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Theorem cnvcnv 6016
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 5970 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 5970 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5709 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 5934 . . . . . 6 Rel 𝐴
5 df-rel 5526 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 233 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5537 . . . . . 6 Rel (V × V)
8 dfrel2 6013 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 233 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3952 . . . 4 𝐴(V × V)
11 dfss 3899 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 233 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2832 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5651 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6013 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 233 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2821 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1538  Vcvv 3441  cin 3880  wss 3881   × cxp 5517  ccnv 5518  Rel wrel 5524
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2113  ax-9 2121  ax-10 2142  ax-11 2158  ax-12 2175  ax-ext 2770  ax-sep 5167  ax-nul 5174  ax-pr 5295
This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-3an 1086  df-tru 1541  df-ex 1782  df-nf 1786  df-sb 2070  df-mo 2598  df-eu 2629  df-clab 2777  df-cleq 2791  df-clel 2870  df-nfc 2938  df-rab 3115  df-v 3443  df-dif 3884  df-un 3886  df-in 3888  df-ss 3898  df-nul 4244  df-if 4426  df-sn 4526  df-pr 4528  df-op 4532  df-br 5031  df-opab 5093  df-xp 5525  df-rel 5526  df-cnv 5527
This theorem is referenced by:  cnvcnv2  6017  cnvcnvss  6018  cnvrescnv  6019  structcnvcnv  16489  strfv2d  16521  elcnvcnvintab  40282  relintab  40283  nonrel  40284  elcnvcnvlem  40299  cnvcnvintabd  40300
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