Theorem elelsuc 6395

Description: Membership in a successor. (Contributed by NM, 20-Jun-1998.)

Assertion

Ref	Expression
elelsuc	⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ suc 𝐵)

Proof of Theorem elelsuc

Step	Hyp	Ref	Expression
1		orc 867	. 2 ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∈ 𝐵 ∨ 𝐴 = 𝐵))
2		elsucg 6390	. 2 ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∈ suc 𝐵 ↔ (𝐴 ∈ 𝐵 ∨ 𝐴 = 𝐵)))
3	1, 2	mpbird 257	1 ⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ suc 𝐵)

Syntax hints:   → wi 4   ∨ wo 847   = wceq 1540   ∈ wcel 2109  suc csuc 6322

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2701

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-tru 1543  df-ex 1780  df-sb 2066  df-clab 2708  df-cleq 2721  df-clel 2803  df-v 3446  df-un 3916  df-sn 4586  df-suc 6326

This theorem is referenced by:  suctr  6408  pssnn  9109  ttrcltr  9645  ttrclss  9649  ttrclselem2  9655  pwsdompw  10132  fin1a2lem4  10332  grur1a  10748  bnj570  34868  satom  35316  satfv0  35318  satfvsuc  35321  satf00  35334  satf0suc  35336  sat1el2xp  35339  fmla  35341  fmla0  35342  fmlasuc0  35344  satfdmfmla  35360  finxpsuclem  37358