Theorem fveqres 6925

Description: Equal values imply equal values in a restriction. (Contributed by NM, 13-Nov-1995.)

Assertion

Ref	Expression
fveqres	⊢ ((𝐹‘𝐴) = (𝐺‘𝐴) → ((𝐹 ↾ 𝐵)‘𝐴) = ((𝐺 ↾ 𝐵)‘𝐴))

Proof of Theorem fveqres

Step	Hyp	Ref	Expression
1		fvres 6900	. . . 4 ⊢ (𝐴 ∈ 𝐵 → ((𝐹 ↾ 𝐵)‘𝐴) = (𝐹‘𝐴))
2		fvres 6900	. . . 4 ⊢ (𝐴 ∈ 𝐵 → ((𝐺 ↾ 𝐵)‘𝐴) = (𝐺‘𝐴))
3	1, 2	eqeq12d 2778	. . 3 ⊢ (𝐴 ∈ 𝐵 → (((𝐹 ↾ 𝐵)‘𝐴) = ((𝐺 ↾ 𝐵)‘𝐴) ↔ (𝐹‘𝐴) = (𝐺‘𝐴)))
4	3	biimprd 251	. 2 ⊢ (𝐴 ∈ 𝐵 → ((𝐹‘𝐴) = (𝐺‘𝐴) → ((𝐹 ↾ 𝐵)‘𝐴) = ((𝐺 ↾ 𝐵)‘𝐴)))
5		nfvres 6919	. . . 4 ⊢ (¬ 𝐴 ∈ 𝐵 → ((𝐹 ↾ 𝐵)‘𝐴) = ∅)
6		nfvres 6919	. . . 4 ⊢ (¬ 𝐴 ∈ 𝐵 → ((𝐺 ↾ 𝐵)‘𝐴) = ∅)
7	5, 6	eqtr4d 2800	. . 3 ⊢ (¬ 𝐴 ∈ 𝐵 → ((𝐹 ↾ 𝐵)‘𝐴) = ((𝐺 ↾ 𝐵)‘𝐴))
8	7	a1d 26	. 2 ⊢ (¬ 𝐴 ∈ 𝐵 → ((𝐹‘𝐴) = (𝐺‘𝐴) → ((𝐹 ↾ 𝐵)‘𝐴) = ((𝐺 ↾ 𝐵)‘𝐴)))
9	4, 8	pm2.61i 184	1 ⊢ ((𝐹‘𝐴) = (𝐺‘𝐴) → ((𝐹 ↾ 𝐵)‘𝐴) = ((𝐺 ↾ 𝐵)‘𝐴))

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   = wceq 1569   ∈ wcel 2142  ∅c0 4285   ↾ cres 5662  ‘cfv 6536

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5256  ax-nul 5268  ax-pr 5403

This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1104  df-tru 1572  df-fal 1582  df-ex 1809  df-sb 2096  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-ral 3079  df-rex 3089  df-rab 3416  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4487  df-sn 4589  df-pr 4591  df-op 4595  df-uni 4872  df-br 5109  df-opab 5173  df-xp 5666  df-dm 5670  df-res 5672  df-iota 6492  df-fv 6544

This theorem is used by:  fvresex  7955