Theorem f0dom0 6537

Description: A function is empty iff it has an empty domain. (Contributed by AV, 10-Feb-2019.)

Assertion

Ref	Expression
f0dom0	⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ ↔ 𝐹 = ∅))

Proof of Theorem f0dom0

Step	Hyp	Ref	Expression
1		feq2 6469	. . . 4 ⊢ (𝑋 = ∅ → (𝐹:𝑋⟶𝑌 ↔ 𝐹:∅⟶𝑌))
2		f0bi 6536	. . . . 5 ⊢ (𝐹:∅⟶𝑌 ↔ 𝐹 = ∅)
3	2	biimpi 219	. . . 4 ⊢ (𝐹:∅⟶𝑌 → 𝐹 = ∅)
4	1, 3	syl6bi 256	. . 3 ⊢ (𝑋 = ∅ → (𝐹:𝑋⟶𝑌 → 𝐹 = ∅))
5	4	com12 32	. 2 ⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ → 𝐹 = ∅))
6		feq1 6468	. . . 4 ⊢ (𝐹 = ∅ → (𝐹:𝑋⟶𝑌 ↔ ∅:𝑋⟶𝑌))
7		dm0 5754	. . . . 5 ⊢ dom ∅ = ∅
8		fdm 6495	. . . . 5 ⊢ (∅:𝑋⟶𝑌 → dom ∅ = 𝑋)
9	7, 8	syl5reqr 2848	. . . 4 ⊢ (∅:𝑋⟶𝑌 → 𝑋 = ∅)
10	6, 9	syl6bi 256	. . 3 ⊢ (𝐹 = ∅ → (𝐹:𝑋⟶𝑌 → 𝑋 = ∅))
11	10	com12 32	. 2 ⊢ (𝐹:𝑋⟶𝑌 → (𝐹 = ∅ → 𝑋 = ∅))
12	5, 11	impbid 215	1 ⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ ↔ 𝐹 = ∅))

Syntax hints:   → wi 4   ↔ wb 209   = wceq 1538  ∅c0 4243  dom cdm 5519  ⟶wf 6320

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2113  ax-9 2121  ax-10 2142  ax-11 2158  ax-12 2175  ax-ext 2770  ax-sep 5167  ax-nul 5174  ax-pr 5295

This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-3an 1086  df-tru 1541  df-ex 1782  df-nf 1786  df-sb 2070  df-mo 2598  df-eu 2629  df-clab 2777  df-cleq 2791  df-clel 2870  df-nfc 2938  df-ral 3111  df-rex 3112  df-v 3443  df-dif 3884  df-un 3886  df-in 3888  df-ss 3898  df-nul 4244  df-if 4426  df-sn 4526  df-pr 4528  df-op 4532  df-br 5031  df-opab 5093  df-id 5425  df-xp 5525  df-rel 5526  df-cnv 5527  df-co 5528  df-dm 5529  df-rn 5530  df-fun 6326  df-fn 6327  df-f 6328

This theorem is referenced by:  pfxn0  14039  elfrlmbasn0  20452  mavmulsolcl  21156