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Theorem cnvcnv 6156
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6108 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6108 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5829 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6069 . . . . . 6 Rel 𝐴
5 df-rel 5638 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 230 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5649 . . . . . 6 Rel (V × V)
8 dfrel2 6153 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 230 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3971 . . . 4 𝐴(V × V)
11 dfss 3908 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 230 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2770 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5770 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6153 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 230 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2759 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1542  Vcvv 3429  cin 3888  wss 3889   × cxp 5629  ccnv 5630  Rel wrel 5636
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2708  ax-sep 5231  ax-pr 5375
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2715  df-cleq 2728  df-clel 2811  df-rab 3390  df-v 3431  df-dif 3892  df-un 3894  df-in 3896  df-ss 3906  df-nul 4274  df-if 4467  df-sn 4568  df-pr 4570  df-op 4574  df-br 5086  df-opab 5148  df-xp 5637  df-rel 5638  df-cnv 5639
This theorem is referenced by:  cnvcnv2  6157  cnvcnvss  6158  cnvrescnv  6159  structcnvcnv  17123  strfv2d  17171  elcnvcnvintab  44009  relintab  44010  nonrel  44011  elcnvcnvlem  44026  cnvcnvintabd  44027  tposresg  49353
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