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Theorem cnvcnv 6149
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6101 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6101 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5822 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6062 . . . . . 6 Rel 𝐴
5 df-rel 5630 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 230 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5641 . . . . . 6 Rel (V × V)
8 dfrel2 6146 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 230 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3982 . . . 4 𝐴(V × V)
11 dfss 3919 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 230 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2769 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5762 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6146 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 230 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2758 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1542  Vcvv 3439  cin 3899  wss 3900   × cxp 5621  ccnv 5622  Rel wrel 5628
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2707  ax-sep 5240  ax-nul 5250  ax-pr 5376
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2714  df-cleq 2727  df-clel 2810  df-rab 3399  df-v 3441  df-dif 3903  df-un 3905  df-in 3907  df-ss 3917  df-nul 4285  df-if 4479  df-sn 4580  df-pr 4582  df-op 4586  df-br 5098  df-opab 5160  df-xp 5629  df-rel 5630  df-cnv 5631
This theorem is referenced by:  cnvcnv2  6150  cnvcnvss  6151  cnvrescnv  6152  structcnvcnv  17082  strfv2d  17130  elcnvcnvintab  43860  relintab  43861  nonrel  43862  elcnvcnvlem  43877  cnvcnvintabd  43878  tposresg  49160
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