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Theorem xpcanm 4883
Description: Cancellation law for cross-product. (Contributed by Jim Kingdon, 14-Dec-2018.)
Assertion
Ref Expression
xpcanm (∃𝑥 𝑥𝐶 → ((𝐶 × 𝐴) = (𝐶 × 𝐵) ↔ 𝐴 = 𝐵))
Distinct variable group:   𝑥,𝐶
Allowed substitution hints:   𝐴(𝑥)   𝐵(𝑥)

Proof of Theorem xpcanm
StepHypRef Expression
1 ssxp2 4881 . . 3 (∃𝑥 𝑥𝐶 → ((𝐶 × 𝐴) ⊆ (𝐶 × 𝐵) ↔ 𝐴𝐵))
2 ssxp2 4881 . . 3 (∃𝑥 𝑥𝐶 → ((𝐶 × 𝐵) ⊆ (𝐶 × 𝐴) ↔ 𝐵𝐴))
31, 2anbi12d 458 . 2 (∃𝑥 𝑥𝐶 → (((𝐶 × 𝐴) ⊆ (𝐶 × 𝐵) ∧ (𝐶 × 𝐵) ⊆ (𝐶 × 𝐴)) ↔ (𝐴𝐵𝐵𝐴)))
4 eqss 3041 . 2 ((𝐶 × 𝐴) = (𝐶 × 𝐵) ↔ ((𝐶 × 𝐴) ⊆ (𝐶 × 𝐵) ∧ (𝐶 × 𝐵) ⊆ (𝐶 × 𝐴)))
5 eqss 3041 . 2 (𝐴 = 𝐵 ↔ (𝐴𝐵𝐵𝐴))
63, 4, 53bitr4g 222 1 (∃𝑥 𝑥𝐶 → ((𝐶 × 𝐴) = (𝐶 × 𝐵) ↔ 𝐴 = 𝐵))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 103  wb 104   = wceq 1290  wex 1427  wcel 1439  wss 3000   × cxp 4450
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 666  ax-5 1382  ax-7 1383  ax-gen 1384  ax-ie1 1428  ax-ie2 1429  ax-8 1441  ax-10 1442  ax-11 1443  ax-i12 1444  ax-bndl 1445  ax-4 1446  ax-14 1451  ax-17 1465  ax-i9 1469  ax-ial 1473  ax-i5r 1474  ax-ext 2071  ax-sep 3963  ax-pow 4015  ax-pr 4045
This theorem depends on definitions:  df-bi 116  df-3an 927  df-tru 1293  df-nf 1396  df-sb 1694  df-eu 1952  df-mo 1953  df-clab 2076  df-cleq 2082  df-clel 2085  df-nfc 2218  df-ral 2365  df-rex 2366  df-v 2622  df-un 3004  df-in 3006  df-ss 3013  df-pw 3435  df-sn 3456  df-pr 3457  df-op 3459  df-br 3852  df-opab 3906  df-xp 4458  df-rel 4459  df-cnv 4460  df-dm 4462  df-rn 4463
This theorem is referenced by: (None)
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