Theorem elelsuc 6398

Description: Membership in a successor. (Contributed by NM, 20-Jun-1998.)

Assertion

Ref	Expression
elelsuc	⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ suc 𝐵)

Proof of Theorem elelsuc

Step	Hyp	Ref	Expression
1		orc 868	. 2 ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∈ 𝐵 ∨ 𝐴 = 𝐵))
2		elsucg 6393	. 2 ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∈ suc 𝐵 ↔ (𝐴 ∈ 𝐵 ∨ 𝐴 = 𝐵)))
3	1, 2	mpbird 257	1 ⊢ (𝐴 ∈ 𝐵 → 𝐴 ∈ suc 𝐵)

Syntax hints:   → wi 4   ∨ wo 848   = wceq 1542   ∈ wcel 2114  suc csuc 6325

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2708

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-tru 1545  df-ex 1782  df-sb 2069  df-clab 2715  df-cleq 2728  df-clel 2811  df-v 3431  df-un 3894  df-sn 4568  df-suc 6329

This theorem is referenced by:  suctr  6411  pssnn  9103  ttrcltr  9637  ttrclss  9641  ttrclselem2  9647  pwsdompw  10125  fin1a2lem4  10325  grur1a  10742  bnj570  35047  fineqvnttrclselem3  35267  satom  35538  satfv0  35540  satfvsuc  35543  satf00  35556  satf0suc  35558  sat1el2xp  35561  fmla  35563  fmla0  35564  fmlasuc0  35566  satfdmfmla  35582  finxpsuclem  37713