Proof of Theorem nvo2
| Step | Hyp | Ref
| Expression |
| 1 | | simpr 490 |
. . . . . 6
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → (𝐵 ∘ 𝐵) ⊆ I ) |
| 2 | | simpl 488 |
. . . . . . . 8
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → 𝐵:𝑋⟶𝑋) |
| 3 | | frn 6745 |
. . . . . . . 8
⊢ (𝐵:𝑋⟶𝑋 → ran 𝐵 ⊆ 𝑋) |
| 4 | 2, 3 | syl 18 |
. . . . . . 7
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ran 𝐵 ⊆ 𝑋) |
| 5 | | fdm 6747 |
. . . . . . . 8
⊢ (𝐵:𝑋⟶𝑋 → dom 𝐵 = 𝑋) |
| 6 | 2, 5 | syl 18 |
. . . . . . 7
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → dom 𝐵 = 𝑋) |
| 7 | 4, 6 | sseqtrrd 3950 |
. . . . . 6
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ran 𝐵 ⊆ dom 𝐵) |
| 8 | 1, 7 | jca 521 |
. . . . 5
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ((𝐵 ∘ 𝐵) ⊆ I ∧ ran 𝐵 ⊆ dom 𝐵)) |
| 9 | | cossidcnvss 38216 |
. . . . 5
⊢ (((𝐵 ∘ 𝐵) ⊆ I ∧ ran 𝐵 ⊆ dom 𝐵) ↔ (◡𝐵 ⊆ 𝐵 ∧ (𝐵 ∘ ◡𝐵) ⊆ I )) |
| 10 | 8, 9 | sylib 221 |
. . . 4
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → (◡𝐵 ⊆ 𝐵 ∧ (𝐵 ∘ ◡𝐵) ⊆ I )) |
| 11 | 10 | simpld 500 |
. . 3
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ◡𝐵 ⊆ 𝐵) |
| 12 | | frel 6743 |
. . . . . 6
⊢ (𝐵:𝑋⟶𝑋 → Rel 𝐵) |
| 13 | 2, 12 | syl 18 |
. . . . 5
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → Rel 𝐵) |
| 14 | | dfrel2 6197 |
. . . . 5
⊢ (Rel
𝐵 ↔ ◡◡𝐵 = 𝐵) |
| 15 | 13, 14 | sylib 221 |
. . . 4
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ◡◡𝐵 = 𝐵) |
| 16 | | cnvss 5860 |
. . . . 5
⊢ (◡𝐵 ⊆ 𝐵 → ◡◡𝐵 ⊆ ◡𝐵) |
| 17 | 11, 16 | syl 18 |
. . . 4
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ◡◡𝐵 ⊆ ◡𝐵) |
| 18 | 15, 17 | eqsstrrd 3948 |
. . 3
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → 𝐵 ⊆ ◡𝐵) |
| 19 | 11, 18 | eqssd 3930 |
. 2
⊢ ((𝐵:𝑋⟶𝑋 ∧ (𝐵 ∘ 𝐵) ⊆ I ) → ◡𝐵 = 𝐵) |
| 20 | | simpr 490 |
. . . . . 6
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → ◡𝐵 = 𝐵) |
| 21 | 20 | eqimssd 3969 |
. . . . 5
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → ◡𝐵 ⊆ 𝐵) |
| 22 | | simpl 488 |
. . . . . . 7
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → 𝐵:𝑋⟶𝑋) |
| 23 | | ffun 6740 |
. . . . . . 7
⊢ (𝐵:𝑋⟶𝑋 → Fun 𝐵) |
| 24 | 22, 23 | syl 18 |
. . . . . 6
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → Fun 𝐵) |
| 25 | | df-fun 6566 |
. . . . . . 7
⊢ (Fun
𝐵 ↔ (Rel 𝐵 ∧ (𝐵 ∘ ◡𝐵) ⊆ I )) |
| 26 | 25 | simprbi 503 |
. . . . . 6
⊢ (Fun
𝐵 → (𝐵 ∘ ◡𝐵) ⊆ I ) |
| 27 | 24, 26 | syl 18 |
. . . . 5
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → (𝐵 ∘ ◡𝐵) ⊆ I ) |
| 28 | 21, 27 | jca 521 |
. . . 4
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → (◡𝐵 ⊆ 𝐵 ∧ (𝐵 ∘ ◡𝐵) ⊆ I )) |
| 29 | 28, 9 | sylibr 237 |
. . 3
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → ((𝐵 ∘ 𝐵) ⊆ I ∧ ran 𝐵 ⊆ dom 𝐵)) |
| 30 | 29 | simpld 500 |
. 2
⊢ ((𝐵:𝑋⟶𝑋 ∧ ◡𝐵 = 𝐵) → (𝐵 ∘ 𝐵) ⊆ I ) |
| 31 | 19, 30 | impbida 813 |
1
⊢ (𝐵:𝑋⟶𝑋 → ((𝐵 ∘ 𝐵) ⊆ I ↔ ◡𝐵 = 𝐵)) |