Theorem ecun 38427

Description: The union coset of 𝐴. (Contributed by Peter Mazsa, 28-Jan-2026.)

Assertion

Ref	Expression
ecun	⊢ (𝐴 ∈ 𝑉 → [𝐴](𝑅 ∪ 𝑆) = ([𝐴]𝑅 ∪ [𝐴]𝑆))

Proof of Theorem ecun

Dummy variable 𝑥 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		unab 4255	. . 3 ⊢ ({𝑥 ∣ 𝐴𝑅𝑥} ∪ {𝑥 ∣ 𝐴𝑆𝑥}) = {𝑥 ∣ (𝐴𝑅𝑥 ∨ 𝐴𝑆𝑥)}
2	1	a1i 11	. 2 ⊢ (𝐴 ∈ 𝑉 → ({𝑥 ∣ 𝐴𝑅𝑥} ∪ {𝑥 ∣ 𝐴𝑆𝑥}) = {𝑥 ∣ (𝐴𝑅𝑥 ∨ 𝐴𝑆𝑥)})
3		dfec2 8625	. . 3 ⊢ (𝐴 ∈ 𝑉 → [𝐴]𝑅 = {𝑥 ∣ 𝐴𝑅𝑥})
4		dfec2 8625	. . 3 ⊢ (𝐴 ∈ 𝑉 → [𝐴]𝑆 = {𝑥 ∣ 𝐴𝑆𝑥})
5	3, 4	uneq12d 4116	. 2 ⊢ (𝐴 ∈ 𝑉 → ([𝐴]𝑅 ∪ [𝐴]𝑆) = ({𝑥 ∣ 𝐴𝑅𝑥} ∪ {𝑥 ∣ 𝐴𝑆𝑥}))
6		elecALTV 38313	. . . . 5 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝑥 ∈ V) → (𝑥 ∈ [𝐴](𝑅 ∪ 𝑆) ↔ 𝐴(𝑅 ∪ 𝑆)𝑥))
7	6	elvd 3442	. . . 4 ⊢ (𝐴 ∈ 𝑉 → (𝑥 ∈ [𝐴](𝑅 ∪ 𝑆) ↔ 𝐴(𝑅 ∪ 𝑆)𝑥))
8		brun 5140	. . . 4 ⊢ (𝐴(𝑅 ∪ 𝑆)𝑥 ↔ (𝐴𝑅𝑥 ∨ 𝐴𝑆𝑥))
9	7, 8	bitrdi 287	. . 3 ⊢ (𝐴 ∈ 𝑉 → (𝑥 ∈ [𝐴](𝑅 ∪ 𝑆) ↔ (𝐴𝑅𝑥 ∨ 𝐴𝑆𝑥)))
10	9	eqabdv 2864	. 2 ⊢ (𝐴 ∈ 𝑉 → [𝐴](𝑅 ∪ 𝑆) = {𝑥 ∣ (𝐴𝑅𝑥 ∨ 𝐴𝑆𝑥)})
11	2, 5, 10	3eqtr4rd 2777	1 ⊢ (𝐴 ∈ 𝑉 → [𝐴](𝑅 ∪ 𝑆) = ([𝐴]𝑅 ∪ [𝐴]𝑆))

Syntax hints:   → wi 4   ↔ wb 206   ∨ wo 847   = wceq 1541   ∈ wcel 2111  {cab 2709  Vcvv 3436   ∪ cun 3895   class class class wbr 5089  [cec 8620

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2113  ax-9 2121  ax-10 2144  ax-12 2180  ax-ext 2703  ax-sep 5232  ax-nul 5242  ax-pr 5368

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-nf 1785  df-sb 2068  df-clab 2710  df-cleq 2723  df-clel 2806  df-ral 3048  df-rex 3057  df-rab 3396  df-v 3438  df-dif 3900  df-un 3902  df-in 3904  df-ss 3914  df-nul 4281  df-if 4473  df-sn 4574  df-pr 4576  df-op 4580  df-br 5090  df-opab 5152  df-xp 5620  df-cnv 5622  df-dm 5624  df-rn 5625  df-res 5626  df-ima 5627  df-ec 8624

This theorem is referenced by:  ecunres  38428