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Theorem cnvcnv 6189
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6139 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6139 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5858 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6104 . . . . . 6 Rel 𝐴
5 df-rel 5666 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 233 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5677 . . . . . 6 Rel (V × V)
8 dfrel2 6186 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 233 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3983 . . . 4 𝐴(V × V)
11 dfss 3921 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 233 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2796 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5799 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6186 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 233 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2785 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   = wceq 1570  Vcvv 3453  cin 3901  wss 3902   × cxp 5657  ccnv 5658  Rel wrel 5664
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2734  ax-sep 5255  ax-pr 5402
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-rab 3415  df-v 3455  df-dif 3905  df-un 3907  df-in 3909  df-ss 3919  df-nul 4283  df-if 4486  df-sn 4588  df-pr 4590  df-op 4594  df-br 5108  df-opab 5172  df-xp 5665  df-rel 5666  df-cnv 5667
This theorem is used by:  cnvcnv2  6190  cnvcnvssOLD  6192  cnvrescnv  6193  structcnvcnv  17249  strfv2d  17297  elcnvcnvintab  44409  relintab  44410  nonrel  44411  elcnvcnvlem  44426  cnvcnvintabd  44427  tposresg  49791
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