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Theorem dmqseqim2 39109
Description: Lemma for erimeq2 39130. (Contributed by Peter Mazsa, 29-Dec-2021.)
Assertion
Ref Expression
dmqseqim2 (𝑅𝑉 → (Rel 𝑅 → ((dom 𝑅 / 𝑅) = 𝐴 → (𝐵 ∈ ran 𝑅𝐵 𝐴))))

Proof of Theorem dmqseqim2
StepHypRef Expression
1 dmqseqim 39108 . 2 (𝑅𝑉 → (Rel 𝑅 → ((dom 𝑅 / 𝑅) = 𝐴 → ran 𝑅 = 𝐴)))
2 eleq2 2828 . 2 (ran 𝑅 = 𝐴 → (𝐵 ∈ ran 𝑅𝐵 𝐴))
31, 2syl8 76 1 (𝑅𝑉 → (Rel 𝑅 → ((dom 𝑅 / 𝑅) = 𝐴 → (𝐵 ∈ ran 𝑅𝐵 𝐴))))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 207   = wceq 1547  wcel 2119   cuni 4838  dom cdm 5618  ran crn 5619  Rel wrel 5623   / cqs 8632
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-11 2168  ax-ext 2711  ax-sep 5218  ax-pr 5362  ax-un 7678
This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-3an 1094  df-tru 1550  df-fal 1560  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-clel 2814  df-ral 3054  df-rex 3064  df-rab 3392  df-v 3433  df-dif 3886  df-un 3888  df-in 3890  df-ss 3900  df-nul 4262  df-if 4455  df-sn 4556  df-pr 4558  df-op 4562  df-uni 4839  df-iun 4923  df-br 5073  df-opab 5135  df-xp 5624  df-rel 5625  df-cnv 5626  df-dm 5628  df-rn 5629  df-res 5630  df-ima 5631  df-ec 8635  df-qs 8639
This theorem is referenced by:  erimeq2  39130
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