Theorem zorn2g 10594

Description: Zorn's Lemma of [Monk1] p. 117. This version of zorn2 10597 avoids the Axiom of Choice by assuming that 𝐴 is well-orderable. (Contributed by NM, 6-Apr-1997.) (Revised by Mario Carneiro, 9-May-2015.)

Assertion

Ref	Expression
zorn2g	⊢ ((𝐴 ∈ dom card ∧ 𝑅 Po 𝐴 ∧ ∀𝑤((𝑤 ⊆ 𝐴 ∧ 𝑅 Or 𝑤) → ∃𝑥 ∈ 𝐴 ∀𝑧 ∈ 𝑤 (𝑧𝑅𝑥 ∨ 𝑧 = 𝑥))) → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 ¬ 𝑥𝑅𝑦)

Distinct variable groups:   𝑥,𝑦,𝑧,𝑤,𝑅   𝑥,𝐴,𝑦,𝑧,𝑤

Proof of Theorem zorn2g

Dummy variables 𝑣 𝑢 𝑔 ℎ 𝑡 𝑠 𝑟 𝑞 𝑑 𝑘 𝑚 𝑛 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		breq1 5109	. . . . . . . . 9 ⊢ (𝑔 = 𝑘 → (𝑔𝑞𝑛 ↔ 𝑘𝑞𝑛))
2	1	notbid 321	. . . . . . . 8 ⊢ (𝑔 = 𝑘 → (¬ 𝑔𝑞𝑛 ↔ ¬ 𝑘𝑞𝑛))
3	2	cbvralvw 3244	. . . . . . 7 ⊢ (∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑛)
4		breq2 5110	. . . . . . . . 9 ⊢ (𝑛 = 𝑚 → (𝑘𝑞𝑛 ↔ 𝑘𝑞𝑚))
5	4	notbid 321	. . . . . . . 8 ⊢ (𝑛 = 𝑚 → (¬ 𝑘𝑞𝑛 ↔ ¬ 𝑘𝑞𝑚))
6	5	ralbidv 3189	. . . . . . 7 ⊢ (𝑛 = 𝑚 → (∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑛 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
7	3, 6	bitrid 286	. . . . . 6 ⊢ (𝑛 = 𝑚 → (∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
8	7	cbvriotavw 7397	. . . . 5 ⊢ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛) = (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚)
9		rneq 5923	. . . . . . . 8 ⊢ (ℎ = 𝑑 → ran ℎ = ran 𝑑)
10	9	raleqdv 3323	. . . . . . 7 ⊢ (ℎ = 𝑑 → (∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣 ↔ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣))
11	10	rabbidv 3423	. . . . . 6 ⊢ (ℎ = 𝑑 → {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} = {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣})
12	11	raleqdv 3323	. . . . . 6 ⊢ (ℎ = 𝑑 → (∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
13	11, 12	riotaeqbidv 7390	. . . . 5 ⊢ (ℎ = 𝑑 → (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚) = (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
14	8, 13	eqtrid 2810	. . . 4 ⊢ (ℎ = 𝑑 → (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛) = (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
15	14	cbvmptv 5212	. . 3 ⊢ (ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛)) = (𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
16		recseq 8395	. . 3 ⊢ ((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛)) = (𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚)) → recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) = recs((𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))))
17	15, 16	ax-mp 5	. 2 ⊢ recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) = recs((𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚)))
18		breq1 5109	. . . . 5 ⊢ (𝑞 = 𝑠 → (𝑞𝑅𝑣 ↔ 𝑠𝑅𝑣))
19	18	cbvralvw 3244	. . . 4 ⊢ (∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣 ↔ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑣)
20		breq2 5110	. . . . 5 ⊢ (𝑣 = 𝑟 → (𝑠𝑅𝑣 ↔ 𝑠𝑅𝑟))
21	20	ralbidv 3189	. . . 4 ⊢ (𝑣 = 𝑟 → (∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑣 ↔ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑟))
22	19, 21	bitrid 286	. . 3 ⊢ (𝑣 = 𝑟 → (∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣 ↔ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑟))
23	22	cbvrabv 3426	. 2 ⊢ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} = {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑟}
24		eqid 2763	. 2 ⊢ {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑢)𝑠𝑅𝑟} = {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑢)𝑠𝑅𝑟}
25		eqid 2763	. 2 ⊢ {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑡)𝑠𝑅𝑟} = {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑡)𝑠𝑅𝑟}
26	17, 23, 24, 25	zorn2lem7 10593	1 ⊢ ((𝐴 ∈ dom card ∧ 𝑅 Po 𝐴 ∧ ∀𝑤((𝑤 ⊆ 𝐴 ∧ 𝑅 Or 𝑤) → ∃𝑥 ∈ 𝐴 ∀𝑧 ∈ 𝑤 (𝑧𝑅𝑥 ∨ 𝑧 = 𝑥))) → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 ¬ 𝑥𝑅𝑦)

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 401   ∨ wo 861   ∧ w3a 1103  ∀wal 1567   = wceq 1569   ∈ wcel 2146  ∀wral 3080  ∃wrex 3090  {crab 3416  Vcvv 3454   ⊆ wss 3900   class class class wbr 5106   ↦ cmpt 5189   Po wpo 5561   Or wor 5562  dom cdm 5655  ran crn 5656   “ cima 5658  ℩crio 7386  recscrecs 8392  cardccrd 10029

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2196  ax-12 2215  ax-ext 2735  ax-rep 5235  ax-sep 5252  ax-nul 5263  ax-pow 5331  ax-pr 5395  ax-un 7761

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2101  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3081  df-rex 3091  df-rmo 3369  df-reu 3370  df-rab 3417  df-v 3456  df-sbc 3743  df-csb 3852  df-ss 3901  df-pss 4017  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-pw 4562  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-int 4911  df-iun 4956  df-br 5107  df-opab 5171  df-mpt 5190  df-tr 5216  df-id 5550  df-eprel 5555  df-po 5563  df-so 5564  df-fr 5608  df-se 5609  df-we 5610  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668  df-pred 6311  df-ord 6372  df-on 6373  df-suc 6375  df-iota 6501  df-fun 6549  df-fn 6550  df-f 6551  df-f1 6552  df-fo 6553  df-f1o 6554  df-fv 6555  df-isom 6556  df-riota 7387  df-ov 7433  df-2nd 8012  df-frecs 8313  df-wrecs 8344  df-recs 8393  df-en 8988  df-card 10033

This theorem is used by:  zorng  10595  zorn2  10597