Theorem zorn2g 10502

Description: Zorn's Lemma of [Monk1] p. 117. This version of zorn2 10505 avoids the Axiom of Choice by assuming that 𝐴 is well-orderable. (Contributed by NM, 6-Apr-1997.) (Revised by Mario Carneiro, 9-May-2015.)

Assertion

Ref	Expression
zorn2g	⊢ ((𝐴 ∈ dom card ∧ 𝑅 Po 𝐴 ∧ ∀𝑤((𝑤 ⊆ 𝐴 ∧ 𝑅 Or 𝑤) → ∃𝑥 ∈ 𝐴 ∀𝑧 ∈ 𝑤 (𝑧𝑅𝑥 ∨ 𝑧 = 𝑥))) → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 ¬ 𝑥𝑅𝑦)

Distinct variable groups:   𝑥,𝑦,𝑧,𝑤,𝑅   𝑥,𝐴,𝑦,𝑧,𝑤

Proof of Theorem zorn2g

Dummy variables 𝑣 𝑢 𝑔 ℎ 𝑡 𝑠 𝑟 𝑞 𝑑 𝑘 𝑚 𝑛 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		breq1 5114	. . . . . . . . 9 ⊢ (𝑔 = 𝑘 → (𝑔𝑞𝑛 ↔ 𝑘𝑞𝑛))
2	1	notbid 321	. . . . . . . 8 ⊢ (𝑔 = 𝑘 → (¬ 𝑔𝑞𝑛 ↔ ¬ 𝑘𝑞𝑛))
3	2	cbvralvw 3245	. . . . . . 7 ⊢ (∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑛)
4		breq2 5115	. . . . . . . . 9 ⊢ (𝑛 = 𝑚 → (𝑘𝑞𝑛 ↔ 𝑘𝑞𝑚))
5	4	notbid 321	. . . . . . . 8 ⊢ (𝑛 = 𝑚 → (¬ 𝑘𝑞𝑛 ↔ ¬ 𝑘𝑞𝑚))
6	5	ralbidv 3190	. . . . . . 7 ⊢ (𝑛 = 𝑚 → (∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑛 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
7	3, 6	bitrid 286	. . . . . 6 ⊢ (𝑛 = 𝑚 → (∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
8	7	cbvriotavw 7386	. . . . 5 ⊢ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛) = (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚)
9		rneq 5928	. . . . . . . 8 ⊢ (ℎ = 𝑑 → ran ℎ = ran 𝑑)
10	9	raleqdv 3325	. . . . . . 7 ⊢ (ℎ = 𝑑 → (∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣 ↔ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣))
11	10	rabbidv 3425	. . . . . 6 ⊢ (ℎ = 𝑑 → {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} = {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣})
12	11	raleqdv 3325	. . . . . 6 ⊢ (ℎ = 𝑑 → (∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚 ↔ ∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
13	11, 12	riotaeqbidv 7379	. . . . 5 ⊢ (ℎ = 𝑑 → (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚) = (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
14	8, 13	eqtrid 2812	. . . 4 ⊢ (ℎ = 𝑑 → (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛) = (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
15	14	cbvmptv 5217	. . 3 ⊢ (ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛)) = (𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))
16		recseq 8366	. . 3 ⊢ ((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛)) = (𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚)) → recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) = recs((𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚))))
17	15, 16	ax-mp 5	. 2 ⊢ recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) = recs((𝑑 ∈ V ↦ (℩𝑚 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣}∀𝑘 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} ¬ 𝑘𝑞𝑚)))
18		breq1 5114	. . . . 5 ⊢ (𝑞 = 𝑠 → (𝑞𝑅𝑣 ↔ 𝑠𝑅𝑣))
19	18	cbvralvw 3245	. . . 4 ⊢ (∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣 ↔ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑣)
20		breq2 5115	. . . . 5 ⊢ (𝑣 = 𝑟 → (𝑠𝑅𝑣 ↔ 𝑠𝑅𝑟))
21	20	ralbidv 3190	. . . 4 ⊢ (𝑣 = 𝑟 → (∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑣 ↔ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑟))
22	19, 21	bitrid 286	. . 3 ⊢ (𝑣 = 𝑟 → (∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣 ↔ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑟))
23	22	cbvrabv 3428	. 2 ⊢ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran 𝑑 𝑞𝑅𝑣} = {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ ran 𝑑 𝑠𝑅𝑟}
24		eqid 2765	. 2 ⊢ {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑢)𝑠𝑅𝑟} = {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑢)𝑠𝑅𝑟}
25		eqid 2765	. 2 ⊢ {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑡)𝑠𝑅𝑟} = {𝑟 ∈ 𝐴 ∣ ∀𝑠 ∈ (recs((ℎ ∈ V ↦ (℩𝑛 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣}∀𝑔 ∈ {𝑣 ∈ 𝐴 ∣ ∀𝑞 ∈ ran ℎ 𝑞𝑅𝑣} ¬ 𝑔𝑞𝑛))) “ 𝑡)𝑠𝑅𝑟}
26	17, 23, 24, 25	zorn2lem7 10501	1 ⊢ ((𝐴 ∈ dom card ∧ 𝑅 Po 𝐴 ∧ ∀𝑤((𝑤 ⊆ 𝐴 ∧ 𝑅 Or 𝑤) → ∃𝑥 ∈ 𝐴 ∀𝑧 ∈ 𝑤 (𝑧𝑅𝑥 ∨ 𝑧 = 𝑥))) → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 ¬ 𝑥𝑅𝑦)

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 401   ∨ wo 861   ∧ w3a 1103  ∀wal 1568   = wceq 1570   ∈ wcel 2146  ∀wral 3081  ∃wrex 3091  {crab 3418  Vcvv 3457   ⊆ wss 3906   class class class wbr 5111   ↦ cmpt 5194   Po wpo 5569   Or wor 5570  dom cdm 5663  ran crn 5664   “ cima 5666  ℩crio 7375  recscrecs 8363  cardccrd 9937

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2195  ax-12 2216  ax-ext 2737  ax-rep 5240  ax-sep 5259  ax-nul 5271  ax-pow 5338  ax-pr 5406  ax-un 7742

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2569  df-eu 2599  df-clab 2744  df-cleq 2757  df-clel 2840  df-nfc 2914  df-ne 2961  df-ral 3082  df-rex 3092  df-rmo 3371  df-reu 3372  df-rab 3419  df-v 3459  df-sbc 3747  df-csb 3855  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-pss 3926  df-nul 4287  df-if 4490  df-pw 4566  df-sn 4592  df-pr 4594  df-op 4598  df-uni 4875  df-int 4915  df-iun 4960  df-br 5112  df-opab 5176  df-mpt 5195  df-tr 5221  df-id 5558  df-eprel 5563  df-po 5571  df-so 5572  df-fr 5616  df-se 5617  df-we 5618  df-xp 5669  df-rel 5670  df-cnv 5671  df-co 5672  df-dm 5673  df-rn 5674  df-res 5675  df-ima 5676  df-pred 6306  df-ord 6367  df-on 6368  df-suc 6370  df-iota 6496  df-fun 6542  df-fn 6543  df-f 6544  df-f1 6545  df-fo 6546  df-f1o 6547  df-fv 6548  df-isom 6549  df-riota 7376  df-ov 7422  df-2nd 7993  df-frecs 8284  df-wrecs 8315  df-recs 8364  df-en 8950  df-card 9941

This theorem is used by:  zorng  10503  zorn2  10505