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Theorem eldisjn0elb 38710
Description: Two forms of disjoint elements when the empty set is not an element of the class. (Contributed by Peter Mazsa, 31-Dec-2024.)
Assertion
Ref Expression
eldisjn0elb (( ElDisj 𝐴 ∧ ¬ ∅ ∈ 𝐴) ↔ ( Disj ( E ↾ 𝐴) ∧ (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴))

Proof of Theorem eldisjn0elb
StepHypRef Expression
1 df-eldisj 38672 . 2 ( ElDisj 𝐴 ↔ Disj ( E ↾ 𝐴))
2 n0el3 38616 . 2 (¬ ∅ ∈ 𝐴 ↔ (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴)
31, 2anbi12i 628 1 (( ElDisj 𝐴 ∧ ¬ ∅ ∈ 𝐴) ↔ ( Disj ( E ↾ 𝐴) ∧ (dom ( E ↾ 𝐴) / ( E ↾ 𝐴)) = 𝐴))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wa 395   = wceq 1540  wcel 2109  c0 4292   E cep 5530  ccnv 5630  dom cdm 5631  cres 5633   / cqs 8647   Disj wdisjALTV 38176   ElDisj weldisj 38178
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-10 2142  ax-11 2158  ax-12 2178  ax-ext 2701  ax-sep 5246  ax-nul 5256  ax-pr 5382
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-nf 1784  df-sb 2066  df-mo 2533  df-eu 2562  df-clab 2708  df-cleq 2721  df-clel 2803  df-nfc 2878  df-ne 2926  df-ral 3045  df-rex 3054  df-rab 3403  df-v 3446  df-dif 3914  df-un 3916  df-in 3918  df-ss 3928  df-nul 4293  df-if 4485  df-sn 4586  df-pr 4588  df-op 4592  df-br 5103  df-opab 5165  df-eprel 5531  df-xp 5637  df-rel 5638  df-cnv 5639  df-dm 5641  df-rn 5642  df-res 5643  df-ima 5644  df-ec 8650  df-qs 8654  df-eldisj 38672
This theorem is referenced by:  mpet3  38801  cpet2  38802
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