Theorem ecqs 6831

Description: Equivalence class in terms of quotient set. (Contributed by NM, 29-Jan-1999.)

Hypothesis

Ref	Expression
ecqs.1	⊢ 𝑅 ∈ V

Assertion

Ref	Expression
ecqs	⊢ [𝐴]𝑅 = ∪ ({𝐴} / 𝑅)

Proof of Theorem ecqs

Step	Hyp	Ref	Expression
1		df-ec 6769	. 2 ⊢ [𝐴]𝑅 = (𝑅 “ {𝐴})
2		ecqs.1	. . 3 ⊢ 𝑅 ∈ V
3		uniqs 6827	. . 3 ⊢ (𝑅 ∈ V → ∪ ({𝐴} / 𝑅) = (𝑅 “ {𝐴}))
4	2, 3	ax-mp 5	. 2 ⊢ ∪ ({𝐴} / 𝑅) = (𝑅 “ {𝐴})
5	1, 4	eqtr4i 2256	1 ⊢ [𝐴]𝑅 = ∪ ({𝐴} / 𝑅)

Syntax hints:   = wceq 1398   ∈ wcel 2203  Vcvv 2813  {csn 3689  ∪ cuni 3914   “ cima 4752  [cec 6765   / cqs 6766

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-13 2205  ax-14 2206  ax-ext 2214  ax-sep 4228  ax-pow 4287  ax-pr 4322  ax-un 4554

This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-nf 1510  df-sb 1812  df-eu 2083  df-mo 2084  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-ral 2525  df-rex 2526  df-v 2815  df-un 3215  df-in 3217  df-ss 3224  df-pw 3671  df-sn 3695  df-pr 3696  df-op 3698  df-uni 3915  df-iun 3993  df-br 4110  df-opab 4172  df-xp 4755  df-cnv 4757  df-dm 4759  df-rn 4760  df-res 4761  df-ima 4762  df-ec 6769  df-qs 6773

This theorem is referenced by: (None)