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Theorem cnvcnv 6153
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6105 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6105 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5828 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6064 . . . . . 6 Rel 𝐴
5 df-rel 5638 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 230 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5649 . . . . . 6 Rel (V × V)
8 dfrel2 6150 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 230 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3993 . . . 4 𝐴(V × V)
11 dfss 3930 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 230 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2763 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5768 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6150 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 230 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2752 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1540  Vcvv 3444  cin 3910  wss 3911   × cxp 5629  ccnv 5630  Rel wrel 5636
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2701  ax-sep 5246  ax-nul 5256  ax-pr 5382
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2066  df-clab 2708  df-cleq 2721  df-clel 2803  df-rab 3403  df-v 3446  df-dif 3914  df-un 3916  df-in 3918  df-ss 3928  df-nul 4293  df-if 4485  df-sn 4586  df-pr 4588  df-op 4592  df-br 5103  df-opab 5165  df-xp 5637  df-rel 5638  df-cnv 5639
This theorem is referenced by:  cnvcnv2  6154  cnvcnvss  6155  cnvrescnv  6156  structcnvcnv  17099  strfv2d  17147  elcnvcnvintab  43564  relintab  43565  nonrel  43566  elcnvcnvlem  43581  cnvcnvintabd  43582  tposresg  48859
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