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Theorem rnssi 5920
Description: Subclass inference for range. (Contributed by Peter Mazsa, 24-Sep-2022.)
Hypothesis
Ref Expression
rnssi.1 𝐴𝐵
Assertion
Ref Expression
rnssi ran 𝐴 ⊆ ran 𝐵

Proof of Theorem rnssi
StepHypRef Expression
1 rnssi.1 . 2 𝐴𝐵
2 rnss 5919 . 2 (𝐴𝐵 → ran 𝐴 ⊆ ran 𝐵)
31, 2ax-mp 5 1 ran 𝐴 ⊆ ran 𝐵
Colors of variables: wff setvar class
Syntax hints:  wss 3926  ran crn 5655
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2707
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2065  df-clab 2714  df-cleq 2727  df-clel 2809  df-rab 3416  df-v 3461  df-dif 3929  df-un 3931  df-ss 3943  df-nul 4309  df-if 4501  df-sn 4602  df-pr 4604  df-op 4608  df-br 5120  df-opab 5182  df-cnv 5662  df-dm 5664  df-rn 5665
This theorem is referenced by:  rnresss  6004  ssrnres  6167  fssres  6743  smores  8364  rnttrcl  9734  brdom4  10542  smobeth  10598  nqerf  10942  catcoppccl  18128  lern  18599  gsumzres  19888  gsumzaddlem  19900  gsumzadd  19901  dprdfadd  20001  txkgen  23588  dvlog  26610  perpln2  28636  pfxrn2  32861  fixssrn  35871  cnvrcl0  43596
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