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Theorem elcnvcnvlem 42942
Description: Two ways to say a set is a member of the converse of the converse of a class. (Contributed by RP, 20-Aug-2020.)
Assertion
Ref Expression
elcnvcnvlem (𝐴𝐵 ↔ (𝐴 ∈ (V × V) ∧ ( I ‘𝐴) ∈ 𝐵))

Proof of Theorem elcnvcnvlem
StepHypRef Expression
1 cnvcnv 6190 . . . 4 𝐵 = (𝐵 ∩ (V × V))
2 incom 4197 . . . 4 (𝐵 ∩ (V × V)) = ((V × V) ∩ 𝐵)
31, 2eqtri 2755 . . 3 𝐵 = ((V × V) ∩ 𝐵)
43eleq2i 2820 . 2 (𝐴𝐵𝐴 ∈ ((V × V) ∩ 𝐵))
5 elinlem 42941 . 2 (𝐴 ∈ ((V × V) ∩ 𝐵) ↔ (𝐴 ∈ (V × V) ∧ ( I ‘𝐴) ∈ 𝐵))
64, 5bitri 275 1 (𝐴𝐵 ↔ (𝐴 ∈ (V × V) ∧ ( I ‘𝐴) ∈ 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wb 205  wa 395  wcel 2099  Vcvv 3469  cin 3943   I cid 5569   × cxp 5670  ccnv 5671  cfv 6542
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1790  ax-4 1804  ax-5 1906  ax-6 1964  ax-7 2004  ax-8 2101  ax-9 2109  ax-10 2130  ax-12 2164  ax-ext 2698  ax-sep 5293  ax-nul 5300  ax-pr 5423
This theorem depends on definitions:  df-bi 206  df-an 396  df-or 847  df-3an 1087  df-tru 1537  df-fal 1547  df-ex 1775  df-nf 1779  df-sb 2061  df-mo 2529  df-eu 2558  df-clab 2705  df-cleq 2719  df-clel 2805  df-ral 3057  df-rex 3066  df-rab 3428  df-v 3471  df-dif 3947  df-un 3949  df-in 3951  df-ss 3961  df-nul 4319  df-if 4525  df-sn 4625  df-pr 4627  df-op 4631  df-uni 4904  df-br 5143  df-opab 5205  df-id 5570  df-xp 5678  df-rel 5679  df-cnv 5680  df-co 5681  df-dm 5682  df-iota 6494  df-fun 6544  df-fv 6550
This theorem is referenced by: (None)
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