Theorem ordgt0ge1 8402

Description: Two ways to express that an ordinal class is positive. (Contributed by NM, 21-Dec-2004.)

Assertion

Ref	Expression
ordgt0ge1	⊢ (Ord 𝐴 → (∅ ∈ 𝐴 ↔ 1o ⊆ 𝐴))

Proof of Theorem ordgt0ge1

Step	Hyp	Ref	Expression
1		0elon 6356	. . 3 ⊢ ∅ ∈ On
2		ordelsuc 7744	. . 3 ⊢ ((∅ ∈ On ∧ Ord 𝐴) → (∅ ∈ 𝐴 ↔ suc ∅ ⊆ 𝐴))
3	1, 2	mpan 690	. 2 ⊢ (Ord 𝐴 → (∅ ∈ 𝐴 ↔ suc ∅ ⊆ 𝐴))
4		df-1o 8379	. . 3 ⊢ 1o = suc ∅
5	4	sseq1i 3960	. 2 ⊢ (1o ⊆ 𝐴 ↔ suc ∅ ⊆ 𝐴)
6	3, 5	bitr4di 289	1 ⊢ (Ord 𝐴 → (∅ ∈ 𝐴 ↔ 1o ⊆ 𝐴))

Syntax hints:   → wi 4   ↔ wb 206   ∈ wcel 2109   ⊆ wss 3899  ∅c0 4280  Ord word 6300  Oncon0 6301  suc csuc 6303  1_oc1o 8372

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2701  ax-sep 5231  ax-nul 5241  ax-pr 5367

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3or 1087  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2066  df-clab 2708  df-cleq 2721  df-clel 2803  df-ne 2926  df-ral 3045  df-rex 3054  df-rab 3393  df-v 3435  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-pss 3919  df-nul 4281  df-if 4473  df-pw 4549  df-sn 4574  df-pr 4576  df-op 4580  df-uni 4857  df-br 5089  df-opab 5151  df-tr 5196  df-eprel 5513  df-po 5521  df-so 5522  df-fr 5566  df-we 5568  df-ord 6304  df-on 6305  df-suc 6307  df-1o 8379

This theorem is referenced by:  ordge1n0  8403  oe0m1  8430  omword1  8482  omword2  8483  omlimcl  8487  oen0  8495  oewordi  8500  oe0rif  43275