Theorem f0dom0 6327

Description: A function is empty iff it has an empty domain. (Contributed by AV, 10-Feb-2019.)

Assertion

Ref	Expression
f0dom0	⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ ↔ 𝐹 = ∅))

Proof of Theorem f0dom0

Step	Hyp	Ref	Expression
1		feq2 6261	. . . 4 ⊢ (𝑋 = ∅ → (𝐹:𝑋⟶𝑌 ↔ 𝐹:∅⟶𝑌))
2		f0bi 6326	. . . . 5 ⊢ (𝐹:∅⟶𝑌 ↔ 𝐹 = ∅)
3	2	biimpi 208	. . . 4 ⊢ (𝐹:∅⟶𝑌 → 𝐹 = ∅)
4	1, 3	syl6bi 245	. . 3 ⊢ (𝑋 = ∅ → (𝐹:𝑋⟶𝑌 → 𝐹 = ∅))
5	4	com12 32	. 2 ⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ → 𝐹 = ∅))
6		feq1 6260	. . . 4 ⊢ (𝐹 = ∅ → (𝐹:𝑋⟶𝑌 ↔ ∅:𝑋⟶𝑌))
7		dm0 5572	. . . . 5 ⊢ dom ∅ = ∅
8		fdm 6287	. . . . 5 ⊢ (∅:𝑋⟶𝑌 → dom ∅ = 𝑋)
9	7, 8	syl5reqr 2877	. . . 4 ⊢ (∅:𝑋⟶𝑌 → 𝑋 = ∅)
10	6, 9	syl6bi 245	. . 3 ⊢ (𝐹 = ∅ → (𝐹:𝑋⟶𝑌 → 𝑋 = ∅))
11	10	com12 32	. 2 ⊢ (𝐹:𝑋⟶𝑌 → (𝐹 = ∅ → 𝑋 = ∅))
12	5, 11	impbid 204	1 ⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ ↔ 𝐹 = ∅))

Syntax hints:   → wi 4   ↔ wb 198   = wceq 1658  ∅c0 4145  dom cdm 5343  ⟶wf 6120

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1896  ax-4 1910  ax-5 2011  ax-6 2077  ax-7 2114  ax-9 2175  ax-10 2194  ax-11 2209  ax-12 2222  ax-13 2391  ax-ext 2804  ax-sep 5006  ax-nul 5014  ax-pr 5128

This theorem depends on definitions:  df-bi 199  df-an 387  df-or 881  df-3an 1115  df-tru 1662  df-ex 1881  df-nf 1885  df-sb 2070  df-mo 2606  df-eu 2641  df-clab 2813  df-cleq 2819  df-clel 2822  df-nfc 2959  df-ral 3123  df-rex 3124  df-rab 3127  df-v 3417  df-dif 3802  df-un 3804  df-in 3806  df-ss 3813  df-nul 4146  df-if 4308  df-sn 4399  df-pr 4401  df-op 4405  df-br 4875  df-opab 4937  df-id 5251  df-xp 5349  df-rel 5350  df-cnv 5351  df-co 5352  df-dm 5353  df-rn 5354  df-fun 6126  df-fn 6127  df-f 6128

This theorem is referenced by:  swrdn0OLD  13718  pfxn0  13766  elfrlmbasn0  20470  mavmulsolcl  20726