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Theorem cnvcnv 6194
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6145 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6145 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5864 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6110 . . . . . 6 Rel 𝐴
5 df-rel 5672 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 233 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5683 . . . . . 6 Rel (V × V)
8 dfrel2 6191 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 233 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3994 . . . 4 𝐴(V × V)
11 dfss 3932 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 233 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2804 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5805 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6191 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 233 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2793 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1568  Vcvv 3462  cin 3912  wss 3913   × cxp 5663  ccnv 5664  Rel wrel 5670
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1823  ax-4 1837  ax-5 1938  ax-6 1995  ax-7 2036  ax-8 2152  ax-9 2160  ax-ext 2742  ax-sep 5262  ax-pr 5408
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1571  df-fal 1581  df-ex 1808  df-sb 2099  df-clab 2749  df-cleq 2762  df-clel 2845  df-rab 3424  df-v 3464  df-dif 3916  df-un 3918  df-in 3920  df-ss 3930  df-nul 4295  df-if 4493  df-sn 4595  df-pr 4597  df-op 4601  df-br 5115  df-opab 5179  df-xp 5671  df-rel 5672  df-cnv 5673
This theorem is referenced by:  cnvcnv2  6195  cnvcnvssOLD  6197  cnvrescnv  6198  structcnvcnv  17216  strfv2d  17264  elcnvcnvintab  44260  relintab  44261  nonrel  44262  elcnvcnvlem  44277  cnvcnvintabd  44278  tposresg  49605
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