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| Mirrors > Home > ILE Home > Th. List > mpjao3dan | Unicode version | ||
| Description: Eliminate a 3-way disjunction in a deduction. (Contributed by Thierry Arnoux, 13-Apr-2018.) |
| Ref | Expression |
|---|---|
| mpjao3dan.1 |
|
| mpjao3dan.2 |
|
| mpjao3dan.3 |
|
| mpjao3dan.4 |
|
| Ref | Expression |
|---|---|
| mpjao3dan |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpjao3dan.1 |
. . 3
| |
| 2 | mpjao3dan.2 |
. . 3
| |
| 3 | 1, 2 | jaodan 804 |
. 2
|
| 4 | mpjao3dan.3 |
. 2
| |
| 5 | mpjao3dan.4 |
. . 3
| |
| 6 | df-3or 1005 |
. . 3
| |
| 7 | 5, 6 | sylib 122 |
. 2
|
| 8 | 3, 4, 7 | mpjaodan 805 |
1
|
| Colors of variables: wff set class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 716 |
| This theorem depends on definitions: df-bi 117 df-3or 1005 |
| This theorem is referenced by: wetriext 4675 nntri3 6664 nntri2or2 6665 nntr2 6670 tridc 7088 nnnninfeq 7326 exmidontriimlem2 7436 caucvgprlemnkj 7885 caucvgprlemnbj 7886 caucvgprprlemnkj 7911 caucvgprprlemnbj 7912 caucvgsr 8021 npnflt 10049 nmnfgt 10052 xleadd1a 10107 xltadd1 10110 xlt2add 10114 xsubge0 10115 xleaddadd 10121 addmodlteq 10659 iseqf1olemkle 10758 hashfiv01gt1 11043 iswrdiz 11119 xrmaxltsup 11818 xrmaxadd 11821 xrbdtri 11836 cvgratz 12092 zdvdsdc 12372 divalglemeunn 12481 divalglemex 12482 divalglemeuneg 12483 divalg 12484 znege1 12749 ennnfonelemk 13020 isxmet2d 15071 trilpolemres 16646 trirec0 16648 |
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