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Theorem cnvcnv 6147
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6099 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6099 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5819 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6063 . . . . . 6 Rel 𝐴
5 df-rel 5628 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 232 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5639 . . . . . 6 Rel (V × V)
8 dfrel2 6144 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 232 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3966 . . . 4 𝐴(V × V)
11 dfss 3904 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 232 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2775 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5760 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6144 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 232 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2764 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1548  Vcvv 3433  cin 3884  wss 3885   × cxp 5619  ccnv 5620  Rel wrel 5626
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1803  ax-4 1817  ax-5 1918  ax-6 1975  ax-7 2016  ax-8 2123  ax-9 2131  ax-ext 2713  ax-sep 5221  ax-pr 5365
This theorem depends on definitions:  df-bi 209  df-an 398  df-or 855  df-3an 1095  df-tru 1551  df-fal 1561  df-ex 1788  df-sb 2075  df-clab 2720  df-cleq 2733  df-clel 2816  df-rab 3394  df-v 3435  df-dif 3888  df-un 3890  df-in 3892  df-ss 3902  df-nul 4265  df-if 4458  df-sn 4559  df-pr 4561  df-op 4565  df-br 5076  df-opab 5138  df-xp 5627  df-rel 5628  df-cnv 5629
This theorem is referenced by:  cnvcnv2  6148  cnvcnvss  6149  cnvrescnv  6150  structcnvcnv  17118  strfv2d  17166  elcnvcnvintab  44041  relintab  44042  nonrel  44043  elcnvcnvlem  44058  cnvcnvintabd  44059  tposresg  49382
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