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Theorem csbres 5983
Description: Distribute proper substitution through the restriction of a class. (Contributed by Alan Sare, 10-Nov-2012.) (Revised by NM, 23-Aug-2018.)
Assertion
Ref Expression
csbres 𝐴 / 𝑥(𝐵𝐶) = (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶)

Proof of Theorem csbres
StepHypRef Expression
1 df-res 5675 . . 3 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
21csbeq2i 3862 . 2 𝐴 / 𝑥(𝐵𝐶) = 𝐴 / 𝑥(𝐵 ∩ (𝐶 × V))
3 csbxp 5764 . . . . . 6 𝐴 / 𝑥(𝐶 × V) = (𝐴 / 𝑥𝐶 × 𝐴 / 𝑥V)
4 csbconstg 3873 . . . . . . 7 (𝐴 ∈ V → 𝐴 / 𝑥V = V)
54xpeq2d 5693 . . . . . 6 (𝐴 ∈ V → (𝐴 / 𝑥𝐶 × 𝐴 / 𝑥V) = (𝐴 / 𝑥𝐶 × V))
63, 5eqtrid 2810 . . . . 5 (𝐴 ∈ V → 𝐴 / 𝑥(𝐶 × V) = (𝐴 / 𝑥𝐶 × V))
7 0xp 5762 . . . . . . 7 (∅ × V) = ∅
87a1i 11 . . . . . 6 𝐴 ∈ V → (∅ × V) = ∅)
9 csbprc 4375 . . . . . . 7 𝐴 ∈ V → 𝐴 / 𝑥𝐶 = ∅)
109xpeq1d 5692 . . . . . 6 𝐴 ∈ V → (𝐴 / 𝑥𝐶 × V) = (∅ × V))
11 csbprc 4375 . . . . . 6 𝐴 ∈ V → 𝐴 / 𝑥(𝐶 × V) = ∅)
128, 10, 113eqtr4rd 2809 . . . . 5 𝐴 ∈ V → 𝐴 / 𝑥(𝐶 × V) = (𝐴 / 𝑥𝐶 × V))
136, 12pm2.61i 184 . . . 4 𝐴 / 𝑥(𝐶 × V) = (𝐴 / 𝑥𝐶 × V)
1413ineq2i 4171 . . 3 (𝐴 / 𝑥𝐵𝐴 / 𝑥(𝐶 × V)) = (𝐴 / 𝑥𝐵 ∩ (𝐴 / 𝑥𝐶 × V))
15 csbin 4408 . . 3 𝐴 / 𝑥(𝐵 ∩ (𝐶 × V)) = (𝐴 / 𝑥𝐵𝐴 / 𝑥(𝐶 × V))
16 df-res 5675 . . 3 (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶) = (𝐴 / 𝑥𝐵 ∩ (𝐴 / 𝑥𝐶 × V))
1714, 15, 163eqtr4i 2796 . 2 𝐴 / 𝑥(𝐵 ∩ (𝐶 × V)) = (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶)
182, 17eqtri 2786 1 𝐴 / 𝑥(𝐵𝐶) = (𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3   = wceq 1570  wcel 2143  Vcvv 3455  csb 3854  cin 3905  c0 4287   × cxp 5661  cres 5665
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-10 2176  ax-11 2192  ax-12 2213  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-nf 1814  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-nfc 2912  df-rab 3417  df-v 3457  df-sbc 3746  df-csb 3855  df-dif 3909  df-in 3913  df-nul 4288  df-opab 5175  df-xp 5669  df-res 5675
This theorem is referenced by:  csbfrecsg  8282  csbima12gALTVD  45585
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