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Theorem coxp 49764
Description: Composition with a Cartesian product. (Contributed by Zhi Wang, 6-Oct-2025.)
Assertion
Ref Expression
coxp (𝐴 ∘ (𝐵 × 𝐶)) = (𝐵 × (𝐴𝐶))

Proof of Theorem coxp
Dummy variables 𝑥 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 relco 6104 . 2 Rel (𝐴 ∘ (𝐵 × 𝐶))
2 relxp 5673 . 2 Rel (𝐵 × (𝐴𝐶))
3 brxp 5704 . . . . . 6 (𝑥(𝐵 × 𝐶)𝑧 ↔ (𝑥𝐵𝑧𝐶))
43anbi1i 636 . . . . 5 ((𝑥(𝐵 × 𝐶)𝑧𝑧𝐴𝑦) ↔ ((𝑥𝐵𝑧𝐶) ∧ 𝑧𝐴𝑦))
5 anass 474 . . . . 5 (((𝑥𝐵𝑧𝐶) ∧ 𝑧𝐴𝑦) ↔ (𝑥𝐵 ∧ (𝑧𝐶𝑧𝐴𝑦)))
64, 5bitri 278 . . . 4 ((𝑥(𝐵 × 𝐶)𝑧𝑧𝐴𝑦) ↔ (𝑥𝐵 ∧ (𝑧𝐶𝑧𝐴𝑦)))
76exbii 1881 . . 3 (∃𝑧(𝑥(𝐵 × 𝐶)𝑧𝑧𝐴𝑦) ↔ ∃𝑧(𝑥𝐵 ∧ (𝑧𝐶𝑧𝐴𝑦)))
8 vex 3454 . . . 4 𝑥 ∈ V
9 vex 3454 . . . 4 𝑦 ∈ V
108, 9opelco 5851 . . 3 (⟨𝑥, 𝑦⟩ ∈ (𝐴 ∘ (𝐵 × 𝐶)) ↔ ∃𝑧(𝑥(𝐵 × 𝐶)𝑧𝑧𝐴𝑦))
119elima2 6062 . . . . 5 (𝑦 ∈ (𝐴𝐶) ↔ ∃𝑧(𝑧𝐶𝑧𝐴𝑦))
1211anbi2i 635 . . . 4 ((𝑥𝐵𝑦 ∈ (𝐴𝐶)) ↔ (𝑥𝐵 ∧ ∃𝑧(𝑧𝐶𝑧𝐴𝑦)))
13 opelxp 5691 . . . 4 (⟨𝑥, 𝑦⟩ ∈ (𝐵 × (𝐴𝐶)) ↔ (𝑥𝐵𝑦 ∈ (𝐴𝐶)))
14 19.42v 1986 . . . 4 (∃𝑧(𝑥𝐵 ∧ (𝑧𝐶𝑧𝐴𝑦)) ↔ (𝑥𝐵 ∧ ∃𝑧(𝑧𝐶𝑧𝐴𝑦)))
1512, 13, 143bitr4i 306 . . 3 (⟨𝑥, 𝑦⟩ ∈ (𝐵 × (𝐴𝐶)) ↔ ∃𝑧(𝑥𝐵 ∧ (𝑧𝐶𝑧𝐴𝑦)))
167, 10, 153bitr4i 306 . 2 (⟨𝑥, 𝑦⟩ ∈ (𝐴 ∘ (𝐵 × 𝐶)) ↔ ⟨𝑥, 𝑦⟩ ∈ (𝐵 × (𝐴𝐶)))
171, 2, 16eqrelriiv 5770 1 (𝐴 ∘ (𝐵 × 𝐶)) = (𝐵 × (𝐴𝐶))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wa 401   = wceq 1570  wex 1812  wcel 2145  cop 4590   class class class wbr 5103   × cxp 5653  cima 5658  ccom 5659
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5251  ax-pr 5398
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668
This theorem is used by:  cosn  49765
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