Theorem relbrcnv 6107

Description: When 𝑅 is a relation, the sethood assumptions on brcnv 5866 can be omitted. (Contributed by Mario Carneiro, 28-Apr-2015.)

Hypothesis

Ref	Expression
relbrcnv.1	⊢ Rel 𝑅

Assertion

Ref	Expression
relbrcnv	⊢ (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴)

Proof of Theorem relbrcnv

Step	Hyp	Ref	Expression
1		relbrcnv.1	. 2 ⊢ Rel 𝑅
2		relbrcnvg 6105	. 2 ⊢ (Rel 𝑅 → (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴))
3	1, 2	ax-mp 5	1 ⊢ (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴)

This proof depends on syntax axioms:   ↔ wb 209   class class class wbr 5107  ^◡ccnv 5658  Rel wrel 5664

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734  ax-sep 5255  ax-pr 5402

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-ral 3079  df-rex 3089  df-rab 3415  df-v 3455  df-dif 3905  df-un 3907  df-in 3909  df-ss 3919  df-nul 4283  df-if 4486  df-sn 4588  df-pr 4590  df-op 4594  df-br 5108  df-opab 5172  df-xp 5665  df-rel 5666  df-cnv 5667

This theorem is used by:  compssiso  10379  fneval  36958  br1cnvinxp  38994  brcnvep  39005  brid  39047  brcnvrabga  39077  br1cnvxrn2  39154  br1cnvssrres  39320  brcnvssr  39321  brco2f1o  44859  brco3f1o  44860  neicvgnvor  44943