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Theorem csbov 7437
Description: Move class substitution in and out of an operation. (Contributed by NM, 23-Aug-2018.)
Assertion
Ref Expression
csbov 𝐴 / 𝑥(𝐵𝐹𝐶) = (𝐵𝐴 / 𝑥𝐹𝐶)
Distinct variable groups:   𝑥,𝐵   𝑥,𝐶
Allowed substitution hints:   𝐴(𝑥)   𝐹(𝑥)

Proof of Theorem csbov
StepHypRef Expression
1 csbov123 7436 . 2 𝐴 / 𝑥(𝐵𝐹𝐶) = (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐹𝐴 / 𝑥𝐶)
2 csbconstg 3871 . . . 4 (𝐴 ∈ V → 𝐴 / 𝑥𝐵 = 𝐵)
3 csbconstg 3871 . . . 4 (𝐴 ∈ V → 𝐴 / 𝑥𝐶 = 𝐶)
42, 3oveq12d 7410 . . 3 (𝐴 ∈ V → (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐹𝐴 / 𝑥𝐶) = (𝐵𝐴 / 𝑥𝐹𝐶))
5 0fv 6904 . . . . 5 (∅‘⟨𝐵, 𝐶⟩) = ∅
6 df-ov 7395 . . . . 5 (𝐵𝐶) = (∅‘⟨𝐵, 𝐶⟩)
7 0ov 7429 . . . . 5 (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶) = ∅
85, 6, 73eqtr4ri 2795 . . . 4 (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶) = (𝐵𝐶)
9 csbprc 4362 . . . . 5 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
109oveqd 7409 . . . 4 𝐴 ∈ V → (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐹𝐴 / 𝑥𝐶) = (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶))
119oveqd 7409 . . . 4 𝐴 ∈ V → (𝐵𝐴 / 𝑥𝐹𝐶) = (𝐵𝐶))
128, 10, 113eqtr4a 2822 . . 3 𝐴 ∈ V → (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐹𝐴 / 𝑥𝐶) = (𝐵𝐴 / 𝑥𝐹𝐶))
134, 12pm2.61i 183 . 2 (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐹𝐴 / 𝑥𝐶) = (𝐵𝐴 / 𝑥𝐹𝐶)
141, 13eqtri 2784 1 𝐴 / 𝑥(𝐵𝐹𝐶) = (𝐵𝐴 / 𝑥𝐹𝐶)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3   = wceq 1559  wcel 2141  Vcvv 3453  csb 3852  c0 4285  cop 4587  cfv 6517  (class class class)co 7392
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-8 2143  ax-9 2151  ax-10 2174  ax-11 2190  ax-12 2211  ax-ext 2733  ax-nul 5255  ax-pr 5389
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1099  df-tru 1562  df-fal 1572  df-ex 1799  df-nf 1803  df-sb 2090  df-mo 2565  df-eu 2595  df-clab 2740  df-cleq 2753  df-clel 2836  df-nfc 2910  df-ne 2957  df-ral 3076  df-rex 3086  df-rab 3414  df-v 3455  df-sbc 3745  df-csb 3853  df-dif 3907  df-un 3909  df-ss 3921  df-nul 4286  df-if 4480  df-sn 4582  df-pr 4584  df-op 4588  df-uni 4865  df-br 5100  df-dm 5655  df-iota 6473  df-fv 6525  df-ov 7395
This theorem is referenced by:  mptcoe1matfsupp  22842  mp2pm2mplem4  22849
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