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Theorem disjxrn 36010
Description: Two ways of saying that a range Cartesian product is disjoint. (Contributed by Peter Mazsa, 17-Jun-2020.) (Revised by Peter Mazsa, 21-Sep-2021.)
Assertion
Ref Expression
disjxrn ( Disj (𝑅𝑆) ↔ ( ≀ 𝑅 ∩ ≀ 𝑆) ⊆ I )

Proof of Theorem disjxrn
StepHypRef Expression
1 xrnrel 35658 . . 3 Rel (𝑅𝑆)
2 dfdisjALTV2 35980 . . 3 ( Disj (𝑅𝑆) ↔ ( ≀ (𝑅𝑆) ⊆ I ∧ Rel (𝑅𝑆)))
31, 2mpbiran2 708 . 2 ( Disj (𝑅𝑆) ↔ ≀ (𝑅𝑆) ⊆ I )
4 1cosscnvxrn 35748 . . 3 (𝑅𝑆) = ( ≀ 𝑅 ∩ ≀ 𝑆)
54sseq1i 3988 . 2 ( ≀ (𝑅𝑆) ⊆ I ↔ ( ≀ 𝑅 ∩ ≀ 𝑆) ⊆ I )
63, 5bitri 277 1 ( Disj (𝑅𝑆) ↔ ( ≀ 𝑅 ∩ ≀ 𝑆) ⊆ I )
Colors of variables: wff setvar class
Syntax hints:  wb 208  cin 3928  wss 3929   I cid 5452  ccnv 5547  Rel wrel 5553  cxrn 35485  ccoss 35486   Disj wdisjALTV 35520
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1969  ax-7 2014  ax-8 2115  ax-9 2123  ax-10 2144  ax-11 2160  ax-12 2176  ax-ext 2792  ax-sep 5196  ax-nul 5203  ax-pow 5259  ax-pr 5323  ax-un 7454
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-3an 1084  df-tru 1539  df-ex 1780  df-nf 1784  df-sb 2069  df-mo 2621  df-eu 2653  df-clab 2799  df-cleq 2813  df-clel 2892  df-nfc 2962  df-ne 3016  df-ral 3142  df-rex 3143  df-rab 3146  df-v 3493  df-sbc 3769  df-dif 3932  df-un 3934  df-in 3936  df-ss 3945  df-nul 4285  df-if 4461  df-sn 4561  df-pr 4563  df-op 4567  df-uni 4832  df-br 5060  df-opab 5122  df-mpt 5140  df-id 5453  df-xp 5554  df-rel 5555  df-cnv 5556  df-co 5557  df-dm 5558  df-rn 5559  df-res 5560  df-ima 5561  df-iota 6307  df-fun 6350  df-fn 6351  df-f 6352  df-fo 6354  df-fv 6356  df-1st 7682  df-2nd 7683  df-ec 8284  df-xrn 35656  df-coss 35692  df-cnvrefrel 35798  df-disjALTV 35971
This theorem is referenced by:  disjorimxrn  36011
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