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Theorem fconstmpt 4820
Description: Representation of a constant function using the mapping operation. (Note that 𝑥 cannot appear free in 𝐵.) (Contributed by NM, 12-Oct-1999.) (Revised by Mario Carneiro, 16-Nov-2013.)
Assertion
Ref Expression
fconstmpt (𝐴 × {𝐵}) = (𝑥𝐴𝐵)
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵

Proof of Theorem fconstmpt
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 velsn 3725 . . . 4 (𝑦 ∈ {𝐵} ↔ 𝑦 = 𝐵)
21anbi2i 461 . . 3 ((𝑥𝐴𝑦 ∈ {𝐵}) ↔ (𝑥𝐴𝑦 = 𝐵))
32opabbii 4196 . 2 {⟨𝑥, 𝑦⟩ ∣ (𝑥𝐴𝑦 ∈ {𝐵})} = {⟨𝑥, 𝑦⟩ ∣ (𝑥𝐴𝑦 = 𝐵)}
4 df-xp 4778 . 2 (𝐴 × {𝐵}) = {⟨𝑥, 𝑦⟩ ∣ (𝑥𝐴𝑦 ∈ {𝐵})}
5 df-mpt 4192 . 2 (𝑥𝐴𝐵) = {⟨𝑥, 𝑦⟩ ∣ (𝑥𝐴𝑦 = 𝐵)}
63, 4, 53eqtr4i 2269 1 (𝐴 × {𝐵}) = (𝑥𝐴𝐵)
Colors of variables: wff set class
Syntax hints:  wa 104   = wceq 1402  wcel 2209  {csn 3708  {copab 4189  cmpt 4190   × cxp 4770
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220
This theorem depends on definitions:  df-bi 117  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-v 2823  df-sn 3714  df-opab 4191  df-mpt 4192  df-xp 4778
This theorem is referenced by:  fconst  5586  fcoconst  5873  fmptsn  5898  fconstmpo  6177  ofc12  6320  caofinvl  6322  xpexgALT  6360  inftonninf  10862  fser0const  10955  prod1dc  12336  gsumconstcmn  14149  pws0g  14196  rrgsupp  14557  psrlinv  15058  psr1clfi  15062  mpl0fi  15076  cnmptc  15366  dvexp  15795  dvexp2  15796  dvmptidcn  15798  dvmptccn  15799  dvmptid  15800  dvmptc  15801  dvmptfsum  15809  dvef  15811  elply2  15819  plyconst  15829  plycolemc  15842  nninfall  17026  nninfsellemeqinf  17033  nninfnfiinf  17040  exmidsbthrlem  17041
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