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Theorem partsuc2 39572
Description: Property of the partition. (Contributed by Peter Mazsa, 24-Jul-2024.)
Assertion
Ref Expression
partsuc2 (((𝑅 ↾ (𝐴 ∪ {𝐴})) ∖ (𝑅 ↾ {𝐴})) Part ((𝐴 ∪ {𝐴}) ∖ {𝐴}) ↔ (𝑅𝐴) Part 𝐴)

Proof of Theorem partsuc2
StepHypRef Expression
1 ressucdifsn2 39177 . 2 ((𝑅 ↾ (𝐴 ∪ {𝐴})) ∖ (𝑅 ↾ {𝐴})) = (𝑅𝐴)
2 sucdifsn2 39175 . 2 ((𝐴 ∪ {𝐴}) ∖ {𝐴}) = 𝐴
3 parteq12 39569 . 2 ((((𝑅 ↾ (𝐴 ∪ {𝐴})) ∖ (𝑅 ↾ {𝐴})) = (𝑅𝐴) ∧ ((𝐴 ∪ {𝐴}) ∖ {𝐴}) = 𝐴) → (((𝑅 ↾ (𝐴 ∪ {𝐴})) ∖ (𝑅 ↾ {𝐴})) Part ((𝐴 ∪ {𝐴}) ∖ {𝐴}) ↔ (𝑅𝐴) Part 𝐴))
41, 2, 3mp2an 705 1 (((𝑅 ↾ (𝐴 ∪ {𝐴})) ∖ (𝑅 ↾ {𝐴})) Part ((𝐴 ∪ {𝐴}) ∖ {𝐴}) ↔ (𝑅𝐴) Part 𝐴)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209   = wceq 1570  cdif 3905  cun 3906  {csn 4594  cres 5668   Part wpart 38914
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-11 2195  ax-ext 2738  ax-sep 5262  ax-pr 5409  ax-reg 9564
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2745  df-cleq 2758  df-clel 2841  df-ral 3083  df-rex 3093  df-rab 3420  df-v 3460  df-dif 3911  df-un 3913  df-in 3915  df-ss 3925  df-nul 4290  df-if 4493  df-sn 4595  df-pr 4597  df-op 4601  df-br 5115  df-opab 5179  df-id 5561  df-xp 5672  df-rel 5673  df-cnv 5674  df-co 5675  df-dm 5676  df-rn 5677  df-res 5678  df-ima 5679  df-ec 8705  df-qs 8709  df-coss 39191  df-cnvrefrel 39297  df-dmqs 39413  df-funALTV 39457  df-disjALTV 39480  df-part 39559
This theorem is used by: (None)
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