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Theorem cocnv 35163
Description: Composition with a function and then with the converse. (Contributed by Jeff Madsen, 2-Sep-2009.)
Assertion
Ref Expression
cocnv ((Fun 𝐹 ∧ Fun 𝐺) → ((𝐹𝐺) ∘ 𝐺) = (𝐹 ↾ ran 𝐺))

Proof of Theorem cocnv
StepHypRef Expression
1 coass 6085 . 2 ((𝐹𝐺) ∘ 𝐺) = (𝐹 ∘ (𝐺𝐺))
2 funcocnv2 6614 . . . . 5 (Fun 𝐺 → (𝐺𝐺) = ( I ↾ ran 𝐺))
32adantl 485 . . . 4 ((Fun 𝐹 ∧ Fun 𝐺) → (𝐺𝐺) = ( I ↾ ran 𝐺))
43coeq2d 5697 . . 3 ((Fun 𝐹 ∧ Fun 𝐺) → (𝐹 ∘ (𝐺𝐺)) = (𝐹 ∘ ( I ↾ ran 𝐺)))
5 resco 6070 . . . 4 ((𝐹 ∘ I ) ↾ ran 𝐺) = (𝐹 ∘ ( I ↾ ran 𝐺))
6 funrel 6341 . . . . . . 7 (Fun 𝐹 → Rel 𝐹)
7 coi1 6082 . . . . . . 7 (Rel 𝐹 → (𝐹 ∘ I ) = 𝐹)
86, 7syl 17 . . . . . 6 (Fun 𝐹 → (𝐹 ∘ I ) = 𝐹)
98reseq1d 5817 . . . . 5 (Fun 𝐹 → ((𝐹 ∘ I ) ↾ ran 𝐺) = (𝐹 ↾ ran 𝐺))
109adantr 484 . . . 4 ((Fun 𝐹 ∧ Fun 𝐺) → ((𝐹 ∘ I ) ↾ ran 𝐺) = (𝐹 ↾ ran 𝐺))
115, 10syl5eqr 2847 . . 3 ((Fun 𝐹 ∧ Fun 𝐺) → (𝐹 ∘ ( I ↾ ran 𝐺)) = (𝐹 ↾ ran 𝐺))
124, 11eqtrd 2833 . 2 ((Fun 𝐹 ∧ Fun 𝐺) → (𝐹 ∘ (𝐺𝐺)) = (𝐹 ↾ ran 𝐺))
131, 12syl5eq 2845 1 ((Fun 𝐹 ∧ Fun 𝐺) → ((𝐹𝐺) ∘ 𝐺) = (𝐹 ↾ ran 𝐺))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 399   = wceq 1538   I cid 5424  ccnv 5518  ran crn 5520  cres 5521  ccom 5523  Rel wrel 5524  Fun wfun 6318
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2113  ax-9 2121  ax-10 2142  ax-11 2158  ax-12 2175  ax-ext 2770  ax-sep 5167  ax-nul 5174  ax-pr 5295
This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-3an 1086  df-tru 1541  df-ex 1782  df-nf 1786  df-sb 2070  df-mo 2598  df-eu 2629  df-clab 2777  df-cleq 2791  df-clel 2870  df-nfc 2938  df-ral 3111  df-rex 3112  df-rab 3115  df-v 3443  df-dif 3884  df-un 3886  df-in 3888  df-ss 3898  df-nul 4244  df-if 4426  df-sn 4526  df-pr 4528  df-op 4532  df-br 5031  df-opab 5093  df-id 5425  df-xp 5525  df-rel 5526  df-cnv 5527  df-co 5528  df-dm 5529  df-rn 5530  df-res 5531  df-fun 6326
This theorem is referenced by: (None)
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