cardinal number. Definition 8 of [Suppes] p. 225. (Contributed by Mario Carneiro, 15-Jan-2013.)
((card‘𝐴) = 𝐴 ↔ (𝐴 ∈ On ∧ ∀𝑥 ∈ On (𝐴𝑥𝐴𝑥)))
 
Theoremcarddom2 9666 Two numerable sets have the dominance relationship iff their cardinalities have the subset relationship. See also carddom 10241, which uses AC. (Contributed by Mario Carneiro, 11-Jan-2013.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ dom card ∧ 𝐵 ∈ dom card) → ((card‘𝐴) ⊆ (card‘𝐵) ↔ 𝐴𝐵))
 
Theoremharcard 9667 The class of ordinal numbers dominated by a set is a cardinal number. Theorem 59 of [Suppes] p. 228. (Contributed by Mario Carneiro, 20-Jan-2013.) (Revised by Mario Carneiro, 15-May-2015.)
(card‘(har‘𝐴)) = (har‘𝐴)
 
Theoremcardprclem 9668* Lemma for cardprc 9669. (Contributed by Mario Carneiro, 22-Jan-2013.) (Revised by Mario Carneiro, 15-May-2015.)
𝐴 = {𝑥 ∣ (card‘𝑥) = 𝑥}        ¬ 𝐴 ∈ V
 
Theoremcardprc 9669 The class of all cardinal numbers is not a set (i.e. is a proper class). Theorem 19.8 of [Eisenberg] p. 310. In this proof (which does not use AC), we cannot use Cantor's construction canth3 10248 to ensure that there is always a cardinal larger than a given cardinal, but we can use Hartogs' construction hartogs 9233 to construct (effectively) (ℵ‘suc 𝐴) from (ℵ‘𝐴), which achieves the same thing. (Contributed by Mario Carneiro, 22-Jan-2013.)
{𝑥 ∣ (card‘𝑥) = 𝑥} ∉ V
 
Theoremcarduni 9670* The union of a set of cardinals is a cardinal. Theorem 18.14 of [Monk1] p. 133. (Contributed by Mario Carneiro, 20-Jan-2013.)
(𝐴𝑉 → (∀𝑥𝐴 (card‘𝑥) = 𝑥 → (card‘ 𝐴) = 𝐴))
 
Theoremcardiun 9671* The indexed union of a set of cardinals is a cardinal. (Contributed by NM, 3-Nov-2003.)
(𝐴𝑉 → (∀𝑥𝐴 (card‘𝐵) = 𝐵 → (card‘ 𝑥𝐴 𝐵) = 𝑥𝐴 𝐵))
 
Theoremcardennn 9672 If 𝐴 is equinumerous to a natural number, then that number is its cardinal. (Contributed by Mario Carneiro, 11-Jan-2013.)
((𝐴𝐵𝐵 ∈ ω) → (card‘𝐴) = 𝐵)
 
Theoremcardsucinf 9673 The cardinality of the successor of an infinite ordinal. (Contributed by Mario Carneiro, 11-Jan-2013.)
((𝐴 ∈ On ∧ ω ⊆ 𝐴) → (card‘suc 𝐴) = (card‘𝐴))
 
Theoremcardsucnn 9674 The cardinality of the successor of a finite ordinal (natural number). This theorem does not hold for infinite ordinals; see cardsucinf 9673. (Contributed by NM, 7-Nov-2008.)
(𝐴 ∈ ω → (card‘suc 𝐴) = suc (card‘𝐴))
 
Theoremcardom 9675 The set of natural numbers is a cardinal number. Theorem 18.11 of [Monk1] p. 133. (Contributed by NM, 28-Oct-2003.)
(card‘ω) = ω
 
Theoremcarden2 9676 Two numerable sets are equinumerous iff their cardinal numbers are equal. Unlike carden 10238, the Axiom of Choice is not required. (Contributed by Mario Carneiro, 22-Sep-2013.)
((𝐴 ∈ dom card ∧ 𝐵 ∈ dom card) → ((card‘𝐴) = (card‘𝐵) ↔ 𝐴𝐵))
 
Theoremcardsdom2 9677 A numerable set is strictly dominated by another iff their cardinalities are strictly ordered. (Contributed by Stefan O'Rear, 30-Oct-2014.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ dom card ∧ 𝐵 ∈ dom card) → ((card‘𝐴) ∈ (card‘𝐵) ↔ 𝐴𝐵))
 
Theoremdomtri2 9678 Trichotomy of dominance for numerable sets (does not use AC). (Contributed by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ dom card ∧ 𝐵 ∈ dom card) → (𝐴𝐵 ↔ ¬ 𝐵𝐴))
 
Theoremnnsdomel 9679 Strict dominance and elementhood are the same for finite ordinals. (Contributed by Stefan O'Rear, 2-Nov-2014.)
((𝐴 ∈ ω ∧ 𝐵 ∈ ω) → (𝐴𝐵𝐴𝐵))
 
Theoremcardval2 9680* An alternate version of the value of the cardinal number of a set. Compare cardval 10233. This theorem could be used to give a simpler definition of card in place of df-card 9628. It apparently does not occur in the literature. (Contributed by NM, 7-Nov-2003.)
(𝐴 ∈ dom card → (card‘𝐴) = {𝑥 ∈ On ∣ 𝑥𝐴})
 
Theoremisinffi 9681* An infinite set contains subsets equinumerous to every finite set. Extension of isinf 8965 from finite ordinals to all finite sets. (Contributed by Stefan O'Rear, 8-Oct-2014.)
((¬ 𝐴 ∈ Fin ∧ 𝐵 ∈ Fin) → ∃𝑓 𝑓:𝐵1-1𝐴)
 
Theoremfidomtri 9682 Trichotomy of dominance without AC when one set is finite. (Contributed by Stefan O'Rear, 30-Oct-2014.) (Revised by Mario Carneiro, 27-Apr-2015.)
((𝐴 ∈ Fin ∧ 𝐵𝑉) → (𝐴𝐵 ↔ ¬ 𝐵𝐴))
 
Theoremfidomtri2 9683 Trichotomy of dominance without AC when one set is finite. (Contributed by Stefan O'Rear, 30-Oct-2014.) (Revised by Mario Carneiro, 7-May-2015.)
((𝐴𝑉𝐵 ∈ Fin) → (𝐴𝐵 ↔ ¬ 𝐵𝐴))
 
Theoremharsdom 9684 The Hartogs number of a well-orderable set strictly dominates the set. (Contributed by Mario Carneiro, 15-May-2015.)
(𝐴 ∈ dom card → 𝐴 ≺ (har‘𝐴))
 
Theoremonsdom 9685* Any well-orderable set is strictly dominated by an ordinal number. (Contributed by Jeff Hankins, 22-Oct-2009.) (Proof shortened by Mario Carneiro, 15-May-2015.)
(𝐴 ∈ dom card → ∃𝑥 ∈ On 𝐴𝑥)
 
Theoremharval2 9686* An alternate expression for the Hartogs number of a well-orderable set. (Contributed by Mario Carneiro, 15-May-2015.)
(𝐴 ∈ dom card → (har‘𝐴) = {𝑥 ∈ On ∣ 𝐴𝑥})
 
Theoremharsucnn 9687 The next cardinal after a finite ordinal is the successor ordinal. (Contributed by RP, 5-Nov-2023.)
(𝐴 ∈ ω → (har‘𝐴) = suc 𝐴)
 
Theoremcardmin2 9688* The smallest ordinal that strictly dominates a set is a cardinal, if it exists. (Contributed by Mario Carneiro, 2-Feb-2013.)
(∃𝑥 ∈ On 𝐴𝑥 ↔ (card‘ {𝑥 ∈ On ∣ 𝐴𝑥}) = {𝑥 ∈ On ∣ 𝐴𝑥})
 
Theorempm54.43lem 9689* In Theorem *54.43 of [WhiteheadRussell] p. 360, the number 1 is defined as the collection of all sets with cardinality 1 (i.e. all singletons; see card1 9657), so that their 𝐴 ∈ 1 means, in our notation, 𝐴 ∈ {𝑥 ∣ (card‘𝑥) = 1o}. Here we show that this is equivalent to 𝐴 ≈ 1o so that we can use the latter more convenient notation in pm54.43 9690. (Contributed by NM, 4-Nov-2013.)
(𝐴 ≈ 1o𝐴 ∈ {𝑥 ∣ (card‘𝑥) = 1o})
 
Theorempm54.43 9690 Theorem *54.43 of [WhiteheadRussell] p. 360. "From this proposition it will follow, when arithmetical addition has been defined, that 1+1=2." See http://en.wikipedia.org/wiki/Principia_Mathematica#Quotations. This theorem states that two sets of cardinality 1 are disjoint iff their union has cardinality 2.

Whitehead and Russell define 1 as the collection of all sets with cardinality 1 (i.e. all singletons; see card1 9657), so that their 𝐴 ∈ 1 means, in our notation, 𝐴 ∈ {𝑥 ∣ (card‘𝑥) = 1o} which is the same as 𝐴 ≈ 1o by pm54.43lem 9689. We do not have several of their earlier lemmas available (which would otherwise be unused by our different approach to arithmetic), so our proof is longer. (It is also longer because we must show every detail.)

Theorem dju1p1e2 9860 shows the derivation of 1+1=2 for cardinal numbers from this theorem. (Contributed by NM, 4-Apr-2007.)

((𝐴 ≈ 1o𝐵 ≈ 1o) → ((𝐴𝐵) = ∅ ↔ (𝐴𝐵) ≈ 2o))
 
Theorempr2nelem 9691 Lemma for pr2ne 9692. (Contributed by FL, 17-Aug-2008.)
((𝐴𝐶𝐵𝐷𝐴𝐵) → {𝐴, 𝐵} ≈ 2o)
 
Theorempr2ne 9692 If an unordered pair has two elements they are different. (Contributed by FL, 14-Feb-2010.)
((𝐴𝐶𝐵𝐷) → ({𝐴, 𝐵} ≈ 2o𝐴𝐵))
 
Theoremprdom2 9693 An unordered pair has at most two elements. (Contributed by FL, 22-Feb-2011.)
((𝐴𝐶𝐵𝐷) → {𝐴, 𝐵} ≼ 2o)
 
Theoremen2eqpr 9694 Building a set with two elements. (Contributed by FL, 11-Aug-2008.) (Revised by Mario Carneiro, 10-Sep-2015.)
((𝐶 ≈ 2o𝐴𝐶𝐵𝐶) → (𝐴𝐵𝐶 = {𝐴, 𝐵}))
 
Theoremen2eleq 9695 Express a set of pair cardinality as the unordered pair of a given element and the other element. (Contributed by Stefan O'Rear, 22-Aug-2015.)
((𝑋𝑃𝑃 ≈ 2o) → 𝑃 = {𝑋, (𝑃 ∖ {𝑋})})
 
Theoremen2other2 9696 Taking the other element twice in a pair gets back to the original element. (Contributed by Stefan O'Rear, 22-Aug-2015.)
((𝑋𝑃𝑃 ≈ 2o) → (𝑃 ∖ { (𝑃 ∖ {𝑋})}) = 𝑋)
 
Theoremdif1card 9697 The cardinality of a nonempty finite set is one greater than the cardinality of the set with one element removed. (Contributed by Jeff Madsen, 2-Sep-2009.) (Proof shortened by Mario Carneiro, 2-Feb-2013.)
((𝐴 ∈ Fin ∧ 𝑋𝐴) → (card‘𝐴) = suc (card‘(𝐴 ∖ {𝑋})))
 
Theoremleweon 9698* Lexicographical order is a well-ordering of On × On. Proposition 7.56(1) of [TakeutiZaring] p. 54. Note that unlike r0weon 9699, this order is not set-like, as the preimage of ⟨1o, ∅⟩ is the proper class ({∅} × On). (Contributed by Mario Carneiro, 9-Mar-2013.)
𝐿 = {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ (On × On) ∧ 𝑦 ∈ (On × On)) ∧ ((1st𝑥) ∈ (1st𝑦) ∨ ((1st𝑥) = (1st𝑦) ∧ (2nd𝑥) ∈ (2nd𝑦))))}       𝐿 We (On × On)
 
Theoremr0weon 9699* A set-like well-ordering of the class of ordinal pairs. Proposition 7.58(1) of [TakeutiZaring] p. 54. (Contributed by Mario Carneiro, 7-Mar-2013.) (Revised by Mario Carneiro, 26-Jun-2015.)
𝐿 = {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ (On × On) ∧ 𝑦 ∈ (On × On)) ∧ ((1st𝑥) ∈ (1st𝑦) ∨ ((1st𝑥) = (1st𝑦) ∧ (2nd𝑥) ∈ (2nd𝑦))))}    &   𝑅 = {⟨𝑧, 𝑤⟩ ∣ ((𝑧 ∈ (On × On) ∧ 𝑤 ∈ (On × On)) ∧ (((1st𝑧) ∪ (2nd𝑧)) ∈ ((1st𝑤) ∪ (2nd𝑤)) ∨ (((1st𝑧) ∪ (2nd𝑧)) = ((1st𝑤) ∪ (2nd𝑤)) ∧ 𝑧𝐿𝑤)))}       (𝑅 We (On × On) ∧ 𝑅 Se (On × On))
 
Theoreminfxpenlem 9700* Lemma for infxpen 9701. (Contributed by Mario Carneiro, 9-Mar-2013.) (Revised by Mario Carneiro, 26-Jun-2015.)
𝐿 = {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ (On × On) ∧ 𝑦 ∈ (On × On)) ∧ ((1st𝑥) ∈ (1st𝑦) ∨ ((1st𝑥) = (1st𝑦) ∧ (2nd𝑥) ∈ (2nd𝑦))))}    &   𝑅 = {⟨𝑧, 𝑤⟩ ∣ ((𝑧 ∈ (On × On) ∧ 𝑤 ∈ (On × On)) ∧ (((1st𝑧) ∪ (2nd𝑧)) ∈ ((1st𝑤) ∪ (2nd𝑤)) ∨ (((1st𝑧) ∪ (2nd𝑧)) = ((1st𝑤) ∪ (2nd𝑤)) ∧ 𝑧𝐿𝑤)))}    &   𝑄 = (𝑅 ∩ ((𝑎 × 𝑎) × (𝑎 × 𝑎)))    &   (𝜑 ↔ ((𝑎 ∈ On ∧ ∀𝑚𝑎 (ω ⊆ 𝑚 → (𝑚 × 𝑚) ≈ 𝑚)) ∧ (ω ⊆ 𝑎 ∧ ∀𝑚𝑎 𝑚𝑎)))    &   𝑀 = ((1st𝑤) ∪ (2nd𝑤))    &   𝐽 = OrdIso(𝑄, (𝑎 × 𝑎))       ((𝐴 ∈ On ∧ ω ⊆ 𝐴) → (𝐴 × 𝐴) ≈ 𝐴)
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