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Theorem rnssi 5882
Description: Subclass inference for range. (Contributed by Peter Mazsa, 24-Sep-2022.)
Hypothesis
Ref Expression
rnssi.1 𝐴𝐵
Assertion
Ref Expression
rnssi ran 𝐴 ⊆ ran 𝐵

Proof of Theorem rnssi
StepHypRef Expression
1 rnssi.1 . 2 𝐴𝐵
2 rnss 5881 . 2 (𝐴𝐵 → ran 𝐴 ⊆ ran 𝐵)
31, 2ax-mp 5 1 ran 𝐴 ⊆ ran 𝐵
Colors of variables: wff setvar class
Syntax hints:  wss 3883  ran crn 5619
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2711
This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-3an 1094  df-tru 1550  df-fal 1560  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-clel 2814  df-rab 3392  df-v 3433  df-dif 3886  df-un 3888  df-ss 3900  df-nul 4262  df-if 4455  df-sn 4556  df-pr 4558  df-op 4562  df-br 5073  df-opab 5135  df-cnv 5626  df-dm 5628  df-rn 5629
This theorem is referenced by:  rnresss  5969  ssrnres  6129  fssres  6693  smores  8282  rnttrcl  9634  brdom4  10443  smobeth  10500  nqerf  10844  catcoppccl  18075  lern  18548  gsumzres  19875  gsumzaddlem  19887  gsumzadd  19888  dprdfadd  19988  txkgen  23635  dvlog  26633  perpln2  28797  pfxrn2  33019  fixssrn  36133  cnvrcl0  44069
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