Theorem recseq 8419

Description: Equality theorem for recs. (Contributed by Stefan O'Rear, 18-Jan-2015.)

Assertion

Ref	Expression
recseq	⊢ (𝐹 = 𝐺 → recs(𝐹) = recs(𝐺))

Proof of Theorem recseq

Step	Hyp	Ref	Expression
1		wrecseq3 8373	. 2 ⊢ (𝐹 = 𝐺 → wrecs( E , On, 𝐹) = wrecs( E , On, 𝐺))
2		df-recs 8417	. 2 ⊢ recs(𝐹) = wrecs( E , On, 𝐹)
3		df-recs 8417	. 2 ⊢ recs(𝐺) = wrecs( E , On, 𝐺)
4	1, 2, 3	3eqtr4g 2823	1 ⊢ (𝐹 = 𝐺 → recs(𝐹) = recs(𝐺))

This proof depends on syntax axioms:   → wi 4   = wceq 1570   E cep 5557  Oncon0 6388  wrecscwrecs 8367  recscrecs 8416

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ral 3081  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4841  df-uni 4873  df-br 5109  df-opab 5174  df-xp 5664  df-cnv 5666  df-co 5667  df-dm 5668  df-rn 5669  df-res 5670  df-ima 5671  df-pred 6330  df-iota 6520  df-fv 6574  df-ov 7454  df-frecs 8337  df-wrecs 8368  df-recs 8417

This theorem is used by:  rdgeq1  8457  rdgeq2  8458  dfoi  9542  oieq1  9543  oieq2  9544  ordtypecbv  9548  dfac12r  10264  zorn2g  10620  ttukey2g  10633  csbrdgg  38520  aomclem3  44324  aomclem8  44329