Users' Mathboxes Mathbox for Peter Mazsa < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  n0el3 Structured version   Visualization version   GIF version

Theorem n0el3 36690
Description: Two ways of expressing that the empty set is not an element of a class. (Contributed by Peter Mazsa, 27-May-2021.)
Assertion
Ref Expression
n0el3 (¬ ∅ ∈ 𝐴 ↔ (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴)

Proof of Theorem n0el3
StepHypRef Expression
1 n0el2 36395 . . . . 5 (¬ ∅ ∈ 𝐴 ↔ dom ( E ↾ 𝐴) = 𝐴)
21biimpi 215 . . . 4 (¬ ∅ ∈ 𝐴 → dom ( E ↾ 𝐴) = 𝐴)
32qseq1d 36352 . . 3 (¬ ∅ ∈ 𝐴 → (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = (𝐴 / ( E ↾ 𝐴)))
4 qsresid 36387 . . . 4 (𝐴 / ( E ↾ 𝐴)) = (𝐴 / E )
5 qsid 8530 . . . 4 (𝐴 / E ) = 𝐴
64, 5eqtri 2766 . . 3 (𝐴 / ( E ↾ 𝐴)) = 𝐴
73, 6eqtrdi 2795 . 2 (¬ ∅ ∈ 𝐴 → (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴)
8 n0eldmqseq 36689 . 2 ((dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴 → ¬ ∅ ∈ 𝐴)
97, 8impbii 208 1 (¬ ∅ ∈ 𝐴 ↔ (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 205   = wceq 1539  wcel 2108  c0 4253   E cep 5485  ccnv 5579  dom cdm 5580  cres 5582   / cqs 8455
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1799  ax-4 1813  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2110  ax-9 2118  ax-10 2139  ax-11 2156  ax-12 2173  ax-ext 2709  ax-sep 5218  ax-nul 5225  ax-pr 5347
This theorem depends on definitions:  df-bi 206  df-an 396  df-or 844  df-3an 1087  df-tru 1542  df-fal 1552  df-ex 1784  df-nf 1788  df-sb 2069  df-mo 2540  df-eu 2569  df-clab 2716  df-cleq 2730  df-clel 2817  df-nfc 2888  df-ne 2943  df-ral 3068  df-rex 3069  df-rab 3072  df-v 3424  df-dif 3886  df-un 3888  df-in 3890  df-ss 3900  df-nul 4254  df-if 4457  df-sn 4559  df-pr 4561  df-op 4565  df-br 5071  df-opab 5133  df-eprel 5486  df-xp 5586  df-rel 5587  df-cnv 5588  df-dm 5590  df-rn 5591  df-res 5592  df-ima 5593  df-ec 8458  df-qs 8462
This theorem is referenced by:  cnvepresdmqss  36691  cnvepresdmqs  36692
  Copyright terms: Public domain W3C validator