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Theorem sbequ 1886
Description: An equality theorem for substitution. Used in proof of Theorem 9.7 in [Megill] p. 449 (p. 16 of the preprint). (Contributed by NM, 5-Aug-1993.)
Assertion
Ref Expression
sbequ (𝑥 = 𝑦 → ([𝑥 / 𝑧]𝜑 ↔ [𝑦 / 𝑧]𝜑))

Proof of Theorem sbequ
StepHypRef Expression
1 sbequi 1885 . 2 (𝑥 = 𝑦 → ([𝑥 / 𝑧]𝜑 → [𝑦 / 𝑧]𝜑))
2 sbequi 1885 . . 3 (𝑦 = 𝑥 → ([𝑦 / 𝑧]𝜑 → [𝑥 / 𝑧]𝜑))
32equcoms 1754 . 2 (𝑥 = 𝑦 → ([𝑦 / 𝑧]𝜑 → [𝑥 / 𝑧]𝜑))
41, 3impbid 129 1 (𝑥 = 𝑦 → ([𝑥 / 𝑧]𝜑 ↔ [𝑦 / 𝑧]𝜑))
Colors of variables: wff set class
Syntax hints:  wi 4  wb 105  [wsb 1808
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 714  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-10 1551  ax-11 1552  ax-i12 1553  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581
This theorem depends on definitions:  df-bi 117  df-nf 1507  df-sb 1809
This theorem is referenced by:  drsb2  1887  sbco2vlem  1995  sbco2v  1999  sbco2yz  2014  sbcocom  2021  sb10f  2046  hbsb4  2063  nfsb4or  2072  sb8eu  2090  sb8euh  2100  cbvab  2353  cbvralf  2756  cbvrexf  2757  cbvreu  2763  cbvralsv  2781  cbvrexsv  2782  cbvrab  2797  cbvreucsf  3189  cbvrabcsf  3190  sbss  3599  disjiun  4077  cbvopab1  4156  cbvmpt  4178  tfis  4674  findes  4694  cbviota  5282  sb8iota  5285  cbvriota  5965  uzind4s  9781  bezoutlemmain  12514  cbvrald  16110  setindft  16286
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