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Theorem cnvcnv 6189
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6140 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6140 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5859 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6105 . . . . . 6 Rel 𝐴
5 df-rel 5667 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 233 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5678 . . . . . 6 Rel (V × V)
8 dfrel2 6186 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 233 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3985 . . . 4 𝐴(V × V)
11 dfss 3923 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 233 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2796 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5800 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6186 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 233 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2785 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   = wceq 1569  Vcvv 3454  cin 3903  wss 3904   × cxp 5658  ccnv 5659  Rel wrel 5665
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5256  ax-pr 5403
This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1104  df-tru 1572  df-fal 1582  df-ex 1809  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-rab 3416  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4487  df-sn 4589  df-pr 4591  df-op 4595  df-br 5109  df-opab 5173  df-xp 5666  df-rel 5667  df-cnv 5668
This theorem is used by:  cnvcnv2  6190  cnvcnvssOLD  6192  cnvrescnv  6193  structcnvcnv  17219  strfv2d  17267  elcnvcnvintab  44336  relintab  44337  nonrel  44338  elcnvcnvlem  44353  cnvcnvintabd  44354  tposresg  49684
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