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| Mirrors > Home > ILE Home > Th. List > mpjao3dan | Unicode version | ||
| Description: Eliminate a 3-way disjunction in a deduction. (Contributed by Thierry Arnoux, 13-Apr-2018.) |
| Ref | Expression |
|---|---|
| mpjao3dan.1 |
|
| mpjao3dan.2 |
|
| mpjao3dan.3 |
|
| mpjao3dan.4 |
|
| Ref | Expression |
|---|---|
| mpjao3dan |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpjao3dan.1 |
. . 3
| |
| 2 | mpjao3dan.2 |
. . 3
| |
| 3 | 1, 2 | jaodan 802 |
. 2
|
| 4 | mpjao3dan.3 |
. 2
| |
| 5 | mpjao3dan.4 |
. . 3
| |
| 6 | df-3or 1003 |
. . 3
| |
| 7 | 5, 6 | sylib 122 |
. 2
|
| 8 | 3, 4, 7 | mpjaodan 803 |
1
|
| Colors of variables: wff set class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 714 |
| This theorem depends on definitions: df-bi 117 df-3or 1003 |
| This theorem is referenced by: wetriext 4673 nntri3 6660 nntri2or2 6661 nntr2 6666 tridc 7082 nnnninfeq 7318 exmidontriimlem2 7427 caucvgprlemnkj 7876 caucvgprlemnbj 7877 caucvgprprlemnkj 7902 caucvgprprlemnbj 7903 caucvgsr 8012 npnflt 10040 nmnfgt 10043 xleadd1a 10098 xltadd1 10101 xlt2add 10105 xsubge0 10106 xleaddadd 10112 addmodlteq 10650 iseqf1olemkle 10749 hashfiv01gt1 11034 iswrdiz 11110 xrmaxltsup 11809 xrmaxadd 11812 xrbdtri 11827 cvgratz 12083 zdvdsdc 12363 divalglemeunn 12472 divalglemex 12473 divalglemeuneg 12474 divalg 12475 znege1 12740 ennnfonelemk 13011 isxmet2d 15062 trilpolemres 16582 trirec0 16584 |
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