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| Mirrors > Home > ILE Home > Th. List > mpjao3dan | Unicode version | ||
| Description: Eliminate a 3-way disjunction in a deduction. (Contributed by Thierry Arnoux, 13-Apr-2018.) |
| Ref | Expression |
|---|---|
| mpjao3dan.1 |
|
| mpjao3dan.2 |
|
| mpjao3dan.3 |
|
| mpjao3dan.4 |
|
| Ref | Expression |
|---|---|
| mpjao3dan |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpjao3dan.1 |
. . 3
| |
| 2 | mpjao3dan.2 |
. . 3
| |
| 3 | 1, 2 | jaodan 809 |
. 2
|
| 4 | mpjao3dan.3 |
. 2
| |
| 5 | mpjao3dan.4 |
. . 3
| |
| 6 | df-3or 1010 |
. . 3
| |
| 7 | 5, 6 | sylib 122 |
. 2
|
| 8 | 3, 4, 7 | mpjaodan 810 |
1
|
| Colors of variables: wff set class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 721 |
| This theorem depends on definitions: df-bi 117 df-3or 1010 |
| This theorem is referenced by: wetriext 4719 nntri3 6760 nntri2or2 6761 nntr2 6766 tridc 7194 nnnninfeq 7458 exmidontriimlem2 7568 caucvgprlemnkj 8023 caucvgprlemnbj 8024 caucvgprprlemnkj 8049 caucvgprprlemnbj 8050 caucvgsr 8159 npnflt 10196 nmnfgt 10199 xleadd1a 10254 xltadd1 10257 xlt2add 10261 xsubge0 10262 xleaddadd 10268 addmodlteq 10813 iseqf1olemkle 10912 hashfiv01gt1 11199 iswrdiz 11289 xrmaxltsup 12002 xrmaxadd 12005 xrbdtri 12020 cvgratz 12277 zdvdsdc 12557 divalglemeunn 12666 divalglemex 12667 divalglemeuneg 12668 divalg 12669 znege1 12934 ennnfonelemk 13269 isxmet2d 15372 trilpolemres 16996 trirec0 16998 |
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