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| Mirrors > Home > ILE Home > Th. List > mpjao3dan | Unicode version | ||
| Description: Eliminate a 3-way disjunction in a deduction. (Contributed by Thierry Arnoux, 13-Apr-2018.) |
| Ref | Expression |
|---|---|
| mpjao3dan.1 |
|
| mpjao3dan.2 |
|
| mpjao3dan.3 |
|
| mpjao3dan.4 |
|
| Ref | Expression |
|---|---|
| mpjao3dan |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpjao3dan.1 |
. . 3
| |
| 2 | mpjao3dan.2 |
. . 3
| |
| 3 | 1, 2 | jaodan 799 |
. 2
|
| 4 | mpjao3dan.3 |
. 2
| |
| 5 | mpjao3dan.4 |
. . 3
| |
| 6 | df-3or 982 |
. . 3
| |
| 7 | 5, 6 | sylib 122 |
. 2
|
| 8 | 3, 4, 7 | mpjaodan 800 |
1
|
| Colors of variables: wff set class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 711 |
| This theorem depends on definitions: df-bi 117 df-3or 982 |
| This theorem is referenced by: wetriext 4625 nntri3 6583 nntri2or2 6584 nntr2 6589 tridc 6996 nnnninfeq 7230 exmidontriimlem2 7334 caucvgprlemnkj 7779 caucvgprlemnbj 7780 caucvgprprlemnkj 7805 caucvgprprlemnbj 7806 caucvgsr 7915 npnflt 9937 nmnfgt 9940 xleadd1a 9995 xltadd1 9998 xlt2add 10002 xsubge0 10003 xleaddadd 10009 addmodlteq 10543 iseqf1olemkle 10642 hashfiv01gt1 10927 iswrdiz 11001 xrmaxltsup 11569 xrmaxadd 11572 xrbdtri 11587 cvgratz 11843 zdvdsdc 12123 divalglemeunn 12232 divalglemex 12233 divalglemeuneg 12234 divalg 12235 znege1 12500 ennnfonelemk 12771 isxmet2d 14820 trilpolemres 15981 trirec0 15983 |
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