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Theorem imadifssranOLD 6198
Description: Obsolete version of imadifssran 6197 as of 10-Jul-2026. (Contributed by AV, 4-Oct-2025.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
imadifssranOLD ((Rel 𝐹𝐴 ⊆ dom 𝐹) → ((𝐹 “ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴) → ran 𝐹 = ran (𝐹𝐴)))

Proof of Theorem imadifssranOLD
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 df-ima 5668 . . 3 (𝐹 “ (dom 𝐹𝐴)) = ran (𝐹 ↾ (dom 𝐹𝐴))
21sseq1i 3959 . 2 ((𝐹 “ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴) ↔ ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴))
3 ssel 3925 . . . . . . 7 (ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴) → (𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)))
4 resdm 6019 . . . . . . . . . . . . . . 15 (Rel 𝐹 → (𝐹 ↾ dom 𝐹) = 𝐹)
54eqcomd 2766 . . . . . . . . . . . . . 14 (Rel 𝐹𝐹 = (𝐹 ↾ dom 𝐹))
65adantr 486 . . . . . . . . . . . . 13 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → 𝐹 = (𝐹 ↾ dom 𝐹))
76rneqd 5922 . . . . . . . . . . . 12 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → ran 𝐹 = ran (𝐹 ↾ dom 𝐹))
87eleq2d 2846 . . . . . . . . . . 11 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → (𝑦 ∈ ran 𝐹𝑦 ∈ ran (𝐹 ↾ dom 𝐹)))
9 undif 4438 . . . . . . . . . . . . . . . . . . . 20 (𝐴 ⊆ dom 𝐹 ↔ (𝐴 ∪ (dom 𝐹𝐴)) = dom 𝐹)
109biimpi 219 . . . . . . . . . . . . . . . . . . 19 (𝐴 ⊆ dom 𝐹 → (𝐴 ∪ (dom 𝐹𝐴)) = dom 𝐹)
1110eqcomd 2766 . . . . . . . . . . . . . . . . . 18 (𝐴 ⊆ dom 𝐹 → dom 𝐹 = (𝐴 ∪ (dom 𝐹𝐴)))
1211reseq2d 5972 . . . . . . . . . . . . . . . . 17 (𝐴 ⊆ dom 𝐹 → (𝐹 ↾ dom 𝐹) = (𝐹 ↾ (𝐴 ∪ (dom 𝐹𝐴))))
13 resundi 5986 . . . . . . . . . . . . . . . . 17 (𝐹 ↾ (𝐴 ∪ (dom 𝐹𝐴))) = ((𝐹𝐴) ∪ (𝐹 ↾ (dom 𝐹𝐴)))
1412, 13eqtrdi 2811 . . . . . . . . . . . . . . . 16 (𝐴 ⊆ dom 𝐹 → (𝐹 ↾ dom 𝐹) = ((𝐹𝐴) ∪ (𝐹 ↾ (dom 𝐹𝐴))))
1514rneqd 5922 . . . . . . . . . . . . . . 15 (𝐴 ⊆ dom 𝐹 → ran (𝐹 ↾ dom 𝐹) = ran ((𝐹𝐴) ∪ (𝐹 ↾ (dom 𝐹𝐴))))
16 rnun 6136 . . . . . . . . . . . . . . 15 ran ((𝐹𝐴) ∪ (𝐹 ↾ (dom 𝐹𝐴))) = (ran (𝐹𝐴) ∪ ran (𝐹 ↾ (dom 𝐹𝐴)))
1715, 16eqtrdi 2811 . . . . . . . . . . . . . 14 (𝐴 ⊆ dom 𝐹 → ran (𝐹 ↾ dom 𝐹) = (ran (𝐹𝐴) ∪ ran (𝐹 ↾ (dom 𝐹𝐴))))
1817eleq2d 2846 . . . . . . . . . . . . 13 (𝐴 ⊆ dom 𝐹 → (𝑦 ∈ ran (𝐹 ↾ dom 𝐹) ↔ 𝑦 ∈ (ran (𝐹𝐴) ∪ ran (𝐹 ↾ (dom 𝐹𝐴)))))
19 elun 4100 . . . . . . . . . . . . 13 (𝑦 ∈ (ran (𝐹𝐴) ∪ ran (𝐹 ↾ (dom 𝐹𝐴))) ↔ (𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴))))
2018, 19bitrdi 290 . . . . . . . . . . . 12 (𝐴 ⊆ dom 𝐹 → (𝑦 ∈ ran (𝐹 ↾ dom 𝐹) ↔ (𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)))))
2120adantl 487 . . . . . . . . . . 11 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → (𝑦 ∈ ran (𝐹 ↾ dom 𝐹) ↔ (𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)))))
228, 21bitrd 282 . . . . . . . . . 10 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → (𝑦 ∈ ran 𝐹 ↔ (𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)))))
2322adantl 487 . . . . . . . . 9 (((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) ∧ (Rel 𝐹𝐴 ⊆ dom 𝐹)) → (𝑦 ∈ ran 𝐹 ↔ (𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)))))
24 pm2.27 43 . . . . . . . . . . . 12 (𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → ((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)))
2524jao1i 872 . . . . . . . . . . 11 ((𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴))) → ((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)))
2625com12 33 . . . . . . . . . 10 ((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) → ((𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴))) → 𝑦 ∈ ran (𝐹𝐴)))
2726adantr 486 . . . . . . . . 9 (((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) ∧ (Rel 𝐹𝐴 ⊆ dom 𝐹)) → ((𝑦 ∈ ran (𝐹𝐴) ∨ 𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴))) → 𝑦 ∈ ran (𝐹𝐴)))
2823, 27sylbid 243 . . . . . . . 8 (((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) ∧ (Rel 𝐹𝐴 ⊆ dom 𝐹)) → (𝑦 ∈ ran 𝐹𝑦 ∈ ran (𝐹𝐴)))
2928ex 418 . . . . . . 7 ((𝑦 ∈ ran (𝐹 ↾ (dom 𝐹𝐴)) → 𝑦 ∈ ran (𝐹𝐴)) → ((Rel 𝐹𝐴 ⊆ dom 𝐹) → (𝑦 ∈ ran 𝐹𝑦 ∈ ran (𝐹𝐴))))
303, 29syl 18 . . . . . 6 (ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴) → ((Rel 𝐹𝐴 ⊆ dom 𝐹) → (𝑦 ∈ ran 𝐹𝑦 ∈ ran (𝐹𝐴))))
3130impcom 413 . . . . 5 (((Rel 𝐹𝐴 ⊆ dom 𝐹) ∧ ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴)) → (𝑦 ∈ ran 𝐹𝑦 ∈ ran (𝐹𝐴)))
3231ssrdv 3937 . . . 4 (((Rel 𝐹𝐴 ⊆ dom 𝐹) ∧ ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴)) → ran 𝐹 ⊆ ran (𝐹𝐴))
33 rnresss 6010 . . . . 5 ran (𝐹𝐴) ⊆ ran 𝐹
3433a1i 11 . . . 4 (((Rel 𝐹𝐴 ⊆ dom 𝐹) ∧ ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴)) → ran (𝐹𝐴) ⊆ ran 𝐹)
3532, 34eqssd 3948 . . 3 (((Rel 𝐹𝐴 ⊆ dom 𝐹) ∧ ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴)) → ran 𝐹 = ran (𝐹𝐴))
3635ex 418 . 2 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → (ran (𝐹 ↾ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴) → ran 𝐹 = ran (𝐹𝐴)))
372, 36biimtrid 245 1 ((Rel 𝐹𝐴 ⊆ dom 𝐹) → ((𝐹 “ (dom 𝐹𝐴)) ⊆ ran (𝐹𝐴) → ran 𝐹 = ran (𝐹𝐴)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wa 401  wo 861   = wceq 1570  wcel 2145  cdif 3896  cun 3897  wss 3899  dom cdm 5655  ran crn 5656  cres 5657  cima 5658  Rel wrel 5660
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5251  ax-pr 5398
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-xp 5661  df-rel 5662  df-cnv 5663  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668
This theorem is used by: (None)
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