Theorem spcgv 2912

Description: Rule of specialization, using implicit substitution. Compare Theorem 7.3 of [Quine] p. 44. (Contributed by NM, 22-Jun-1994.)

Hypothesis

Ref	Expression
spcgv.1	|- ( x = A -> ( ph <-> ps ) )

Assertion

Ref	Expression
spcgv	|- ( A e. V -> ( A. x ph -> ps ) )

Distinct variable groups:   ps, x   x, A

Allowed substitution hints:   ph( x)   V( x)

Proof of Theorem spcgv

Step	Hyp	Ref	Expression
1		nfcv 2392	. 2 |- F/_ x A
2		nfv 1581	. 2 |- F/ x ps
3		spcgv.1	. 2 |- ( x = A -> ( ph <-> ps ) )
4	1, 2, 3	spcgf 2907	1 |- ( A e. V -> ( A. x ph -> ps ) )

This proof depends on syntax axioms:   -> wi 4   <-> wb 105   A.wal 1400   = wceq 1402   e. wcel 2209

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220

This proof depends on definitions:  df-bi 117  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-v 2823

This theorem is used by:  spcv  2919  mob2  3006  intss1  3985  dfiin2g  4045  exmidsssnc  4340  exmid1stab  4345  frirrg  4495  frind  4497  alxfr  4607  elirr  4688  en2lp  4701  tfisi  4734  mptfvex  5791  tfrcl  6635  rdgisucinc  6656  frecabex  6669  fisseneq  7242  mkvprop  7498  exmidfodomrlemr  7554  exmidfodomrlemrALT  7555  acfun  7563  exmidmotap  7627  ccfunen  7630  zfz1isolem1  11292  zfz1iso  11293  uniopn  15102  pw1nct  17033  sbthom  17071