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| Mirrors > Home > MPE Home > Th. List > Mathboxes > conrel1d | Structured version Visualization version GIF version | ||
| Description: Deduction about composition with a class with no relational content. (Contributed by RP, 24-Dec-2019.) |
| Ref | Expression |
|---|---|
| conrel1d.a | ⊢ (𝜑 → ◡𝐴 = ∅) |
| Ref | Expression |
|---|---|
| conrel1d | ⊢ (𝜑 → (𝐴 ∘ 𝐵) = ∅) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | incom 4138 | . . 3 ⊢ (dom 𝐴 ∩ ran 𝐵) = (ran 𝐵 ∩ dom 𝐴) | |
| 2 | dfdm4 5837 | . . . . 5 ⊢ dom 𝐴 = ran ◡𝐴 | |
| 3 | conrel1d.a | . . . . . . 7 ⊢ (𝜑 → ◡𝐴 = ∅) | |
| 4 | 3 | rneqd 5880 | . . . . . 6 ⊢ (𝜑 → ran ◡𝐴 = ran ∅) |
| 5 | rn0 5868 | . . . . . 6 ⊢ ran ∅ = ∅ | |
| 6 | 4, 5 | eqtrdi 2790 | . . . . 5 ⊢ (𝜑 → ran ◡𝐴 = ∅) |
| 7 | 2, 6 | eqtrid 2786 | . . . 4 ⊢ (𝜑 → dom 𝐴 = ∅) |
| 8 | ineq2 4143 | . . . . 5 ⊢ (dom 𝐴 = ∅ → (ran 𝐵 ∩ dom 𝐴) = (ran 𝐵 ∩ ∅)) | |
| 9 | in0 4323 | . . . . 5 ⊢ (ran 𝐵 ∩ ∅) = ∅ | |
| 10 | 8, 9 | eqtrdi 2790 | . . . 4 ⊢ (dom 𝐴 = ∅ → (ran 𝐵 ∩ dom 𝐴) = ∅) |
| 11 | 7, 10 | syl 17 | . . 3 ⊢ (𝜑 → (ran 𝐵 ∩ dom 𝐴) = ∅) |
| 12 | 1, 11 | eqtrid 2786 | . 2 ⊢ (𝜑 → (dom 𝐴 ∩ ran 𝐵) = ∅) |
| 13 | 12 | coemptyd 14932 | 1 ⊢ (𝜑 → (𝐴 ∘ 𝐵) = ∅) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 = wceq 1547 ∩ cin 3882 ∅c0 4261 ◡ccnv 5617 dom cdm 5618 ran crn 5619 ∘ ccom 5622 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1802 ax-4 1816 ax-5 1917 ax-6 1974 ax-7 2015 ax-8 2121 ax-9 2129 ax-ext 2711 ax-sep 5218 ax-pr 5362 |
| This theorem depends on definitions: df-bi 208 df-an 397 df-or 854 df-3an 1094 df-tru 1550 df-fal 1560 df-ex 1787 df-sb 2074 df-clab 2718 df-cleq 2731 df-clel 2814 df-ral 3054 df-rex 3064 df-rab 3392 df-v 3433 df-dif 3886 df-un 3888 df-in 3890 df-ss 3900 df-nul 4262 df-if 4455 df-sn 4556 df-pr 4558 df-op 4562 df-br 5073 df-opab 5135 df-xp 5624 df-rel 5625 df-cnv 5626 df-co 5627 df-dm 5628 df-rn 5629 df-res 5630 |
| This theorem is referenced by: (None) |
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