Users' Mathboxes Mathbox for Peter Mazsa < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  disjeq Structured version   Visualization version   GIF version

Theorem disjeq 39173
Description: Equality theorem for disjoints. (Contributed by Peter Mazsa, 22-Sep-2021.)
Assertion
Ref Expression
disjeq (𝐴 = 𝐵 → ( Disj 𝐴 ↔ Disj 𝐵))

Proof of Theorem disjeq
StepHypRef Expression
1 eqimss2 3982 . . 3 (𝐴 = 𝐵𝐵𝐴)
21disjssd 39172 . 2 (𝐴 = 𝐵 → ( Disj 𝐴 → Disj 𝐵))
3 eqimss 3981 . . 3 (𝐴 = 𝐵𝐴𝐵)
43disjssd 39172 . 2 (𝐴 = 𝐵 → ( Disj 𝐵 → Disj 𝐴))
52, 4impbid 212 1 (𝐴 = 𝐵 → ( Disj 𝐴 ↔ Disj 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206   = wceq 1542   Disj wdisjALTV 38558
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-11 2163  ax-ext 2709  ax-sep 5232  ax-pr 5372
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-ral 3053  df-rex 3063  df-rab 3391  df-v 3432  df-dif 3893  df-un 3895  df-in 3897  df-ss 3907  df-nul 4275  df-if 4468  df-sn 4569  df-pr 4571  df-op 4575  df-br 5087  df-opab 5149  df-id 5521  df-xp 5632  df-rel 5633  df-cnv 5634  df-co 5635  df-dm 5636  df-rn 5637  df-res 5638  df-coss 38840  df-cnvrefrel 38946  df-funALTV 39106  df-disjALTV 39129
This theorem is referenced by:  disjeqi  39174  disjeqd  39175  disjdmqseqeq1  39176
  Copyright terms: Public domain W3C validator