MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  xp01disjl Structured version   Visualization version   GIF version

Theorem xp01disjl 8513
Description: Cartesian products with the singletons of ordinals 0 and 1 are disjoint. (Contributed by Jim Kingdon, 11-Jul-2023.)
Assertion
Ref Expression
xp01disjl (({∅} × 𝐴) ∩ ({1o} × 𝐶)) = ∅

Proof of Theorem xp01disjl
StepHypRef Expression
1 1n0 8509 . . 3 1o ≠ ∅
21necomi 2984 . 2 ∅ ≠ 1o
3 disjsn2 4718 . 2 (∅ ≠ 1o → ({∅} ∩ {1o}) = ∅)
4 xpdisj1 6167 . 2 (({∅} ∩ {1o}) = ∅ → (({∅} × 𝐴) ∩ ({1o} × 𝐶)) = ∅)
52, 3, 4mp2b 10 1 (({∅} × 𝐴) ∩ ({1o} × 𝐶)) = ∅
Colors of variables: wff setvar class
Syntax hints:   = wceq 1533  wne 2929  cin 3943  c0 4322  {csn 4630   × cxp 5676  1oc1o 8480
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1789  ax-4 1803  ax-5 1905  ax-6 1963  ax-7 2003  ax-8 2100  ax-9 2108  ax-ext 2696  ax-sep 5300  ax-nul 5307  ax-pr 5429
This theorem depends on definitions:  df-bi 206  df-an 395  df-or 846  df-3an 1086  df-tru 1536  df-fal 1546  df-ex 1774  df-sb 2060  df-clab 2703  df-cleq 2717  df-clel 2802  df-ne 2930  df-ral 3051  df-rex 3060  df-rab 3419  df-v 3463  df-dif 3947  df-un 3949  df-in 3951  df-ss 3961  df-nul 4323  df-if 4531  df-sn 4631  df-pr 4633  df-op 4637  df-opab 5212  df-xp 5684  df-rel 5685  df-suc 6377  df-1o 8487
This theorem is referenced by:  undjudom  10192  endjudisj  10193  djuen  10194  dju1dif  10197  dju1p1e2  10198  djucomen  10202  djuassen  10203  xpdjuen  10204  mapdjuen  10205  djudom1  10207  infdju1  10214  bj-2upln1upl  36634
  Copyright terms: Public domain W3C validator