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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | lcoval 48801* | The value of a linear combination. (Contributed by AV, 5-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) ⇒ ⊢ ((𝑀 ∈ 𝑋 ∧ 𝑉 ∈ 𝒫 𝐵) → (𝐶 ∈ (𝑀 LinCo 𝑉) ↔ (𝐶 ∈ 𝐵 ∧ ∃𝑠 ∈ (𝑅 ↑m 𝑉)(𝑠 finSupp (0g‘𝑆) ∧ 𝐶 = (𝑠( linC ‘𝑀)𝑉))))) | ||
| Theorem | lincfsuppcl 48802 | A linear combination of vectors (with finite support) is a vector. (Contributed by AV, 25-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝑆 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑀 ∈ LMod ∧ (𝑉 ∈ 𝑊 ∧ 𝑉 ⊆ 𝐵) ∧ (𝐹 ∈ (𝑆 ↑m 𝑉) ∧ 𝐹 finSupp 0 )) → (𝐹( linC ‘𝑀)𝑉) ∈ 𝐵) | ||
| Theorem | linccl 48803 | A linear combination of vectors is a vector. (Contributed by AV, 31-Mar-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Base‘(Scalar‘𝑀)) ⇒ ⊢ ((𝑀 ∈ LMod ∧ (𝑉 ∈ Fin ∧ 𝑉 ⊆ 𝐵 ∧ 𝑆 ∈ (𝑅 ↑m 𝑉))) → (𝑆( linC ‘𝑀)𝑉) ∈ 𝐵) | ||
| Theorem | lincval0 48804 | The value of an empty linear combination. (Contributed by AV, 12-Apr-2019.) |
| ⊢ (𝑀 ∈ 𝑋 → (∅( linC ‘𝑀)∅) = (0g‘𝑀)) | ||
| Theorem | lincvalsng 48805 | The linear combination over a singleton. (Contributed by AV, 25-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) & ⊢ · = ( ·𝑠 ‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝐵 ∧ 𝑌 ∈ 𝑅) → ({〈𝑉, 𝑌〉} ( linC ‘𝑀){𝑉}) = (𝑌 · 𝑉)) | ||
| Theorem | lincvalsn 48806 | The linear combination over a singleton. (Contributed by AV, 12-Apr-2019.) (Proof shortened by AV, 25-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) & ⊢ · = ( ·𝑠 ‘𝑀) & ⊢ 𝐹 = {〈𝑉, 𝑌〉} ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝐵 ∧ 𝑌 ∈ 𝑅) → (𝐹( linC ‘𝑀){𝑉}) = (𝑌 · 𝑉)) | ||
| Theorem | lincvalpr 48807 | The linear combination over an unordered pair. (Contributed by AV, 16-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) & ⊢ · = ( ·𝑠 ‘𝑀) & ⊢ + = (+g‘𝑀) & ⊢ 𝐹 = {〈𝑉, 𝑋〉, 〈𝑊, 𝑌〉} ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ≠ 𝑊) ∧ (𝑉 ∈ 𝐵 ∧ 𝑋 ∈ 𝑅) ∧ (𝑊 ∈ 𝐵 ∧ 𝑌 ∈ 𝑅)) → (𝐹( linC ‘𝑀){𝑉, 𝑊}) = ((𝑋 · 𝑉) + (𝑌 · 𝑊))) | ||
| Theorem | lincval1 48808 | The linear combination over a singleton mapping to 0. (Contributed by AV, 12-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) & ⊢ 𝐹 = {〈𝑉, (0g‘𝑆)〉} ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝐵) → (𝐹( linC ‘𝑀){𝑉}) = (0g‘𝑀)) | ||
| Theorem | lcosn0 48809 | Properties of a linear combination over a singleton mapping to 0. (Contributed by AV, 12-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) & ⊢ 𝐹 = {〈𝑉, (0g‘𝑆)〉} ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝐵) → (𝐹 ∈ (𝑅 ↑m {𝑉}) ∧ 𝐹 finSupp (0g‘𝑆) ∧ (𝐹( linC ‘𝑀){𝑉}) = (0g‘𝑀))) | ||
| Theorem | lincvalsc0 48810* | The linear combination where all scalars are 0. (Contributed by AV, 12-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 0 = (0g‘𝑆) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝐹 = (𝑥 ∈ 𝑉 ↦ 0 ) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵) → (𝐹( linC ‘𝑀)𝑉) = 𝑍) | ||
| Theorem | lcoc0 48811* | Properties of a linear combination where all scalars are 0. (Contributed by AV, 12-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 0 = (0g‘𝑆) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝐹 = (𝑥 ∈ 𝑉 ↦ 0 ) & ⊢ 𝑅 = (Base‘𝑆) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵) → (𝐹 ∈ (𝑅 ↑m 𝑉) ∧ 𝐹 finSupp 0 ∧ (𝐹( linC ‘𝑀)𝑉) = 𝑍)) | ||
| Theorem | linc0scn0 48812* | If a set contains the zero element of a module, there is a linear combination being 0 where not all scalars are 0. (Contributed by AV, 13-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 0 = (0g‘𝑆) & ⊢ 1 = (1r‘𝑆) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝐹 = (𝑥 ∈ 𝑉 ↦ if(𝑥 = 𝑍, 1 , 0 )) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵) → (𝐹( linC ‘𝑀)𝑉) = 𝑍) | ||
| Theorem | lincdifsn 48813 | A vector is a linear combination of a set containing this vector. (Contributed by AV, 21-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝑆 = (Base‘𝑅) & ⊢ · = ( ·𝑠 ‘𝑀) & ⊢ + = (+g‘𝑀) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵 ∧ 𝑋 ∈ 𝑉) ∧ (𝐹 ∈ (𝑆 ↑m 𝑉) ∧ 𝐹 finSupp 0 ) ∧ 𝐺 = (𝐹 ↾ (𝑉 ∖ {𝑋}))) → (𝐹( linC ‘𝑀)𝑉) = ((𝐺( linC ‘𝑀)(𝑉 ∖ {𝑋})) + ((𝐹‘𝑋) · 𝑋))) | ||
| Theorem | linc1 48814* | A vector is a linear combination of a set containing this vector. (Contributed by AV, 18-Apr-2019.) (Proof shortened by AV, 28-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 0 = (0g‘𝑆) & ⊢ 1 = (1r‘𝑆) & ⊢ 𝐹 = (𝑥 ∈ 𝑉 ↦ if(𝑥 = 𝑋, 1 , 0 )) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵 ∧ 𝑋 ∈ 𝑉) → (𝐹( linC ‘𝑀)𝑉) = 𝑋) | ||
| Theorem | lincellss 48815 | A linear combination of a subset of a linear subspace is also contained in the linear subspace. (Contributed by AV, 20-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ ((𝑀 ∈ LMod ∧ 𝑆 ∈ (LSubSp‘𝑀) ∧ 𝑉 ⊆ 𝑆) → ((𝐹 ∈ ((Base‘(Scalar‘𝑀)) ↑m 𝑉) ∧ 𝐹 finSupp (0g‘(Scalar‘𝑀))) → (𝐹( linC ‘𝑀)𝑉) ∈ 𝑆)) | ||
| Theorem | lco0 48816 | The set of empty linear combinations over a monoid is the singleton with the identity element of the monoid. (Contributed by AV, 12-Apr-2019.) |
| ⊢ (𝑀 ∈ Mnd → (𝑀 LinCo ∅) = {(0g‘𝑀)}) | ||
| Theorem | lcoel0 48817 | The zero vector is always a linear combination. (Contributed by AV, 12-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) → (0g‘𝑀) ∈ (𝑀 LinCo 𝑉)) | ||
| Theorem | lincsum 48818 | The sum of two linear combinations is a linear combination, see also the proof in [Lang] p. 129. (Contributed by AV, 4-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ + = (+g‘𝑀) & ⊢ 𝑋 = (𝐴( linC ‘𝑀)𝑉) & ⊢ 𝑌 = (𝐵( linC ‘𝑀)𝑉) & ⊢ 𝑆 = (Scalar‘𝑀) & ⊢ 𝑅 = (Base‘𝑆) & ⊢ ✚ = (+g‘𝑆) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) ∧ (𝐴 ∈ (𝑅 ↑m 𝑉) ∧ 𝐵 ∈ (𝑅 ↑m 𝑉)) ∧ (𝐴 finSupp (0g‘𝑆) ∧ 𝐵 finSupp (0g‘𝑆))) → (𝑋 + 𝑌) = ((𝐴 ∘f ✚ 𝐵)( linC ‘𝑀)𝑉)) | ||
| Theorem | lincscm 48819* | A linear combinations multiplied with a scalar is a linear combination, see also the proof in [Lang] p. 129. (Contributed by AV, 9-Apr-2019.) (Revised by AV, 28-Jul-2019.) |
| ⊢ ∙ = ( ·𝑠 ‘𝑀) & ⊢ · = (.r‘(Scalar‘𝑀)) & ⊢ 𝑋 = (𝐴( linC ‘𝑀)𝑉) & ⊢ 𝑅 = (Base‘(Scalar‘𝑀)) & ⊢ 𝐹 = (𝑥 ∈ 𝑉 ↦ (𝑆 · (𝐴‘𝑥))) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) ∧ (𝐴 ∈ (𝑅 ↑m 𝑉) ∧ 𝑆 ∈ 𝑅) ∧ 𝐴 finSupp (0g‘(Scalar‘𝑀))) → (𝑆 ∙ 𝑋) = (𝐹( linC ‘𝑀)𝑉)) | ||
| Theorem | lincsumcl 48820 | The sum of two linear combinations is a linear combination, see also the proof in [Lang] p. 129. (Contributed by AV, 4-Apr-2019.) (Proof shortened by AV, 28-Jul-2019.) |
| ⊢ + = (+g‘𝑀) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) ∧ (𝐶 ∈ (𝑀 LinCo 𝑉) ∧ 𝐷 ∈ (𝑀 LinCo 𝑉))) → (𝐶 + 𝐷) ∈ (𝑀 LinCo 𝑉)) | ||
| Theorem | lincscmcl 48821 | The multiplication of a linear combination with a scalar is a linear combination, see also the proof in [Lang] p. 129. (Contributed by AV, 11-Apr-2019.) (Proof shortened by AV, 28-Jul-2019.) |
| ⊢ · = ( ·𝑠 ‘𝑀) & ⊢ 𝑅 = (Base‘(Scalar‘𝑀)) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) ∧ 𝐶 ∈ 𝑅 ∧ 𝐷 ∈ (𝑀 LinCo 𝑉)) → (𝐶 · 𝐷) ∈ (𝑀 LinCo 𝑉)) | ||
| Theorem | lincsumscmcl 48822 | The sum of a linear combination and a multiplication of a linear combination with a scalar is a linear combination. (Contributed by AV, 11-Apr-2019.) |
| ⊢ · = ( ·𝑠 ‘𝑀) & ⊢ 𝑅 = (Base‘(Scalar‘𝑀)) & ⊢ + = (+g‘𝑀) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) ∧ (𝐶 ∈ 𝑅 ∧ 𝐷 ∈ (𝑀 LinCo 𝑉) ∧ 𝐵 ∈ (𝑀 LinCo 𝑉))) → ((𝐶 · 𝐷) + 𝐵) ∈ (𝑀 LinCo 𝑉)) | ||
| Theorem | lincolss 48823 | According to the statement in [Lang] p. 129, the set (LSubSp‘𝑀) of all linear combinations of a set of vectors V is a submodule (generated by V) of the module M. The elements of V are called generators of (LSubSp‘𝑀). (Contributed by AV, 12-Apr-2019.) |
| ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) → (𝑀 LinCo 𝑉) ∈ (LSubSp‘𝑀)) | ||
| Theorem | ellcoellss 48824* | Every linear combination of a subset of a linear subspace is also contained in the linear subspace. (Contributed by AV, 20-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ ((𝑀 ∈ LMod ∧ 𝑆 ∈ (LSubSp‘𝑀) ∧ 𝑉 ⊆ 𝑆) → ∀𝑥 ∈ (𝑀 LinCo 𝑉)𝑥 ∈ 𝑆) | ||
| Theorem | lcoss 48825 | A set of vectors of a module is a subset of the set of all linear combinations of the set. (Contributed by AV, 18-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 (Base‘𝑀)) → 𝑉 ⊆ (𝑀 LinCo 𝑉)) | ||
| Theorem | lspsslco 48826 | Lemma for lspeqlco 48828. (Contributed by AV, 17-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵) → ((LSpan‘𝑀)‘𝑉) ⊆ (𝑀 LinCo 𝑉)) | ||
| Theorem | lcosslsp 48827 | Lemma for lspeqlco 48828. (Contributed by AV, 20-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵) → (𝑀 LinCo 𝑉) ⊆ ((LSpan‘𝑀)‘𝑉)) | ||
| Theorem | lspeqlco 48828 | Equivalence of a span of a set of vectors of a left module defined as the intersection of all linear subspaces which each contain every vector in that set (see df-lsp 20940) and as the set of all linear combinations of the vectors of the set with finite support. (Contributed by AV, 20-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑉 ∈ 𝒫 𝐵) → (𝑀 LinCo 𝑉) = ((LSpan‘𝑀)‘𝑉)) | ||
According to the definition in [Lang] p. 129: "A subset S of a module M is said
to be linearly independent (over [the ring] A) if whenever we have a
linear combination ∑x ∈S axx which is equal to
0, then ax=0 for all x∈S." This definition does not care for
the finiteness of the set S (because the definition of a linear combination
in [Lang] p.129 does already assure that only a finite number of coefficients
can be 0 in the sum). Our definition df-lininds 48831 does also neither claim that
the subset must be finite, nor that almost all coefficients within the linear
combination are 0. If this is required, it must be explicitly stated as
precondition in the corresponding theorems. | ||
| Syntax | clininds 48829 | Extend class notation with the relation between a module and its linearly independent subsets. |
| class linIndS | ||
| Syntax | clindeps 48830 | Extend class notation with the relation between a module and its linearly dependent subsets. |
| class linDepS | ||
| Definition | df-lininds 48831* | Define the relation between a module and its linearly independent subsets. (Contributed by AV, 12-Apr-2019.) (Revised by AV, 24-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ linIndS = {〈𝑠, 𝑚〉 ∣ (𝑠 ∈ 𝒫 (Base‘𝑚) ∧ ∀𝑓 ∈ ((Base‘(Scalar‘𝑚)) ↑m 𝑠)((𝑓 finSupp (0g‘(Scalar‘𝑚)) ∧ (𝑓( linC ‘𝑚)𝑠) = (0g‘𝑚)) → ∀𝑥 ∈ 𝑠 (𝑓‘𝑥) = (0g‘(Scalar‘𝑚))))} | ||
| Theorem | rellininds 48832 | The class defining the relation between a module and its linearly independent subsets is a relation. (Contributed by AV, 13-Apr-2019.) |
| ⊢ Rel linIndS | ||
| Definition | df-lindeps 48833* | Define the relation between a module and its linearly dependent subsets. (Contributed by AV, 26-Apr-2019.) |
| ⊢ linDepS = {〈𝑠, 𝑚〉 ∣ ¬ 𝑠 linIndS 𝑚} | ||
| Theorem | linindsv 48834 | The classes of the module and its linearly independent subsets are sets. (Contributed by AV, 13-Apr-2019.) |
| ⊢ (𝑆 linIndS 𝑀 → (𝑆 ∈ V ∧ 𝑀 ∈ V)) | ||
| Theorem | islininds 48835* | The property of being a linearly independent subset. (Contributed by AV, 13-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ 𝑊) → (𝑆 linIndS 𝑀 ↔ (𝑆 ∈ 𝒫 𝐵 ∧ ∀𝑓 ∈ (𝐸 ↑m 𝑆)((𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍) → ∀𝑥 ∈ 𝑆 (𝑓‘𝑥) = 0 )))) | ||
| Theorem | linindsi 48836* | The implications of being a linearly independent subset. (Contributed by AV, 13-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ (𝑆 linIndS 𝑀 → (𝑆 ∈ 𝒫 𝐵 ∧ ∀𝑓 ∈ (𝐸 ↑m 𝑆)((𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍) → ∀𝑥 ∈ 𝑆 (𝑓‘𝑥) = 0 ))) | ||
| Theorem | linindslinci 48837* | The implications of being a linearly independent subset and a linear combination of this subset being 0. (Contributed by AV, 24-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑆 linIndS 𝑀 ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ 𝐹 finSupp 0 ∧ (𝐹( linC ‘𝑀)𝑆) = 𝑍)) → ∀𝑥 ∈ 𝑆 (𝐹‘𝑥) = 0 ) | ||
| Theorem | islinindfis 48838* | The property of being a linearly independent finite subset. (Contributed by AV, 27-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑆 ∈ Fin ∧ 𝑀 ∈ 𝑊) → (𝑆 linIndS 𝑀 ↔ (𝑆 ∈ 𝒫 𝐵 ∧ ∀𝑓 ∈ (𝐸 ↑m 𝑆)((𝑓( linC ‘𝑀)𝑆) = 𝑍 → ∀𝑥 ∈ 𝑆 (𝑓‘𝑥) = 0 )))) | ||
| Theorem | islinindfiss 48839* | The property of being a linearly independent finite subset. (Contributed by AV, 27-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑀 ∈ 𝑊 ∧ 𝑆 ∈ Fin ∧ 𝑆 ∈ 𝒫 𝐵) → (𝑆 linIndS 𝑀 ↔ ∀𝑓 ∈ (𝐸 ↑m 𝑆)((𝑓( linC ‘𝑀)𝑆) = 𝑍 → ∀𝑥 ∈ 𝑆 (𝑓‘𝑥) = 0 ))) | ||
| Theorem | linindscl 48840 | A linearly independent set is a subset of (the base set of) a module. (Contributed by AV, 13-Apr-2019.) |
| ⊢ (𝑆 linIndS 𝑀 → 𝑆 ∈ 𝒫 (Base‘𝑀)) | ||
| Theorem | lindepsnlininds 48841 | A linearly dependent subset is not a linearly independent subset. (Contributed by AV, 26-Apr-2019.) |
| ⊢ ((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ 𝑊) → (𝑆 linDepS 𝑀 ↔ ¬ 𝑆 linIndS 𝑀)) | ||
| Theorem | islindeps 48842* | The property of being a linearly dependent subset. (Contributed by AV, 26-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑀 ∈ 𝑊 ∧ 𝑆 ∈ 𝒫 𝐵) → (𝑆 linDepS 𝑀 ↔ ∃𝑓 ∈ (𝐸 ↑m 𝑆)(𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍 ∧ ∃𝑥 ∈ 𝑆 (𝑓‘𝑥) ≠ 0 ))) | ||
| Theorem | lincext1 48843* | Property 1 of an extension of a linear combination. (Contributed by AV, 20-Apr-2019.) (Revised by AV, 29-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐹 = (𝑧 ∈ 𝑆 ↦ if(𝑧 = 𝑋, (𝑁‘𝑌), (𝐺‘𝑧))) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑆 ∈ 𝒫 𝐵) ∧ (𝑌 ∈ 𝐸 ∧ 𝑋 ∈ 𝑆 ∧ 𝐺 ∈ (𝐸 ↑m (𝑆 ∖ {𝑋})))) → 𝐹 ∈ (𝐸 ↑m 𝑆)) | ||
| Theorem | lincext2 48844* | Property 2 of an extension of a linear combination. (Contributed by AV, 20-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐹 = (𝑧 ∈ 𝑆 ↦ if(𝑧 = 𝑋, (𝑁‘𝑌), (𝐺‘𝑧))) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑆 ∈ 𝒫 𝐵) ∧ (𝑌 ∈ 𝐸 ∧ 𝑋 ∈ 𝑆 ∧ 𝐺 ∈ (𝐸 ↑m (𝑆 ∖ {𝑋}))) ∧ 𝐺 finSupp 0 ) → 𝐹 finSupp 0 ) | ||
| Theorem | lincext3 48845* | Property 3 of an extension of a linear combination. (Contributed by AV, 23-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐹 = (𝑧 ∈ 𝑆 ↦ if(𝑧 = 𝑋, (𝑁‘𝑌), (𝐺‘𝑧))) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑆 ∈ 𝒫 𝐵) ∧ (𝑌 ∈ 𝐸 ∧ 𝑋 ∈ 𝑆 ∧ 𝐺 ∈ (𝐸 ↑m (𝑆 ∖ {𝑋}))) ∧ (𝐺 finSupp 0 ∧ (𝑌( ·𝑠 ‘𝑀)𝑋) = (𝐺( linC ‘𝑀)(𝑆 ∖ {𝑋})))) → (𝐹( linC ‘𝑀)𝑆) = 𝑍) | ||
| Theorem | lindslinindsimp1 48846* | Implication 1 for lindslininds 48853. (Contributed by AV, 25-Apr-2019.) (Revised by AV, 30-Jul-2019.) (Proof shortened by II, 16-Feb-2023.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) ⇒ ⊢ ((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) → ((𝑆 ∈ 𝒫 (Base‘𝑀) ∧ ∀𝑓 ∈ (𝐵 ↑m 𝑆)((𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍) → ∀𝑥 ∈ 𝑆 (𝑓‘𝑥) = 0 )) → (𝑆 ⊆ (Base‘𝑀) ∧ ∀𝑠 ∈ 𝑆 ∀𝑦 ∈ (𝐵 ∖ { 0 }) ¬ (𝑦( ·𝑠 ‘𝑀)𝑠) ∈ ((LSpan‘𝑀)‘(𝑆 ∖ {𝑠}))))) | ||
| Theorem | lindslinindimp2lem1 48847* | Lemma 1 for lindslinindsimp2 48852. (Contributed by AV, 25-Apr-2019.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑌 = ((invg‘𝑅)‘(𝑓‘𝑥)) & ⊢ 𝐺 = (𝑓 ↾ (𝑆 ∖ {𝑥})) ⇒ ⊢ (((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) ∧ (𝑆 ⊆ (Base‘𝑀) ∧ 𝑥 ∈ 𝑆 ∧ 𝑓 ∈ (𝐵 ↑m 𝑆))) → 𝑌 ∈ 𝐵) | ||
| Theorem | lindslinindimp2lem2 48848* | Lemma 2 for lindslinindsimp2 48852. (Contributed by AV, 25-Apr-2019.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑌 = ((invg‘𝑅)‘(𝑓‘𝑥)) & ⊢ 𝐺 = (𝑓 ↾ (𝑆 ∖ {𝑥})) ⇒ ⊢ (((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) ∧ (𝑆 ⊆ (Base‘𝑀) ∧ 𝑥 ∈ 𝑆 ∧ 𝑓 ∈ (𝐵 ↑m 𝑆))) → 𝐺 ∈ (𝐵 ↑m (𝑆 ∖ {𝑥}))) | ||
| Theorem | lindslinindimp2lem3 48849* | Lemma 3 for lindslinindsimp2 48852. (Contributed by AV, 25-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑌 = ((invg‘𝑅)‘(𝑓‘𝑥)) & ⊢ 𝐺 = (𝑓 ↾ (𝑆 ∖ {𝑥})) ⇒ ⊢ (((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) ∧ (𝑆 ⊆ (Base‘𝑀) ∧ 𝑥 ∈ 𝑆) ∧ (𝑓 ∈ (𝐵 ↑m 𝑆) ∧ 𝑓 finSupp 0 )) → 𝐺 finSupp 0 ) | ||
| Theorem | lindslinindimp2lem4 48850* | Lemma 4 for lindslinindsimp2 48852. (Contributed by AV, 25-Apr-2019.) (Revised by AV, 30-Jul-2019.) (Proof shortened by II, 16-Feb-2023.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑌 = ((invg‘𝑅)‘(𝑓‘𝑥)) & ⊢ 𝐺 = (𝑓 ↾ (𝑆 ∖ {𝑥})) ⇒ ⊢ (((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) ∧ (𝑆 ⊆ (Base‘𝑀) ∧ 𝑥 ∈ 𝑆) ∧ (𝑓 ∈ (𝐵 ↑m 𝑆) ∧ 𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍)) → (𝑀 Σg (𝑦 ∈ (𝑆 ∖ {𝑥}) ↦ ((𝑓‘𝑦)( ·𝑠 ‘𝑀)𝑦))) = (𝑌( ·𝑠 ‘𝑀)𝑥)) | ||
| Theorem | lindslinindsimp2lem5 48851* | Lemma 5 for lindslinindsimp2 48852. (Contributed by AV, 25-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) ⇒ ⊢ (((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) ∧ (𝑆 ⊆ (Base‘𝑀) ∧ 𝑥 ∈ 𝑆)) → ((𝑓 ∈ (𝐵 ↑m 𝑆) ∧ (𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍)) → (∀𝑦 ∈ (𝐵 ∖ { 0 })∀𝑔 ∈ (𝐵 ↑m (𝑆 ∖ {𝑥}))(¬ 𝑔 finSupp 0 ∨ ¬ (𝑦( ·𝑠 ‘𝑀)𝑥) = (𝑔( linC ‘𝑀)(𝑆 ∖ {𝑥}))) → (𝑓‘𝑥) = 0 ))) | ||
| Theorem | lindslinindsimp2 48852* | Implication 2 for lindslininds 48853. (Contributed by AV, 26-Apr-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) ⇒ ⊢ ((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) → ((𝑆 ⊆ (Base‘𝑀) ∧ ∀𝑠 ∈ 𝑆 ∀𝑦 ∈ (𝐵 ∖ { 0 }) ¬ (𝑦( ·𝑠 ‘𝑀)𝑠) ∈ ((LSpan‘𝑀)‘(𝑆 ∖ {𝑠}))) → (𝑆 ∈ 𝒫 (Base‘𝑀) ∧ ∀𝑓 ∈ (𝐵 ↑m 𝑆)((𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)𝑆) = 𝑍) → ∀𝑥 ∈ 𝑆 (𝑓‘𝑥) = 0 )))) | ||
| Theorem | lindslininds 48853 | Equivalence of definitions df-linds 21779 and df-lininds 48831 for (linear) independence for (left) modules. (Contributed by AV, 26-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ ((𝑆 ∈ 𝑉 ∧ 𝑀 ∈ LMod) → (𝑆 linIndS 𝑀 ↔ 𝑆 ∈ (LIndS‘𝑀))) | ||
| Theorem | linds0 48854 | The empty set is always a linearly independent subset. (Contributed by AV, 13-Apr-2019.) (Revised by AV, 27-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ (𝑀 ∈ 𝑉 → ∅ linIndS 𝑀) | ||
| Theorem | el0ldep 48855 | A set containing the zero element of a module is always linearly dependent, if the underlying ring has at least two elements. (Contributed by AV, 13-Apr-2019.) (Revised by AV, 27-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ (((𝑀 ∈ LMod ∧ 1 < (♯‘(Base‘(Scalar‘𝑀)))) ∧ 𝑆 ∈ 𝒫 (Base‘𝑀) ∧ (0g‘𝑀) ∈ 𝑆) → 𝑆 linDepS 𝑀) | ||
| Theorem | el0ldepsnzr 48856 | A set containing the zero element of a module over a nonzero ring is always linearly dependent. (Contributed by AV, 14-Apr-2019.) (Revised by AV, 27-Apr-2019.) |
| ⊢ (((𝑀 ∈ LMod ∧ (Scalar‘𝑀) ∈ NzRing) ∧ 𝑆 ∈ 𝒫 (Base‘𝑀) ∧ (0g‘𝑀) ∈ 𝑆) → 𝑆 linDepS 𝑀) | ||
| Theorem | lindsrng01 48857 | Any subset of a module is always linearly independent if the underlying ring has at most one element. Since the underlying ring cannot be the empty set (see lmodsn0 20842), this means that the underlying ring has only one element, so it is a zero ring. (Contributed by AV, 14-Apr-2019.) (Revised by AV, 27-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) ⇒ ⊢ ((𝑀 ∈ LMod ∧ ((♯‘𝐸) = 0 ∨ (♯‘𝐸) = 1) ∧ 𝑆 ∈ 𝒫 𝐵) → 𝑆 linIndS 𝑀) | ||
| Theorem | lindszr 48858 | Any subset of a module over a zero ring is always linearly independent. (Contributed by AV, 27-Apr-2019.) |
| ⊢ ((𝑀 ∈ LMod ∧ ¬ (Scalar‘𝑀) ∈ NzRing ∧ 𝑆 ∈ 𝒫 (Base‘𝑀)) → 𝑆 linIndS 𝑀) | ||
| Theorem | snlindsntorlem 48859* | Lemma for snlindsntor 48860. (Contributed by AV, 15-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝑆 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ · = ( ·𝑠 ‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑋 ∈ 𝐵) → (∀𝑓 ∈ (𝑆 ↑m {𝑋})((𝑓( linC ‘𝑀){𝑋}) = 𝑍 → (𝑓‘𝑋) = 0 ) → ∀𝑠 ∈ 𝑆 ((𝑠 · 𝑋) = 𝑍 → 𝑠 = 0 ))) | ||
| Theorem | snlindsntor 48860* | A singleton is linearly independent iff it does not contain a torsion element. According to Wikipedia ("Torsion (algebra)", 15-Apr-2019, https://en.wikipedia.org/wiki/Torsion_(algebra)): "An element m of a module M over a ring R is called a torsion element of the module if there exists a regular element r of the ring (an element that is neither a left nor a right zero divisor) that annihilates m, i.e., (𝑟 · 𝑚) = 0. In an integral domain (a commutative ring without zero divisors), every nonzero element is regular, so a torsion element of a module over an integral domain is one annihilated by a nonzero element of the integral domain." Analogously, the definition in [Lang] p. 147 states that "An element x of [a module] E [over a ring R] is called a torsion element if there exists 𝑎 ∈ 𝑅, 𝑎 ≠ 0, such that 𝑎 · 𝑥 = 0. This definition includes the zero element of the module. Some authors, however, exclude the zero element from the definition of torsion elements. (Contributed by AV, 14-Apr-2019.) (Revised by AV, 27-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝑆 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ · = ( ·𝑠 ‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑋 ∈ 𝐵) → (∀𝑠 ∈ (𝑆 ∖ { 0 })(𝑠 · 𝑋) ≠ 𝑍 ↔ {𝑋} linIndS 𝑀)) | ||
| Theorem | ldepsprlem 48861 | Lemma for ldepspr 48862. (Contributed by AV, 16-Apr-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝑆 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ · = ( ·𝑠 ‘𝑀) & ⊢ 1 = (1r‘𝑅) & ⊢ 𝑁 = (invg‘𝑅) ⇒ ⊢ ((𝑀 ∈ LMod ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝐴 ∈ 𝑆)) → (𝑋 = (𝐴 · 𝑌) → (( 1 · 𝑋)(+g‘𝑀)((𝑁‘𝐴) · 𝑌)) = 𝑍)) | ||
| Theorem | ldepspr 48862 | If a vector is a scalar multiple of another vector, the (unordered pair containing the) two vectors are linearly dependent. (Contributed by AV, 16-Apr-2019.) (Revised by AV, 27-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝑆 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ · = ( ·𝑠 ‘𝑀) ⇒ ⊢ ((𝑀 ∈ LMod ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ≠ 𝑌)) → ((𝐴 ∈ 𝑆 ∧ 𝑋 = (𝐴 · 𝑌)) → {𝑋, 𝑌} linDepS 𝑀)) | ||
| Theorem | lincresunit3lem3 48863 | Lemma 3 for lincresunit3 48870. (Contributed by AV, 18-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ · = ( ·𝑠 ‘𝑀) ⇒ ⊢ (((𝑀 ∈ LMod ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ 𝐴 ∈ 𝑈) → (((𝑁‘𝐴) · 𝑋) = ((𝑁‘𝐴) · 𝑌) ↔ 𝑋 = 𝑌)) | ||
| Theorem | lincresunitlem1 48864 | Lemma 1 for properties of a specially modified restriction of a linear combination containing a unit as scalar. (Contributed by AV, 18-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈)) → (𝐼‘(𝑁‘(𝐹‘𝑋))) ∈ 𝐸) | ||
| Theorem | lincresunitlem2 48865 | Lemma for properties of a specially modified restriction of a linear combination containing a unit as scalar. (Contributed by AV, 18-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ ((((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈)) ∧ 𝑌 ∈ 𝑆) → ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑌)) ∈ 𝐸) | ||
| Theorem | lincresunit1 48866* | Property 1 of a specially modified restriction of a linear combination containing a unit as scalar. (Contributed by AV, 18-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈)) → 𝐺 ∈ (𝐸 ↑m (𝑆 ∖ {𝑋}))) | ||
| Theorem | lincresunit2 48867* | Property 2 of a specially modified restriction of a linear combination containing a unit as scalar. (Contributed by AV, 18-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈 ∧ 𝐹 finSupp 0 )) → 𝐺 finSupp 0 ) | ||
| Theorem | lincresunit3lem1 48868* | Lemma 1 for lincresunit3 48870. (Contributed by AV, 17-May-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈 ∧ 𝑧 ∈ (𝑆 ∖ {𝑋}))) → ((𝑁‘(𝐹‘𝑋))( ·𝑠 ‘𝑀)((𝐺‘𝑧)( ·𝑠 ‘𝑀)𝑧)) = ((𝐹‘𝑧)( ·𝑠 ‘𝑀)𝑧)) | ||
| Theorem | lincresunit3lem2 48869* | Lemma 2 for lincresunit3 48870. (Contributed by AV, 18-May-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈 ∧ 𝐹 finSupp 0 )) → ((𝑁‘(𝐹‘𝑋))( ·𝑠 ‘𝑀)(𝑀 Σg (𝑧 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐺‘𝑧)( ·𝑠 ‘𝑀)𝑧)))) = ((𝐹 ↾ (𝑆 ∖ {𝑋}))( linC ‘𝑀)(𝑆 ∖ {𝑋}))) | ||
| Theorem | lincresunit3 48870* | Property 3 of a specially modified restriction of a linear combination in a vector space. (Contributed by AV, 18-May-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LMod ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ∈ 𝑈 ∧ 𝐹 finSupp 0 ) ∧ (𝐹( linC ‘𝑀)𝑆) = 𝑍) → (𝐺( linC ‘𝑀)(𝑆 ∖ {𝑋})) = 𝑋) | ||
| Theorem | lincreslvec3 48871* | Property 3 of a specially modified restriction of a linear combination in a vector space. (Contributed by AV, 18-May-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 𝑈 = (Unit‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑁 = (invg‘𝑅) & ⊢ 𝐼 = (invr‘𝑅) & ⊢ · = (.r‘𝑅) & ⊢ 𝐺 = (𝑠 ∈ (𝑆 ∖ {𝑋}) ↦ ((𝐼‘(𝑁‘(𝐹‘𝑋))) · (𝐹‘𝑠))) ⇒ ⊢ (((𝑆 ∈ 𝒫 𝐵 ∧ 𝑀 ∈ LVec ∧ 𝑋 ∈ 𝑆) ∧ (𝐹 ∈ (𝐸 ↑m 𝑆) ∧ (𝐹‘𝑋) ≠ 0 ∧ 𝐹 finSupp 0 ) ∧ (𝐹( linC ‘𝑀)𝑆) = 𝑍) → (𝐺( linC ‘𝑀)(𝑆 ∖ {𝑋})) = 𝑋) | ||
| Theorem | islindeps2 48872* | Conditions for being a linearly dependent subset of a (left) module over a nonzero ring. (Contributed by AV, 29-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑆 ∈ 𝒫 𝐵 ∧ 𝑅 ∈ NzRing) → (∃𝑠 ∈ 𝑆 ∃𝑓 ∈ (𝐸 ↑m (𝑆 ∖ {𝑠}))(𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)(𝑆 ∖ {𝑠})) = 𝑠) → 𝑆 linDepS 𝑀)) | ||
| Theorem | islininds2 48873* | Implication of being a linearly independent subset of a (left) module over a nonzero ring. (Contributed by AV, 29-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑀 ∈ LMod ∧ 𝑆 ∈ 𝒫 𝐵 ∧ 𝑅 ∈ NzRing) → (𝑆 linIndS 𝑀 → ∀𝑠 ∈ 𝑆 ∀𝑓 ∈ (𝐸 ↑m (𝑆 ∖ {𝑠}))(¬ 𝑓 finSupp 0 ∨ (𝑓( linC ‘𝑀)(𝑆 ∖ {𝑠})) ≠ 𝑠))) | ||
| Theorem | isldepslvec2 48874* | Alternative definition of being a linearly dependent subset of a (left) vector space. In this case, the reverse implication of islindeps2 48872 holds, so that both definitions are equivalent (see theorem 1.6 in [Roman] p. 46 and the note in [Roman] p. 112: if a nontrivial linear combination of elements (where not all of the coefficients are 0) in an R-vector space is 0, then and only then each of the elements is a linear combination of the others. (Contributed by AV, 30-Apr-2019.) (Proof shortened by AV, 30-Jul-2019.) |
| ⊢ 𝐵 = (Base‘𝑀) & ⊢ 𝑍 = (0g‘𝑀) & ⊢ 𝑅 = (Scalar‘𝑀) & ⊢ 𝐸 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) ⇒ ⊢ ((𝑀 ∈ LVec ∧ 𝑆 ∈ 𝒫 𝐵) → (∃𝑠 ∈ 𝑆 ∃𝑓 ∈ (𝐸 ↑m (𝑆 ∖ {𝑠}))(𝑓 finSupp 0 ∧ (𝑓( linC ‘𝑀)(𝑆 ∖ {𝑠})) = 𝑠) ↔ 𝑆 linDepS 𝑀)) | ||
| Theorem | lindssnlvec 48875 | A singleton not containing the zero element of a vector space is always linearly independent. (Contributed by AV, 16-Apr-2019.) (Revised by AV, 28-Apr-2019.) |
| ⊢ ((𝑀 ∈ LVec ∧ 𝑆 ∈ (Base‘𝑀) ∧ 𝑆 ≠ (0g‘𝑀)) → {𝑆} linIndS 𝑀) | ||
| Theorem | lmod1lem1 48876* | Lemma 1 for lmod1 48881. (Contributed by AV, 28-Apr-2019.) |
| ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), (𝑥 ∈ (Base‘𝑅), 𝑦 ∈ {𝐼} ↦ 𝑦)〉}) ⇒ ⊢ ((𝐼 ∈ 𝑉 ∧ 𝑅 ∈ Ring ∧ 𝑟 ∈ (Base‘𝑅)) → (𝑟( ·𝑠 ‘𝑀)𝐼) ∈ {𝐼}) | ||
| Theorem | lmod1lem2 48877* | Lemma 2 for lmod1 48881. (Contributed by AV, 28-Apr-2019.) |
| ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), (𝑥 ∈ (Base‘𝑅), 𝑦 ∈ {𝐼} ↦ 𝑦)〉}) ⇒ ⊢ ((𝐼 ∈ 𝑉 ∧ 𝑅 ∈ Ring ∧ 𝑟 ∈ (Base‘𝑅)) → (𝑟( ·𝑠 ‘𝑀)(𝐼(+g‘𝑀)𝐼)) = ((𝑟( ·𝑠 ‘𝑀)𝐼)(+g‘𝑀)(𝑟( ·𝑠 ‘𝑀)𝐼))) | ||
| Theorem | lmod1lem3 48878* | Lemma 3 for lmod1 48881. (Contributed by AV, 29-Apr-2019.) |
| ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), (𝑥 ∈ (Base‘𝑅), 𝑦 ∈ {𝐼} ↦ 𝑦)〉}) ⇒ ⊢ (((𝐼 ∈ 𝑉 ∧ 𝑅 ∈ Ring) ∧ (𝑞 ∈ (Base‘𝑅) ∧ 𝑟 ∈ (Base‘𝑅))) → ((𝑞(+g‘(Scalar‘𝑀))𝑟)( ·𝑠 ‘𝑀)𝐼) = ((𝑞( ·𝑠 ‘𝑀)𝐼)(+g‘𝑀)(𝑟( ·𝑠 ‘𝑀)𝐼))) | ||
| Theorem | lmod1lem4 48879* | Lemma 4 for lmod1 48881. (Contributed by AV, 29-Apr-2019.) |
| ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), (𝑥 ∈ (Base‘𝑅), 𝑦 ∈ {𝐼} ↦ 𝑦)〉}) ⇒ ⊢ (((𝐼 ∈ 𝑉 ∧ 𝑅 ∈ Ring) ∧ (𝑞 ∈ (Base‘𝑅) ∧ 𝑟 ∈ (Base‘𝑅))) → ((𝑞(.r‘(Scalar‘𝑀))𝑟)( ·𝑠 ‘𝑀)𝐼) = (𝑞( ·𝑠 ‘𝑀)(𝑟( ·𝑠 ‘𝑀)𝐼))) | ||
| Theorem | lmod1lem5 48880* | Lemma 5 for lmod1 48881. (Contributed by AV, 28-Apr-2019.) |
| ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), (𝑥 ∈ (Base‘𝑅), 𝑦 ∈ {𝐼} ↦ 𝑦)〉}) ⇒ ⊢ ((𝐼 ∈ 𝑉 ∧ 𝑅 ∈ Ring) → ((1r‘(Scalar‘𝑀))( ·𝑠 ‘𝑀)𝐼) = 𝐼) | ||
| Theorem | lmod1 48881* | The (smallest) structure representing a zero module over an arbitrary ring. (Contributed by AV, 29-Apr-2019.) |
| ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), (𝑥 ∈ (Base‘𝑅), 𝑦 ∈ {𝐼} ↦ 𝑦)〉}) ⇒ ⊢ ((𝐼 ∈ 𝑉 ∧ 𝑅 ∈ Ring) → 𝑀 ∈ LMod) | ||
| Theorem | lmod1zr 48882 | The (smallest) structure representing a zero module over a zero ring. (Contributed by AV, 29-Apr-2019.) |
| ⊢ 𝑅 = {〈(Base‘ndx), {𝑍}〉, 〈(+g‘ndx), {〈〈𝑍, 𝑍〉, 𝑍〉}〉, 〈(.r‘ndx), {〈〈𝑍, 𝑍〉, 𝑍〉}〉} & ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), {〈〈𝑍, 𝐼〉, 𝐼〉}〉}) ⇒ ⊢ ((𝐼 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → 𝑀 ∈ LMod) | ||
| Theorem | lmod1zrnlvec 48883 | There is a (left) module (a zero module) which is not a (left) vector space. (Contributed by AV, 29-Apr-2019.) |
| ⊢ 𝑅 = {〈(Base‘ndx), {𝑍}〉, 〈(+g‘ndx), {〈〈𝑍, 𝑍〉, 𝑍〉}〉, 〈(.r‘ndx), {〈〈𝑍, 𝑍〉, 𝑍〉}〉} & ⊢ 𝑀 = ({〈(Base‘ndx), {𝐼}〉, 〈(+g‘ndx), {〈〈𝐼, 𝐼〉, 𝐼〉}〉, 〈(Scalar‘ndx), 𝑅〉} ∪ {〈( ·𝑠 ‘ndx), {〈〈𝑍, 𝐼〉, 𝐼〉}〉}) ⇒ ⊢ ((𝐼 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → 𝑀 ∉ LVec) | ||
| Theorem | lmodn0 48884 | Left modules exist. (Contributed by AV, 29-Apr-2019.) |
| ⊢ LMod ≠ ∅ | ||
| Theorem | zlmodzxzequa 48885 | Example of an equation within the ℤ-module ℤ × ℤ (see example in [Roman] p. 112 for a linearly dependent set). (Contributed by AV, 22-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 0 = {〈0, 0〉, 〈1, 0〉} & ⊢ ∙ = ( ·𝑠 ‘𝑍) & ⊢ − = (-g‘𝑍) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} ⇒ ⊢ ((2 ∙ 𝐴) − (3 ∙ 𝐵)) = 0 | ||
| Theorem | zlmodzxznm 48886 | Example of a linearly dependent set whose elements are not linear combinations of the others, see note in [Roman] p. 112). (Contributed by AV, 23-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 0 = {〈0, 0〉, 〈1, 0〉} & ⊢ ∙ = ( ·𝑠 ‘𝑍) & ⊢ − = (-g‘𝑍) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} ⇒ ⊢ ∀𝑖 ∈ ℤ ((𝑖 ∙ 𝐴) ≠ 𝐵 ∧ (𝑖 ∙ 𝐵) ≠ 𝐴) | ||
| Theorem | zlmodzxzldeplem 48887 | A and B are not equal. (Contributed by AV, 24-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} ⇒ ⊢ 𝐴 ≠ 𝐵 | ||
| Theorem | zlmodzxzequap 48888 | Example of an equation within the ℤ-module ℤ × ℤ (see example in [Roman] p. 112 for a linearly dependent set), written as a sum. (Contributed by AV, 24-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} & ⊢ 0 = {〈0, 0〉, 〈1, 0〉} & ⊢ + = (+g‘𝑍) & ⊢ ∙ = ( ·𝑠 ‘𝑍) ⇒ ⊢ ((2 ∙ 𝐴) + (-3 ∙ 𝐵)) = 0 | ||
| Theorem | zlmodzxzldeplem1 48889 | Lemma 1 for zlmodzxzldep 48893. (Contributed by AV, 24-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} & ⊢ 𝐹 = {〈𝐴, 2〉, 〈𝐵, -3〉} ⇒ ⊢ 𝐹 ∈ (ℤ ↑m {𝐴, 𝐵}) | ||
| Theorem | zlmodzxzldeplem2 48890 | Lemma 2 for zlmodzxzldep 48893. (Contributed by AV, 24-May-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} & ⊢ 𝐹 = {〈𝐴, 2〉, 〈𝐵, -3〉} ⇒ ⊢ 𝐹 finSupp 0 | ||
| Theorem | zlmodzxzldeplem3 48891 | Lemma 3 for zlmodzxzldep 48893. (Contributed by AV, 24-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} & ⊢ 𝐹 = {〈𝐴, 2〉, 〈𝐵, -3〉} ⇒ ⊢ (𝐹( linC ‘𝑍){𝐴, 𝐵}) = (0g‘𝑍) | ||
| Theorem | zlmodzxzldeplem4 48892* | Lemma 4 for zlmodzxzldep 48893. (Contributed by AV, 24-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} & ⊢ 𝐹 = {〈𝐴, 2〉, 〈𝐵, -3〉} ⇒ ⊢ ∃𝑦 ∈ {𝐴, 𝐵} (𝐹‘𝑦) ≠ 0 | ||
| Theorem | zlmodzxzldep 48893 | { A , B } is a linearly dependent set within the ℤ-module ℤ × ℤ (see example in [Roman] p. 112). (Contributed by AV, 22-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} ⇒ ⊢ {𝐴, 𝐵} linDepS 𝑍 | ||
| Theorem | ldepsnlinclem1 48894 | Lemma 1 for ldepsnlinc 48897. (Contributed by AV, 25-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} ⇒ ⊢ (𝐹 ∈ ((Base‘ℤring) ↑m {𝐵}) → (𝐹( linC ‘𝑍){𝐵}) ≠ 𝐴) | ||
| Theorem | ldepsnlinclem2 48895 | Lemma 2 for ldepsnlinc 48897. (Contributed by AV, 25-May-2019.) (Revised by AV, 10-Jun-2019.) |
| ⊢ 𝑍 = (ℤring freeLMod {0, 1}) & ⊢ 𝐴 = {〈0, 3〉, 〈1, 6〉} & ⊢ 𝐵 = {〈0, 2〉, 〈1, 4〉} ⇒ ⊢ (𝐹 ∈ ((Base‘ℤring) ↑m {𝐴}) → (𝐹( linC ‘𝑍){𝐴}) ≠ 𝐵) | ||
| Theorem | lvecpsslmod 48896 | The class of all (left) vector spaces is a proper subclass of the class of all (left) modules. Although it is obvious (and proven by lveclmod 21075) that every left vector space is a left module, there is (at least) one left module which is no left vector space, for example the zero module over the zero ring, see lmod1zrnlvec 48883. (Contributed by AV, 29-Apr-2019.) |
| ⊢ LVec ⊊ LMod | ||
| Theorem | ldepsnlinc 48897* | The reverse implication of islindeps2 48872 does not hold for arbitrary (left) modules, see note in [Roman] p. 112: "... if a nontrivial linear combination of the elements ... in an R-module M is 0, ... where not all of the coefficients are 0, then we cannot conclude ... that one of the elements ... is a linear combination of the others." This means that there is at least one left module having a linearly dependent subset in which there is at least one element which is not a linear combination of the other elements of this subset. Such a left module can be constructed by using zlmodzxzequa 48885 and zlmodzxznm 48886. (Contributed by AV, 25-May-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ ∃𝑚 ∈ LMod ∃𝑠 ∈ 𝒫 (Base‘𝑚)(𝑠 linDepS 𝑚 ∧ ∀𝑣 ∈ 𝑠 ∀𝑓 ∈ ((Base‘(Scalar‘𝑚)) ↑m (𝑠 ∖ {𝑣}))(𝑓 finSupp (0g‘(Scalar‘𝑚)) → (𝑓( linC ‘𝑚)(𝑠 ∖ {𝑣})) ≠ 𝑣)) | ||
| Theorem | ldepslinc 48898* | For (left) vector spaces, isldepslvec2 48874 provides an alternative definition of being a linearly dependent subset, whereas ldepsnlinc 48897 indicates that there is not an analogous alternative definition for arbitrary (left) modules. (Contributed by AV, 25-May-2019.) (Revised by AV, 30-Jul-2019.) |
| ⊢ (∀𝑚 ∈ LVec ∀𝑠 ∈ 𝒫 (Base‘𝑚)(𝑠 linDepS 𝑚 ↔ ∃𝑣 ∈ 𝑠 ∃𝑓 ∈ ((Base‘(Scalar‘𝑚)) ↑m (𝑠 ∖ {𝑣}))(𝑓 finSupp (0g‘(Scalar‘𝑚)) ∧ (𝑓( linC ‘𝑚)(𝑠 ∖ {𝑣})) = 𝑣)) ∧ ¬ ∀𝑚 ∈ LMod ∀𝑠 ∈ 𝒫 (Base‘𝑚)(𝑠 linDepS 𝑚 ↔ ∃𝑣 ∈ 𝑠 ∃𝑓 ∈ ((Base‘(Scalar‘𝑚)) ↑m (𝑠 ∖ {𝑣}))(𝑓 finSupp (0g‘(Scalar‘𝑚)) ∧ (𝑓( linC ‘𝑚)(𝑠 ∖ {𝑣})) = 𝑣))) | ||
| Theorem | suppdm 48899 | If the range of a function does not contain the zero, the support of the function equals its domain. (Contributed by AV, 20-May-2020.) |
| ⊢ (((Fun 𝐹 ∧ 𝐹 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) ∧ 𝑍 ∉ ran 𝐹) → (𝐹 supp 𝑍) = dom 𝐹) | ||
| Theorem | eluz2cnn0n1 48900 | An integer greater than 1 is a complex number not equal to 0 or 1. (Contributed by AV, 23-May-2020.) |
| ⊢ (𝐵 ∈ (ℤ≥‘2) → 𝐵 ∈ (ℂ ∖ {0, 1})) | ||
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