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Theorem ordgt0ge1 8372
Description: Two ways to express that an ordinal class is positive. (Contributed by NM, 21-Dec-2004.)
Assertion
Ref Expression
ordgt0ge1 (Ord 𝐴 → (∅ ∈ 𝐴 ↔ 1o𝐴))

Proof of Theorem ordgt0ge1
StepHypRef Expression
1 0elon 6341 . . 3 ∅ ∈ On
2 ordelsuc 7711 . . 3 ((∅ ∈ On ∧ Ord 𝐴) → (∅ ∈ 𝐴 ↔ suc ∅ ⊆ 𝐴))
31, 2mpan 687 . 2 (Ord 𝐴 → (∅ ∈ 𝐴 ↔ suc ∅ ⊆ 𝐴))
4 df-1o 8345 . . 3 1o = suc ∅
54sseq1i 3958 . 2 (1o𝐴 ↔ suc ∅ ⊆ 𝐴)
63, 5bitr4di 288 1 (Ord 𝐴 → (∅ ∈ 𝐴 ↔ 1o𝐴))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 205  wcel 2105  wss 3896  c0 4266  Ord word 6287  Oncon0 6288  suc csuc 6290  1oc1o 8338
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1912  ax-6 1970  ax-7 2010  ax-8 2107  ax-9 2115  ax-ext 2707  ax-sep 5237  ax-nul 5244  ax-pr 5366
This theorem depends on definitions:  df-bi 206  df-an 397  df-or 845  df-3or 1087  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1781  df-sb 2067  df-clab 2714  df-cleq 2728  df-clel 2814  df-ne 2941  df-ral 3062  df-rex 3071  df-rab 3404  df-v 3442  df-dif 3899  df-un 3901  df-in 3903  df-ss 3913  df-pss 3915  df-nul 4267  df-if 4471  df-pw 4546  df-sn 4571  df-pr 4573  df-op 4577  df-uni 4850  df-br 5087  df-opab 5149  df-tr 5204  df-eprel 5512  df-po 5520  df-so 5521  df-fr 5562  df-we 5564  df-ord 6291  df-on 6292  df-suc 6294  df-1o 8345
This theorem is referenced by:  ordge1n0  8373  oe0m1  8400  omword1  8453  omword2  8454  omlimcl  8458  oen0  8466  oewordi  8471
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