Theorem f002 49782

Description: A function with an empty codomain must have empty domain. (Contributed by Zhi Wang, 1-Oct-2024.)

Hypothesis

Ref	Expression
f002.1	⊢ (𝜑 → 𝐹:𝐴⟶𝐵)

Assertion

Ref	Expression
f002	⊢ (𝜑 → (𝐵 = ∅ → 𝐴 = ∅))

Proof of Theorem f002

Step	Hyp	Ref	Expression
1		f002.1	. 2 ⊢ (𝜑 → 𝐹:𝐴⟶𝐵)
2		feq3 6682	. . 3 ⊢ (𝐵 = ∅ → (𝐹:𝐴⟶𝐵 ↔ 𝐹:𝐴⟶∅))
3		f00 6757	. . . 4 ⊢ (𝐹:𝐴⟶∅ ↔ (𝐹 = ∅ ∧ 𝐴 = ∅))
4	3	simprbi 503	. . 3 ⊢ (𝐹:𝐴⟶∅ → 𝐴 = ∅)
5	2, 4	biimtrdi 256	. 2 ⊢ (𝐵 = ∅ → (𝐹:𝐴⟶𝐵 → 𝐴 = ∅))
6	1, 5	syl5com 32	1 ⊢ (𝜑 → (𝐵 = ∅ → 𝐴 = ∅))

This proof depends on syntax axioms:   → wi 4   = wceq 1570  ∅c0 4279  ⟶wf 6529

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5251  ax-nul 5263  ax-pr 5398

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-mo 2564  df-clab 2739  df-cleq 2752  df-clel 2835  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-id 5550  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-fun 6535  df-fn 6536  df-f 6537

This theorem is used by:  func0g  50015  functhincfun  50375  fullthinc2  50377  thincciso  50379