Theorem feq2 6496

Description: Equality theorem for functions. (Contributed by NM, 1-Aug-1994.)

Assertion

Ref	Expression
feq2	⊢ (𝐴 = 𝐵 → (𝐹:𝐴⟶𝐶 ↔ 𝐹:𝐵⟶𝐶))

Proof of Theorem feq2

Step	Hyp	Ref	Expression
1		fneq2 6445	. . 3 ⊢ (𝐴 = 𝐵 → (𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐵))
2	1	anbi1d 631	. 2 ⊢ (𝐴 = 𝐵 → ((𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐶) ↔ (𝐹 Fn 𝐵 ∧ ran 𝐹 ⊆ 𝐶)))
3		df-f 6359	. 2 ⊢ (𝐹:𝐴⟶𝐶 ↔ (𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐶))
4		df-f 6359	. 2 ⊢ (𝐹:𝐵⟶𝐶 ↔ (𝐹 Fn 𝐵 ∧ ran 𝐹 ⊆ 𝐶))
5	2, 3, 4	3bitr4g 316	1 ⊢ (𝐴 = 𝐵 → (𝐹:𝐴⟶𝐶 ↔ 𝐹:𝐵⟶𝐶))

Syntax hints:   → wi 4   ↔ wb 208   ∧ wa 398   = wceq 1537   ⊆ wss 3936  ran crn 5556   Fn wfn 6350  ⟶wf 6351

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-9 2124  ax-ext 2793

This theorem depends on definitions:  df-bi 209  df-an 399  df-ex 1781  df-cleq 2814  df-fn 6358  df-f 6359

This theorem is referenced by:  feq23  6498  feq2d  6500  feq2i  6506  f00  6561  f0dom0  6563  f1eq2  6571  fressnfv  6922  mapvalg  8416  map0g  8448  ac6sfi  8762  cofsmo  9691  axcc4dom  9863  ac6sg  9910  isghm  18358  pjdm2  20855  cmpcovf  21999  ulmval  24968  measval  31457  isrnmeas  31459  poseq  33095  soseq  33096  elno2  33161  noreson  33167  bj-finsumval0  34570  mbfresfi  34953  stoweidlem62  42367  hoidmvval0b  42892  vonioo  42984  vonicc  42987