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Theorem 1st2ndbr 5970
Description: Express an element of a relation as a relationship between first and second components. (Contributed by Mario Carneiro, 22-Jun-2016.)
Assertion
Ref Expression
1st2ndbr ((Rel 𝐵𝐴𝐵) → (1st𝐴)𝐵(2nd𝐴))

Proof of Theorem 1st2ndbr
StepHypRef Expression
1 1st2nd 5967 . . 3 ((Rel 𝐵𝐴𝐵) → 𝐴 = ⟨(1st𝐴), (2nd𝐴)⟩)
2 simpr 109 . . 3 ((Rel 𝐵𝐴𝐵) → 𝐴𝐵)
31, 2eqeltrrd 2166 . 2 ((Rel 𝐵𝐴𝐵) → ⟨(1st𝐴), (2nd𝐴)⟩ ∈ 𝐵)
4 df-br 3854 . 2 ((1st𝐴)𝐵(2nd𝐴) ↔ ⟨(1st𝐴), (2nd𝐴)⟩ ∈ 𝐵)
53, 4sylibr 133 1 ((Rel 𝐵𝐴𝐵) → (1st𝐴)𝐵(2nd𝐴))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 103  wcel 1439  cop 3455   class class class wbr 3853  Rel wrel 4459  cfv 5030  1st c1st 5925  2nd c2nd 5926
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 666  ax-5 1382  ax-7 1383  ax-gen 1384  ax-ie1 1428  ax-ie2 1429  ax-8 1441  ax-10 1442  ax-11 1443  ax-i12 1444  ax-bndl 1445  ax-4 1446  ax-13 1450  ax-14 1451  ax-17 1465  ax-i9 1469  ax-ial 1473  ax-i5r 1474  ax-ext 2071  ax-sep 3965  ax-pow 4017  ax-pr 4047  ax-un 4271
This theorem depends on definitions:  df-bi 116  df-3an 927  df-tru 1293  df-nf 1396  df-sb 1694  df-eu 1952  df-mo 1953  df-clab 2076  df-cleq 2082  df-clel 2085  df-nfc 2218  df-ral 2365  df-rex 2366  df-v 2624  df-sbc 2844  df-un 3006  df-in 3008  df-ss 3015  df-pw 3437  df-sn 3458  df-pr 3459  df-op 3461  df-uni 3662  df-br 3854  df-opab 3908  df-mpt 3909  df-id 4131  df-xp 4460  df-rel 4461  df-cnv 4462  df-co 4463  df-dm 4464  df-rn 4465  df-iota 4995  df-fun 5032  df-fv 5038  df-1st 5927  df-2nd 5928
This theorem is referenced by: (None)
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