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Theorem inimass 5002
Description: The image of an intersection. (Contributed by Thierry Arnoux, 16-Dec-2017.)
Assertion
Ref Expression
inimass ((𝐴𝐵) “ 𝐶) ⊆ ((𝐴𝐶) ∩ (𝐵𝐶))

Proof of Theorem inimass
StepHypRef Expression
1 rnin 4995 . 2 ran ((𝐴𝐶) ∩ (𝐵𝐶)) ⊆ (ran (𝐴𝐶) ∩ ran (𝐵𝐶))
2 df-ima 4599 . . 3 ((𝐴𝐵) “ 𝐶) = ran ((𝐴𝐵) ↾ 𝐶)
3 resindir 4882 . . . 4 ((𝐴𝐵) ↾ 𝐶) = ((𝐴𝐶) ∩ (𝐵𝐶))
43rneqi 4814 . . 3 ran ((𝐴𝐵) ↾ 𝐶) = ran ((𝐴𝐶) ∩ (𝐵𝐶))
52, 4eqtri 2178 . 2 ((𝐴𝐵) “ 𝐶) = ran ((𝐴𝐶) ∩ (𝐵𝐶))
6 df-ima 4599 . . 3 (𝐴𝐶) = ran (𝐴𝐶)
7 df-ima 4599 . . 3 (𝐵𝐶) = ran (𝐵𝐶)
86, 7ineq12i 3306 . 2 ((𝐴𝐶) ∩ (𝐵𝐶)) = (ran (𝐴𝐶) ∩ ran (𝐵𝐶))
91, 5, 83sstr4i 3169 1 ((𝐴𝐵) “ 𝐶) ⊆ ((𝐴𝐶) ∩ (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  cin 3101  wss 3102  ran crn 4587  cres 4588  cima 4589
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 699  ax-5 1427  ax-7 1428  ax-gen 1429  ax-ie1 1473  ax-ie2 1474  ax-8 1484  ax-10 1485  ax-11 1486  ax-i12 1487  ax-bndl 1489  ax-4 1490  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-14 2131  ax-ext 2139  ax-sep 4082  ax-pow 4135  ax-pr 4169
This theorem depends on definitions:  df-bi 116  df-3an 965  df-tru 1338  df-nf 1441  df-sb 1743  df-clab 2144  df-cleq 2150  df-clel 2153  df-nfc 2288  df-ral 2440  df-rex 2441  df-v 2714  df-un 3106  df-in 3108  df-ss 3115  df-pw 3545  df-sn 3566  df-pr 3567  df-op 3569  df-br 3966  df-opab 4026  df-xp 4592  df-rel 4593  df-cnv 4594  df-dm 4596  df-rn 4597  df-res 4598  df-ima 4599
This theorem is referenced by: (None)
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