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Theorem cnvcnv 6151
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6103 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6103 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5824 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6064 . . . . . 6 Rel 𝐴
5 df-rel 5632 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 230 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5643 . . . . . 6 Rel (V × V)
8 dfrel2 6148 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 230 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3984 . . . 4 𝐴(V × V)
11 dfss 3921 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 230 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2771 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5764 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6148 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 230 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2760 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1542  Vcvv 3441  cin 3901  wss 3902   × cxp 5623  ccnv 5624  Rel wrel 5630
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2709  ax-sep 5242  ax-nul 5252  ax-pr 5378
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-rab 3401  df-v 3443  df-dif 3905  df-un 3907  df-in 3909  df-ss 3919  df-nul 4287  df-if 4481  df-sn 4582  df-pr 4584  df-op 4588  df-br 5100  df-opab 5162  df-xp 5631  df-rel 5632  df-cnv 5633
This theorem is referenced by:  cnvcnv2  6152  cnvcnvss  6153  cnvrescnv  6154  structcnvcnv  17085  strfv2d  17133  elcnvcnvintab  43901  relintab  43902  nonrel  43903  elcnvcnvlem  43918  cnvcnvintabd  43919  tposresg  49200
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