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Theorem cnvcnv 6180
Description: The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.)
Assertion
Ref Expression
cnvcnv 𝐴 = (𝐴 ∩ (V × V))

Proof of Theorem cnvcnv
StepHypRef Expression
1 cnvin 6130 . . 3 (𝐴(V × V)) = (𝐴(V × V))
2 cnvin 6130 . . . 4 (𝐴 ∩ (V × V)) = (𝐴(V × V))
32cnveqi 5848 . . 3 (𝐴 ∩ (V × V)) = (𝐴(V × V))
4 relcnv 6095 . . . . . 6 Rel 𝐴
5 df-rel 5656 . . . . . 6 (Rel 𝐴𝐴 ⊆ (V × V))
64, 5mpbi 232 . . . . 5 𝐴 ⊆ (V × V)
7 relxp 5667 . . . . . 6 Rel (V × V)
8 dfrel2 6177 . . . . . 6 (Rel (V × V) ↔ (V × V) = (V × V))
97, 8mpbi 232 . . . . 5 (V × V) = (V × V)
106, 9sseqtrri 3987 . . . 4 𝐴(V × V)
11 dfss 3925 . . . 4 (𝐴(V × V) ↔ 𝐴 = (𝐴(V × V)))
1210, 11mpbi 232 . . 3 𝐴 = (𝐴(V × V))
131, 3, 123eqtr4ri 2798 . 2 𝐴 = (𝐴 ∩ (V × V))
14 relinxp 5789 . . 3 Rel (𝐴 ∩ (V × V))
15 dfrel2 6177 . . 3 (Rel (𝐴 ∩ (V × V)) ↔ (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V)))
1614, 15mpbi 232 . 2 (𝐴 ∩ (V × V)) = (𝐴 ∩ (V × V))
1713, 16eqtri 2787 1 𝐴 = (𝐴 ∩ (V × V))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1562  Vcvv 3456  cin 3905  wss 3906   × cxp 5647  ccnv 5648  Rel wrel 5654
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1817  ax-4 1831  ax-5 1932  ax-6 1989  ax-7 2030  ax-8 2146  ax-9 2154  ax-ext 2736  ax-sep 5248  ax-pr 5392
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1101  df-tru 1565  df-fal 1575  df-ex 1802  df-sb 2093  df-clab 2743  df-cleq 2756  df-clel 2839  df-rab 3417  df-v 3458  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-nul 4288  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5103  df-opab 5165  df-xp 5655  df-rel 5656  df-cnv 5657
This theorem is referenced by:  cnvcnv2  6181  cnvcnvssOLD  6183  cnvrescnv  6184  structcnvcnv  17191  strfv2d  17239  elcnvcnvintab  44163  relintab  44164  nonrel  44165  elcnvcnvlem  44180  cnvcnvintabd  44181  tposresg  49504
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